初一的题，求过程
\u5176\u5b9e\u662f\u521d\u4e00\u7684\u9898\uff0c\u8981\u8fc7\u7a0b\u3002
1\u3001\u89e3\u8bbe\u8be5\u5e02\u89c4\u5b9a\u7684\u4e09\u53e3\u4e4b\u5bb6\u697c\u623f\u6bcf\u6708\u6807\u51c6\u7528\u6c34\u91cf\u4e3aX\u7acb\u65b9\u7c73\u3002
(12-X)*2.9+1.3X=22
2\u3001\u628aX=-1\u5e26\u5165\u4e3a-a+b=0 a\u548cb\u4e3a\u76f8\u53cd\u6570
3\u3001\u674e\u541b\u5728\u8def\u4e0a\u884c\u8d70\uff0c\u4ed6\u6bcf\u5c0f\u65f6\u8d706\u5343\u7c73\uff0c\u4e00\u8f86\u8f66\u8eab\u957f\u4e3a20\u7c73\u7684\u6c7d\u8f66\u4ece\u674e\u541b\u80cc\u540e\u9a76\u6765\uff0c\u5e76\u4ece\u674e\u541b\u8eab\u65c1\u9a76\u8fc7\u3002\u4ece\u8f66\u5934\u9a76\u5411\u674e\u541b\u5230\u8f66\u5c3e\u9a76\u8fc7\u674e\u541b\u7684\u65f6\u95f4\u4e3a1\u30015\u79d2\uff0c\u6c42\u6c7d\u8f66\u7684\u901f\u5ea6\u662f\u591a\u5c11\u3002
40/1.5
4\u30013\u9879\u76f8\u540c\u7684\u5de5\u7a0b\u7531\u7532\u3001\u4e59\u3001\u4e193\u4e2a\u4eba\u5b8c\u62101\u9879\uff0c\u7532\u6bd4\u4e59\u591a\u75281\u5929\uff0c\u4e59\u6bd4\u4e19\u591a\u75283\u5929\u3002\u4ed6\u4eec\u5f00\u5de5\u7684\u65f6\u95f4\u4e5f\u4e0d\u540c\uff0c\u7532\u6bd4\u4e59\u665a\u5f00\u5de53\u5929\uff0c\u4e19\u6bd4\u4e59\u665a\u5f00\u5de56\u5929\uff0c\u4ece\u7b2c\u4e00\u4e2a\u4eba\u5f00\u5de5\uff0c\u5230\u6700\u540e\u4e00\u4eba\u628a\u5de5\u7a0b\u5e72\u5b8c\uff0c\u524d\u540e\u7528\u4e8625\u5929\u3002\u95ee\u6ca1\u4eba\u5404\u9700\u8981\u591a\u5c11\u5929\u5b8c\u6210\u4e00\u9879\u5de5\u7a0b\uff1f
5\u3001\u5c0f\u864e\u548c\u7238\u7238\u7684\u5e74\u9f84\u4e4b\u548c\u662f52\u5c81\uff0c7\u5e74\u540e\u7238\u7238\u7684\u5e74\u9f84\u662f\u5c0f\u864e\u5e74\u9f84\u76842\u500d\u8fd8\u591a6\u5c81\uff0c\u6c42\u5c0f\u864e\u4eca\u5e74\u51e0\u5c81\uff1f
6\u3001\u67d0\u8d27\u8239\u8f7d\u91cd\u91cf\u4e3a600\u5428\uff0c\u8d27\u4ed3\u5bb9\u79ef465\u7acb\u65b9\u7c73\uff0c\u73b0\u8981\u88c5\u94c1\u548c\u68c9\u82b1\u4e24\u79cd\u8d27\u7269\uff0c\u5df2\u77e5\u94c1\u6bcf\u5428\u4f53\u79ef0\u300113\u7acb\u65b9\u7c73\uff0c\u68c9\u82b1\u6bcf\u5428\u4f53\u79ef4\u7acb\u65b9\u7c73\uff0c\u95ee\u94c1\u548c\u68c9\u82b1\u5404\u88c5\u591a\u5c11\u5428 \u624d\u80fd\u5145\u5206\u5229\u7528\u8239\u7684\u8f7d\u91cd\u91cf\u548c\u8d27\u4ed3\u7684\u5bb9\u79ef\uff1f
