急需求救!由键盘输入n,求s=1*2*3*...n。(1)画出普通流程图。(2)用c语言编写程序实现上述算法。 求S=1-1/2+1/3-1/4+...-1/n的值(n为偶...

\u753b\u51fa\u6d41\u7a0b\u56fe,\u7528\u57fa\u672c\u8bed\u53e5\u5199\u51fa\u7b97\u6cd5:\u8f93\u5165n,\u6c42S=1+1/2+1/3+\u2026\u2026+1/n\u7684\u503c

\u5f00\u59cb\uff08\u8d77\u59cb\u6846\uff09
i
=
1,s
=
0\uff08\u8f93\u5165\u6846\uff09
s\u52a0\u4e0a(1/i)
i
<
n
\u56de\u5230\uff08\u5224\u65ad\u6846\uff09yes\u7bad\u5934\u6253\u5411\u4e0a\u4e00\u6b65\uff0cno\u6307\u5411\u4e0b\u4e00\u6b65
\u8f93\u51fas
\uff08\u8f93\u51fa\u6846\uff09
\u7ed3\u675f\uff08\u8d77\u59cb\u6846\uff09


程序如:
#include<stdio.h>
void main()
{
long n,s;
int i;
printf("请输入n:");
scanf("%ld",&n);
for(i=1;i<=n;i++)
s*=i;
printf("%ld",s);
}

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