x-1的三次方的导数是? (x-1)的2/3次方的导数怎么求,写出过程,谢谢大家了

(x-1)\u7684\u4e09\u6b21\u65b9\u600e\u4e48\u6c42\u5bfc

\uff08x+1)³=x³+3x²+3x+1
\u5b8c\u5168\u7acb\u65b9\u516c\u5f0f\uff1aa³\u00b13a²b\uff0b3ab²\u00b1b³=(a\u00b1b)³
\u7acb\u65b9\u548c\u516c\u5f0f\uff1aa³+b³=(a+b)(a²-ab+b²)
\u7acb\u65b9\u5dee\u516c\u5f0f\uff1aa³-b³=(a-b)(a²+ab+b²)

\u6211\u5728\u505a\u4efb\u52a1\u54e6\uff01\u5e0c\u671b\u80fd\u628a\u6211\u8bbe\u4e3a\u6700\u4f73\u7b54\u6848\u8c22\u8c22\u4f60~~~\u611f\u6fc0\u4e0d\u5c3d\u3002\u3002

\u89e3\uff1a\u56e0\u4e3ax^n\u7684\u6c42\u5bfc\u516c\u5f0f\u662f\uff08x^n\uff09'
=
nx^(n-1)\uff0c

\u6240\u4ee5
(x\uff0d1)^(2/3)
=
2/3(x\uff0d1)^(2/3\uff0d1)
=
2/3(x\uff0d1)^(\uff0d1/3)

[(x-1)^3]'=3(x-1)^2

y'(x)= 3(x-1)^2

3(X-1)^2

3(x-1)^2

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