初一因式分解，赶快
\u521d\u4e00\u56e0\u5f0f\u5206\u89e31.\uff08x^2-3)^2+2(x^2-3)(x-3)+(x-3)^2
=(x^2-3+x-3)^2
=(x^2+x-6)^2
=(x+3)^2(x-2)^2
2.(x+1)(x+3)(x+5)(x+7)+15
=[(x+1)(x+7)][(x+3)(x+5)]+15
=(x^2+8x+7)(x^2+8x+15)+15
=(x^2+8x)+22(x^2+8x)+105+15
=(x^2+8x)+22(x^2+8x)+120
=(x^2+8x+10)(x^2+8x+12)
=(x^2+8x+10)(x+2)(x+6)
3.x^2+y^2+4x+2y+3\u2014\u2014\u9898\u76ee\u662f\u4e0d\u662f\u5199\u9519\u4e86\u5440
x^2-y^2+4x+2y+3
=(x^2+4x+4)-(y^2-2y+1)
=(x+2)^2-(y-1)^2
=(x+2+y-1)(x+2-y+1)
=(x+y+1)(x-y+3)
4.(a^2+a+1)^2+2(a^2+a+1)(a^2+a-1)+(a^2+a-1)^2
=(a^2+a+1+a^2+a-1)^2
=(2a^2+2a)^2
=[2a(a+1)]^2
=4a^2(a+1)^2
5.(x^2+4)^2-16x^2
=(x^2+4+4x)(x^2+4-4x)
=(x+2)^2(x-2)^2
6.(a+b+c)^2-(a-b-c)^2
=(a+b+c+a-b-c)(a+b+c-a+b+c)
=2a(2b+2c)
=4a(b+c)
7.25(x-y)^2-16(x+y)^2
=[5(x-y)+4(x+y)][5(x-y)-4(x+y)]
=(9x-y)(x-9y)
8.x^4-81x^2y^2
=x^2(x^2-9y^2)
=x^2(x+3y)(x-3y)
9.x^2(x-y)+y^2(y-x)
=(x^2-y^2)(x-y)
=(x+y)(x-y)^2
10.(a-b)(x-y)+(b-a)(x+y)
=(b-a)(-x+y+x+y)
=2y(b-a)
(\u4e58\u6cd5)
11.2(2m-1)^2-3(m+1)(m-1)-2(m-1)^2
=8m^2-8m+2-3m^2+3-2m^2+4m-2
=3m^2-4m+3
12.(2x+y+3t)(2x-y-3t)
=(2x)^2-(y+3t)^2
=4x^2-y^2-6ty-9t^2
13.(3a+1)^2(3a-1)^2
=[(3a+1)(3a-1)]^2
=(9a^2-1)^2
=81a^4-18a^2+1
14.(2x-y)(2x+y)-(3x-y)(4x-y)
=4x^2-y^2-(12x^2-7xy+y^2)
=-8x^2+7xy-2y^2
15.(-4x+2y)(-2y-4x)-(2x+3y)(8x-9y)
=(-4x)^2-(2y)^2-(16x^2+6xy-27y^2)
=16x^2-4y^2-16x^2-6xy+27y^2
=23y^2-6xy
16.(2a+b-c)^2
=(2a)^2+2\u00b72a(b-c)+(b-c)^2
=4a^2+4ab-4ac+b^2-2bc+c^2
=4a^2+b^2+c^2+4ab-4ac-2bc
\u89e3\uff1a
4(2x^2-x+1)(x^2-2x+3)-(3x^2-3x+4)^2 =4(2x^2-x+1)(x^2-2x+3)-[(2x^2-x+1)+(x^2-2x+3)]^2 =4(2x^2-x+1)(x^2-2x+3)-(2x^2-x+1)^2-(x^2-2x+3)^2-2(2x^2-x+1)(x^2-2x+3) =-(2x^2-x+1)^2-(x^2-2x+3)^2+2(2x^2-x+1)(x^2-2x+3) =-[(2x^2-x+1)^2+(x^2-2x+3)^2-2(2x^2-x+1)(x^2-2x+3) =-[(2x^2-x+1)-(x^2-2x+3)]^2 =-(x^2+x-2)^2 =-(x+2)^2(x-1)^2
\u795d\u5b66\u4e60\u8fdb\u6b65
=(3a+b)(3a-b)/(3a-b)
=3a+b
2.(x^2+13x+42)/(x+6)
=(x+6)(x+7)/(x+6)
=x+7
3.(3m^2-5m-2)/(3m+1)
=(3m+1)(m-2)/(3m+1)
=m-2
4.(x^2-y^2+2x+1)/(x-y+1)
=[(x+1)^2-y^2]/(x-y+1)
=(x-y+1)(x+y+1)/(x-y+1)
=x+y+1
5.(3x^3*y^2+6x^2*y^3)/(x+2y)
=3x^2y^2(x+2y)/(x+2y)
=3x^2y^2
6.(2-32a^4)/(4a^2+1)/(2a+1)
=2(1-16a^4)/[(4a^2+1)(2a+1)]
=2(1-4a^4)(1+4a^2)/[(4a^2+1)(2a+1)]
=2(1-2a)(1+2a)/[(4a^2+1)(2a+1)]
=2(1-2a)
=2-4a
7.解方程x^3-9x=0
x(x-9)=0
x1=0,x2=9
8.解方程x^3-4x=x^2-4
x(x^2-4)-(x^2-4)=0
(x^2-4)(x-1)=0
(x+2)(x-2)(x-1)=0
x1=-2,x2=2,x3=1
9.已知（a^2+b^2)*(a^2+b^2-1)=6,求a^2+b^2的值
令m=a^2+b^2
则a*(a-1)=6
a^2-a-6=0
(a-3)(a+2)=0
a1=3,a2=-2
因为x^2+y^2>=0
所以a2=-2舍去
所以x^2+y^2=a1=3
10.若二次三项式x^2+ax-1可分解成（x-2)(x+b)求(a+b)的值
(x-2)(x+b)
=x^2-2x+bx-2b
=x^2+(b-2)^2-2b
=x^2+ax-1
对应项系数相等
所以b-2=a,-2b=-1
b=1/2,a=b-2=-3/2
所以a+b=-1
题目太多了
靠这么多 少一点再说
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