C语言大一师妹求指导TT 大一，C语言，求助。。
C\u8bed\u8a00\u9898\u6c42\u89e3\u554a\uff0c\uff0c\uff0c\u5b8c\u5168\u6ca1\u601d\u8defTT\u3002\u3002\u8fd9\u9898\u660e\u663e\u662f\u57fa\u7840\u8d2a\u5fc3\u3002\u3002
\u3002\u3002\u4f60\u5b66\u4e86\u51e0\u5e74\u7684\u7f16\u7a0b\u3002\u3002
\u4ee5\u4e0b\u7ed9\u51fa\u601d\u8def\uff1a
\u56e0\u4e3a\u4ed6\u53ef\u9009\u62e9\u7684\u662f\u8fde\u7eed\u7684\uff0c\u6240\u4ee5\u53ef\u4ee5\u5f97\u5230\u8d2a\u5fc3\u7b56\u7565\uff1af[i]=max(f[i-1],0)+a[i]\uff0c\u5176\u4e2df[i]\u8868\u793a\u4ece\u7b2c1\u9053\u83dc\u5230\u7b2ci\u9053\u83dc\u6240\u83b7\u5f97\u7684\u6700\u5927\u6109\u5feb\u5ea6\u3002\u6ce8\u610f\uff1a\u522b\u4ee5\u4e3a\u8fd9\u662fDP\uff0c\u5b83\u5176\u5b9e\u5c31\u662f\u8d2a\u5fc3\uff01\u56e0\u4e3a\u8fd9\u9898\u7684\u666e\u904d\u65e0\u540e\u6548\u6027\uff0c\u6240\u4ee5\u8d2a\u5fc3\u4e5f\u53ef\u4ee5\u5bf9\u3002
\u5982\u679c\u60f3\u8981\u5177\u4f53\u7a0b\u5e8f\uff0c\u8bf7\u7ee7\u7eed\u8ffd\u95ee\u3002
#include void main(){int i,a,b,k=1;while(1){scanf("%d%d",&a,&b);for(i=1;i<=b;i++)k=(k*a)%1000;printf("%03d\n",k);k=1;}}
#include "string.h"
#include "stdio.h"
int replace(char *source,char *s1,char *s2,int flag)
{int i,k=strlen(source),p=0,j;
char *pStar,strx[50],n=0;
int l=strlen(s1);
if(flag==0)
{
for(i = 0; i <strlen(source); i++)
{ for(j = 0;j<strlen(s1); j++)
{ if((*(source + i+j) == *(s1+j) ) ||*(source + i+j) - *(s1+j) == 32|| *(s1+j) - *(source + i+j ) == 32) p++;
else p=0;
}
if(p==strlen(s1))
for(j=i;j<i+p;j++)
if(source[j]<='Z'&&source[j]>='A')
source[j]=source[j]+32;
}
for(i = 0;s1[i]!='\0'; i++)
if(s1[i]<='Z'&&s1[i]>='A') s1[i]=s1[i]+32;
}
while(pStar=strstr(source,s1))
{
strcpy(strx,pStar+l);
*pStar=NULL;
strcat(strcpy(pStar,s2),strx);
n++;
}
return n;
}
void main()
{ char source[100]="I iNt yy INT YY int yY intyy ",s1[100]="iNt",*s2="FLOAT";
int i=replace(source,s1,s2,0);
printf("%s : %d\n",source,i);
}
首先你的 拼写有误啊，"countinue"-->“ continue”
已经测试通过了。。。！
#include <string.h>
#include "stdio.h"
int replace(char *source,char *s1,char *s2,int flag)
{
int i = 0,j = 0,n = 0;
char dest[200] = {0};
int s2Len = strlen(s2);
for( i = 0; i < strlen(source); i++)
{
if(flag == 1)
{
if(*(source + i) == *s1)
{
int s1Len = strlen(s1);
int sameFlag = 1;
for(j = 1; j < s1Len; j++)
{
// if(*(source + i + j) == *(s1 + j)) //这里的代码是， 只要在source中有和s1相同的字符就替换，而不是
// {//将s1看成一个字符串整体!
// *(source + i + j) = *(s2 + j);
// n++;
// }
if(*(source + i + j) == *(s1 + j))
{
sameFlag++;
}
}
if (sameFlag == s1Len) //source和s1中的所有字符均匹配。
{
for (int index = s2Len-1; index >=0; index--)
{
*(dest+strlen(dest)+index) = *(s2 + index);
}
n++;
i += s1Len-1;
}
}else
{
int dest_index = strlen(dest);
*(dest+dest_index) = *(source + i);
}
}else if(flag == 0)
{
if(*(source + i) == *s1 ||
(*(source + i) - *s1)==32||
(*(source + i) - *s1)==-32)
{
int s1Len = strlen(s1);
int sameFlag = 1;
for(j = 1; j < s1Len; j++)
{
if(*(source + i + j) == *(s1 + j))
{
sameFlag++;
}
}
if (sameFlag == s1Len) //source和s1中的所有字符均匹配。
{
for (int index = s2Len-1; index >=0; index--)
{
*(dest+strlen(dest)+index) = *(s2 + index);
}
n++;
i += s1Len-1;
}
}else
{
int dest_index = strlen(dest);
*(dest+dest_index) = *(source + i);
}
}
}
printf("替换的数量为: %d\n替换后的字符串为:%s\n ",n, dest);
return n;
}
int main()
{
char source[] = "abcdefabcd";
char s1[] = "Ab";
char s2[] = "123";
replace(source, s1,s2,0);
return 0;
}
用手机不好说 不过有两点可以改一下
把continue改成break
如果我没理解错题意的话。。
还有忽略大小写的判断条件可以用abs()函数
编译你的continue写错了，但是根据你的题目貌似你的逻辑不对啊
你的continue 写错了 =。=
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