C语言:将一个十进制的正整数转换为二进制数并输出结果。 急求用c语言:从键盘输入一个十进制正整数,转换成二进制输出

C\u8bed\u8a00\uff1a\u5c06\u4e00\u4e2a\u5341\u8fdb\u5236\u7684\u6b63\u6574\u6570\u8f6c\u6362\u4e3a\u4e8c\u8fdb\u5236\u6570\u5e76\u8f93\u51fa\u7ed3\u679c\u3002

C\u8bed\u8a00\u7684\u7248\u672c\u6211\u4ee5\u524d\u5199\u8fc7\uff0c\u4e0d\u8fc7\u5acc\u5b83\u592a\u4e11\u800c\u4e14\u7528\u5904\u4e0d\u591a\u4e45\u6ca1\u5b58\u6863\u3002
\u7ed9\u4f60\u4e00\u4e2aC++\u7248\u672c\u7684\u5427\uff01
#include
int main()
{
int n = 121; //\u5b9a\u4e49\u4e00\u4e2a\u6574\u6570
bitset bit(121); //16\u4f4d
cout << bit << endl; //\u8f93\u51fa\u5230\u63a7\u5236\u53f0\u5c31\u662f\u4e8c\u8fdb\u5236\u4e86
}
\u6bd4\u8f83\u65b9\u4fbf\u5427\uff0c\u5c31\u9760bitset\u7c7b\u5c31\u89e3\u51b3\u4e86\uff0c\u4f55\u4e50\u800c\u4e0d\u4e3a\u5462\uff1f

#include
void main()
{
int x,a[32],i=0;
printf("\u8bf7\u8f93\u5165\u4e00\u4e2a\u5341\u8fdb\u5236\u6574\u6570.\n");
scanf("%d",&x);
while(x!=0)
{
a[i++]=x%2;
x=x/2;
}
for(i--;i>=0;i--)
printf("%d",a[i]);
printf("\n");
}

#include<stdio.h>
#include <stdlib.h>

int main(int argc, char* argv[])
{
    int a;
    char ascii[100];
    printf("输入10进制数:");
    scanf("%d", &a);
    itoa(a, ascii, 2);
    printf("2进制数:%s
", ascii);
    return 0;
}


#include <stdio.h>
int main()
{
int n,a[100],i=0,j;
scanf("%d",&n);
while(n)
{
a[i++]=n%2;
n/=2;
}
for(j=i-1;j>=0;j--)
printf("%d",a[j]);
printf("\n");
return 0;
}
/*
输出:
10
1010
*/

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