java怎么获取一个字符串中指定的值啊? 比如我这个字符串是“123abc56de” 我想把数字拆分出来该怎么做 java怎么获取一个字符串中指定的值 比如字符串是“123c...

java\u600e\u4e48\u83b7\u53d6\u4e00\u4e2a\u5b57\u7b26\u4e32\u4e2d\u6307\u5b9a\u7684\u503c\u554a\uff1f \u6bd4\u5982\u6211\u8fd9\u4e2a\u5b57\u7b26\u4e32\u662f\u201c123abc56de\u201d

\u4e0d\u77e5\u9053\u4f60\u5177\u4f53\u7684\u9700\u6c42\u662f\u4ec0\u4e48\uff0c\u53ea\u662f\u60f3\u4ece\u4e00\u4e2a\u5b57\u7b26\u4e32\u91cc\u9762\u628a\u6240\u6709\u7684\u6570\u5b57\u90fd\u83b7\u53d6\u51fa\u6765\u4e48\uff1f
import java.util.LinkedList;import java.util.List;public class Test {public static void main(String[] args) {System.out.println(getNumberFromString("adgasdg2342352aa53cc23"));}static List getNumberFromString(String s){List list = new LinkedList();if(s!=null){char[] c = s.toCharArray();StringBuilder numStr = new StringBuilder();for(int i=0;i0){list.add(Integer.parseInt(numStr.toString()));numStr.setLength(0);}}}if(numStr.length()>0){list.add(Integer.parseInt(numStr.toString()));}}return list;}}\u597d\u50cf\u6ca1\u6709\u76f4\u63a5\u53ef\u4ee5\u7528\u7684\u65b9\u6cd5\uff0c\u8fd9\u662f\u6211\u81ea\u5df1\u968f\u4fbf\u5199\u7684\u4e00\u4e2a\u7b97\u6cd5\uff0c\u4f9b\u4f60\u53c2\u8003\uff08\u4f60\u4e5f\u53ef\u4ee5\u8003\u8651\u6b63\u5219\u4ee3\u7801\u53ef\u80fd\u4f1a\u7b80\u5316\u4e0d\u5c11\uff09

public void extractionNumber(){String s = "123c56de"; Pattern p = Pattern.compile("\\d+"); Matcher m = p.matcher(s); int count = 0; while (m.find()) { count += Integer.valueOf(m.group(0)); } System.out.println("The Total is :" + count);}\u5df2\u6d4b\u8bd5\uff0c\u5e0c\u671b\u91c7\u7eb3\u3002

可以使用正则表达式。比如说
String str="123abc56de";
String[] s=str.split("[a-zA-Z]+");
for(int i=0;i<s.length;i++){
System.out.println(s[i]);
}
直接粘贴过去,就可以了,记得好评哟

先把字符串放到一个字符数组里面,再判断就可以可以了啊!

你想得到123和56两个数值?

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