7\u3001\u67d0\u6587\u5177\u5e97\u51fa\u552e\u67d0\u79cd\u6587\u5177\uff0c\u6bcf\u4ef6\u53ef\u76c8\u52292\u5143\uff0c\u4e3a\u4e86\u652f\u63f4\u8d2b\u56f0\u5c71\u533a\uff0c\u73b0\u5728\u6309\u539f\u552e\u4ef77\u6298\u51fa\u552e\u4e00\u5c71\u533a\u5b66\u6821\uff0c\u7ed3\u679c\u6ca1\u4ef6\u53ea\u76c8\u52290\u30012\u5143\uff0c\u95ee\u8be5\u6587\u5177\u6bcf\u4ef6\u7684\u8fdb\u8d27\u4ef7\u662f\u591a\u5c11\u5143\uff1f
8\u3001\u5c0f\u7ea2\u670940\u514b\u548c60\u514b\u7684\u4e24\u79cd\u5c0f\u9970\u54c1\u51715\u4e2a\uff0c\u8fd95\u4e2a\u5c0f\u9970\u54c1\u603b\u91cd260\u514b\uff0c\u521940\u514b\u4e0e60\u514b\u7684\u5c0f\u9970\u54c1\u7684\u4e2a\u6570\u5206\u522b\u662f\u591a\u5c11\uff1f
9\u3001\u67d0\u5546\u573a\u95e8\u53e3\u9a6c\u8def\u5411\u4e1c\u662f\u516c\u56ed\uff0c\u5411\u897f\u662f\u67d0\u4e2d\u5b66\u3002\u8fd9\u4e2a\u4e2d\u5b66\u7684\u4e24\u540d\u5b66\u751f\u4ece\u5546\u573a\u51fa\u53d1\u51c6\u5907\u53bb\u516c\u56ed\uff0c\u4ed6\u4eec\u5546\u8bae\u4e24\u79cd\u65b9\u6848\uff1b
\uff081\uff09\u662f\u6b65\u884c\u56de\u6821\u53d6\u81ea\u884c\u8f66\uff0c\u7136\u540e\u9a91\u8f66\u53bb\u516c\u56ed\uff1b
\uff082\uff09\u76f4\u63a5\u4ece\u5546\u573a\u6b65\u884c\u53bb\u516c\u56ed
\u5df2\u77e5\u9a91\u8f66\u7684\u901f\u5ea6\u662f\u6b65\u884c\u7684\u901f\u5ea6\u76844\u500d\uff0c\u4ece\u5546\u573a\u5230\u5b66\u6821\u67093km\u7684\u8def\u7a0b\uff0c\u7ed3\u679c\u4e24\u65b9\u6848\u82b1\u7684\u65f6\u95f4\u76f8\u540c\uff0c\u5219\u5546\u573a\u5230\u516c\u56ed\u7684\u8def\u7a0b\u662f\u591a\u5c11\u5343\u7c73\uff1f
10\u3001\u4f60\u77e5\u9053\u4e00\u5f20100\u5143\u4eba\u6c11\u5e01\u7684\u4f53\u79ef\u5417\uff1f\u8bf7\u4f60\u5224\u65ad\u4e00\u4e0b\u4e00\u4e2a90cm\u00d765cm\u00d720cm\u7684\u7bb1\u5b50\u53ef\u4ee5\u88c5\u4e0b\u591a\u5c11\u5f20100\u5143\u7684\u4eba\u6c11\u5e01\uff1f
11\u30019596960\u7684\u6709\u6548\u6570\u5b57\u662f\uff08 \uff09
\u8f93\u5165\u5185\u5bb9\u5df2\u7ecf\u8fbe\u5230\u957f\u5ea6\u9650\u5236
\u8fd8\u80fd\u8f93\u5165 9940 \u5b57\u63d2\u5165\u56fe\u7247\u5220\u9664\u56fe\u7247\u63d2\u5165\u5730\u56fe\u5220\u9664\u5730\u56fe\u63d2\u5165\u89c6\u9891\u89c6\u9891\u5730\u56fe1\u3001\u89e3\u8bbe\u8be5\u5e02\u89c4\u5b9a\u7684\u4e09\u53e3\u4e4b\u5bb6\u697c\u623f\u6bcf\u6708\u6807\u51c6\u7528\u6c34\u91cf\u4e3aX\u7acb\u65b9\u7c73\u3002
