大一高数,求平面图形的面积 急)高等数学:计算下列曲线围成的平面图形的面积,求详细过程?
\u9ad8\u7b49\u6570\u5b66\uff0c\u5b9a\u79ef\u5206\u5e94\u7528\uff0c\u6c42\u5e73\u9762\u56fe\u5f62\u7684\u9762\u79ef
\u8be6\u7ec6\u8fc7\u7a0b\u5982\u56fe\uff0c\u5e0c\u671b\u5199\u7684\u5f88\u6e05\u695a\u89e3\u51b3\u4f60\u5fc3\u4e2d\u7684\u95ee\u9898
∴所围成图形面积=∫(0,1)(e-e^x)dx ( ∫(0,1)为函数在[0,1]上的积分,下同)
=∫(0,1)edx-∫(0,1)e^xdx
=exI(0,1)-e^xI(0,1) (xI(0,1)为将x为(0,1)的值)
=e-(e-1)
=1
1
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