c语言中，这题为什么选b？
[C\u8bed\u8a00]\u8bf7\u95ee\u8fd9\u9898\u4e3a\u4ec0\u4e48\u9009B?\u6c42\u5927\u795e\uff01\uff01\u8c22\u8c22\uff01fprintf(fp,"%d",i); //\u6b64\u51fd\u6570\u662f\u5411\u6d41\u4e2d\u4f9d\u7167\u6307\u5b9a\u7684\u683c\u5f0f\u5199\u5165\u6570\u636e\uff0c\u7b2c\u4e00\u9898\u5199\u5165123\u5230\u6587\u672cfscanf(fp,"%d%d",&k,&n); //\u8bfb\u53d6\u6570\u636e\uff0c\u8bfb\u53d6\u65b9\u5f0f\u9ed8\u8ba4\u4e3a\n\u6216\u7a7a\u683c\uff0c\u8fd9\u91ccd1\u6587\u672c\u4e2d\u6ca1\u6709\u7a7a\u683c\uff0c\u6240\u4ee5\u4ee5\u6362\u884c\u95f4\u9694\uff0c\u6240\u4ee5\u7b2c\u4e00\u9898k\u8bfb\u5230\u7684\u662f123\uff0cn\u6ca1\u6709\u8bfb\u5230\u6570\u636e\uff0c\u8f93\u51fa\u7684\u65f6\u5019\u4e3a"%d\u7a7a\u683c%d"\uff0c\u6240\u4ee5\u7ed3\u679c\u4e3a123\u7a7a\u683c0\uff1b\u7b2c\u4e8c\u9898\uff0c\u5199\u5165\u6570\u636e\u683c\u5f0f\u4e3a"%d\u7a7a\u683c"\uff0c\u5373\u5199\u5165\u6570\u636e\u4e3a1 2 3\n4 5\uff0c\u8bfb\u53d6\u683c\u5f0f\u4e3a\u201c%d%d\u201d\uff0c\u9ed8\u8ba4\u4ee5\u7a7a\u683c\u95f4\u9694\uff0c\u6240\u4ee5k=1,n=2\uff0c\u8f93\u51fa\u683c\u5f0f\u4e3a"%d%d"\uff0c\u6240\u6709\u7ed3\u679c\u4e3a12\uff0c\u6b64\u9898\u6ca1\u6709\u7b54\u6848\uff0cD\u5217\u5370\u51fa\u9519
\u7b54\u6848\u9519\u4e86\uff0c\u5e94\u8be5\u662fA
d = 241d/100 = 2 /是取除数
2%9 =2 %是取余数
&&两边的值只要没有0那么答案就是1
所以答案是B
d/100=2 -> 2%9=2(%为取余数的意思） -> a=2
-1 = 11111111
------------------
1&&1=1 1&&0=0 0&&0=0
------------------
11111111
&
11111111
----------
11111111
按位做 "与 "
所以-1&&-1 =1
非0都是1
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