图所示电路中,已知R1=20Ω,R2=5Ω,a,b两端的等效电阻R为 如下图,已知R1=5Ω,R2=10Ω,R3=R4=20Ω。试...

\u56fe\u6240\u793a\u7535\u8def\u4e2d\uff0c\u5df2\u77e5R1\uff1dR2\uff1d20\u03a9\uff0ca\uff0cb\u4e24\u7aef\u7684\u7b49\u6548\u7535\u963bR\u4e3a

Rab=-4\u6b27




\u7ed9\u4e2a\u7b80\u5355\u7684\u7b49\u6548\u7535\u8def\u56fe\uff0cR2\u662f\u6700\u4e0a\u9762\u7684\u7535\u963b\uff0c\u5c06ab\u4e24\u7aef\u7ffb\u8f6c\uff0c\u5982\u4e0a\u56fe\uff1a

\u7b54\u6848\uff1aRab=13.33\u6b27
\u89e3\u6790\uff1a
ab\u95f4\u76f8\u5f53\u4e8eR1\u3001R3\u3001R4\u4e09\u4e2a\u5e76\u8054\uff0c\u5e76\u8054\u4e4b\u540e\u4e0eR2\u4e32\u8054\uff0c\u6545\u603b\u7535\u963b\u4e3a\uff1a
R1\u3001R3\u3001R4\u4e09\u4e2a\u5e76\u8054\u7684\u603b\u7535\u963b\u4e3a\uff1a
1/R\u5e76\uff1d1/5\uff0b1/20\uff0b1/20
\u5373\uff1aR\u5e76\uff1d10/3\u6b27
Rab\uff1d10\uff0b10/3\uff1d40/3\u224813.33\u6b27

若端电压 为U(上正下负),由KCL可知R2电阻的电流为I(方向朝上),然后可列由 U、R1和R2构成回路的KVL方程,即:U+5*I-20*I=0 U=15*I 则等效电阻为Rab=U/I=15欧

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