(12-X)*2.9+1.3X=22
2\u3001\u628aX=-1\u5e26\u5165\u4e3a-a+b=0 a\u548cb\u4e3a\u76f8\u53cd\u6570
3\u3001
\u53c2\u8003\u8d44\u6599\uff1a\u533f\u540d\u56de\u7b54\u63d0\u4ea4\u56de\u7b54 \u56de\u7b54 \u51712\u6761
\u5b66\u4e60\u8981\u811a\u8e0f\u5b9e\u5730\u3001\u3001\u52aa\u529b
\u56de\u7b54\u8005\uff1a \u9146\u9335\u96ea\u50f7 | \u4e00\u7ea7 | 2011-2-5 13:17
\u540e\u9762\u4e24\u9053\u771f\u662f\u521d\u4e00\u7684\u6570\u5b66\u9898\u76ee\uff01\uff01\uff01
\u56de\u7b54\u8005\uff1a \u70ed\u5fc3\u7f51\u53cb | 2011-2-5 13:36
\u8f6c\u53d1\u5230\uff1a \u02c9_\u7c73\u8bed\u4e8c\u7ea7\u6211\u7684\u63d0\u95ee \u6211\u7684\u56de\u7b54 \u79ef\u5206\u5546\u57ce
\uff080\uff09\u6761\u6d88\u606f\u7b49\u5f85\u5904\u7406
\u4eca\u5929\u4f60\u505a\u4efb\u52a1\u4e86\u6ca1\uff1f\u5168\u90e8\u4efb\u52a1\u6301\u4e4b\u4ee5\u6052.\u8301\u58ee\u6210\u957f +100.\u626c\u5e06\u8d77\u822a +660..\u8fdb\u5165\u4e2a\u4eba\u4e2d\u5fc3
\u4f7f\u7528\u767e\u5ea6Hi\u53ef\u4ee5\u7b2c\u4e00\u65f6\u95f4\u6536\u5230\u201c\u63d0\u95ee\u6709\u65b0\u56de\u7b54\u201d\u201c\u56de\u7b54\u88ab\u91c7\u7eb3\u201d\u201c\u7f51\u53cb\u6c42\u52a9\u201d\u7684\u901a\u77e5\u3002\u67e5\u770b\u8be6\u60c5
\u60a8\u60f3\u5728\u81ea\u5df1\u7684\u7f51\u7ad9\u4e0a\u5c55\u793a\u767e\u5ea6\u201c\u77e5\u9053\u201d\u4e0a\u7684\u95ee\u7b54\u5417\uff1f\u6765\u83b7\u53d6\u514d\u8d39\u4ee3\u7801\u5427\uff01
\u5982\u8981\u6295\u8bc9\u6216\u63d0\u51fa\u610f\u89c1\u5efa\u8bae\uff0c
\u8bf7\u5230\u767e\u5ea6\u77e5\u9053\u6295\u8bc9\u5427\u53cd\u9988\u3002
©2011 Baidu \u4f7f\u7528\u767e\u5ea6\u524d\u5fc5\u8bfb \u77e5\u9053\u534f\u8bae \u4efb\u52a1\u63d0\u9192x
3*(10+5+15+30+20+16+14)=330升
第二问为
10-5-15+30-20-16+14=-2
即在A点的西侧2千米处
110/3
〔1〕〔10—5—15＋30—20—16＋14〕×0，01×3＝1，26
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绛旓細4. 鍒濅竴鍗曠嫭1灏忔椂瀹屾垚锛2/15 锛15鍒嗕箣2 鍖栫畝鍘熷紡2/7.5锛 鍒濅簩鍗曠嫭涓灏忔椂锛1/5 鍒濅竴銆佸垵浜屼竴璧峰伐浣滐細2/15+1/5=5/15=1/3 鍓╀綑锛1-1/3=2/3 鍒濅簩瀹屾垚鏃堕棿 2/3梅1/5= 10/3 鍏遍渶锛10/3+1=13/3 鐮佸瓧寰堣緵鑻﹀搱~~~ 甯屾湜閲囩撼鍝垀~~...
绛旓細锛-2锛壝凤紙-2鍙堝洓鍒嗕箣涓锛壝楋紙-1.5锛=锛-2锛墄(-4/9)X(-3/2)=-4/3 -14+锛1-0.5锛壝椾笁鍒嗕箣涓脳锛3-9锛=-14+1/2x1/3x(-6)=-14-1 =-15 -8脳锛+12锛壝楋紙-7锛壝13 =-96x(-7)x1/13 =672/13 涓夊張浜屽垎涔嬩竴*锛-涓冨垎涔嬩簲锛+锛-涓冨垎涔嬩簲锛*浜屽張浜屽垎涔嬩竴+锛-...
