水平面上A,B两个物体的质量分别为m1和m2,与水平面间的动摩擦因数均相同,A,B分别在水平力F1和F2的作用下,

\u4e24\u4e2a\u7269\u4f53\u7684\u8d28\u91cf\u5206\u522b\u4e3am1\u548cm2\uff0c\u4e14m1=4m2\uff0c\u5f53\u5b83\u4eec\u4ee5\u76f8\u540c\u7684\u52a8\u80fd\u5728\u52a8\u6469\u64e6\u56e0\u6570\u76f8\u540c\u7684\u6c34\u5e73\u9762\u4e0a\u8fd0\u884c\u65f6\uff0c\u5b83\u4eec\u7684\u6ed1

\u56e0\u4e3a\u662f\u4e24\u7269\u4f53\u53ea\u53d7\u91cd\u529b\u548c\u6469\u64e6\u529b\uff0c\u6469\u64e6\u529b\u548c\u91cd\u529b\u6709\u5173\uff0c\u53ef\u4ee5\u5f97\u51fa\u6469\u64e6\u529bF\uff1d\u03bcM\u3002a=F/M
\u6240\u4ee5\u53ef\u77e5a\u4e0e\u7269\u4f53\u8d28\u91cf\u65e0\u5173\u3002a=\u03bc\u3002\u4ee5\u76f8\u540c\u52a8\u91cf\u53731/2(m1)(v1)\u5e73\u65b9\uff1d1/2(m2)(v2)\u5e73\u65b9
\u6240\u4ee5\u53ef\u5f97\u51fa\uff08v1)\uff1a(v2)\uff1d1\uff1a2\uff0c\u6839\u636ev=v0+at\u5f97\u51fa(t1)\uff1a(t2)\uff1d1\uff1a2
\u53c8\u56e0\u4e3as=(v0)t+1/2at\u5e73\u65b9\u3002\u6240\u4ee5\u5f97\u51fa(s1)\uff1a(s2)\uff1d1\uff1a4
\u7ed3\u679c\u9009\u62e9D

C \u7531\u529f\u7684\u5b9a\u4e49\u5f0f\uff1a W = Fl cos \u03b8 \u53ef\u77e5\uff0c\u4e24\u79cd\u60c5\u51b5\u4e0b\u529b\u76f8\u540c\uff0c\u4f4d\u79fb\u76f8\u540c\uff0c\u529b\u548c\u4f4d\u79fb\u7684\u5939\u89d2\u4e5f\u76f8\u540c\uff0c\u6240\u4ee5 W 1 = W 2 \uff0cC\u6b63\u786e\u3002

设A B物体向右匀加速运动
A物体受B物体的支持力N和摩擦力f
N=m1g
F1-f=m1a
AB做为一个整体:
F1+F2-u(m1+m2)g=(m1+m2)a
解出: f=F1-m1a=(m2F1-m1F2)/(m1+m2)+um1g

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