电解饱和食盐水,当阴极附近有0.4molOH-生成时,阳极生成(  )A.0.2mo

\u7535\u89e3\u9971\u548c\u98df\u76d0\u6c34\uff0c\u5f53\u9634\u6781\u9644\u8fd1\u67090.4molOH - \u751f\u6210\u65f6\uff0c\u9633\u6781\u751f\u6210\uff08\u3000\u3000\uff09 A\uff0e0.2mol H 2 B\uff0e0.2mol Cl 2

\u7535\u89e3\u9971\u548c\u98df\u76d0\u6c34\uff0c\u9633\u6781\u53d1\u751f2Cl - -2e - =Cl 2 \u2191\uff0c\u9634\u6781\u53d1\u751f4H 2 O+4e - =2H 2 \u2191+4OH - \uff0c\u7531\u7535\u5b50\u5b88\u6052\u53ef\u77e5\uff0c2Cl 2 \u2191\uff5e4OH - \uff0c\u9634\u6781\u9644\u8fd1\u67090.4molOH - \u751f\u6210\u65f6\uff0c\u9633\u6781\u751f\u6210\u6c2f\u6c14\u4e3a 0.4mol 2 =0.2mol\uff0c\u6545\u9009B\uff0e

2NaCl+2H2O=2NaOH+H2+Cl2
\u770b\u5316\u5b66\u65b9\u7a0b\u5f0f\u7684\u8bdd\u5e94\u8be5\u662f1\uff1a1 \u4f46\u56e0\u4e3a\u6c2f\u6c14\u4f1a\u6709\u4e00\u90e8\u5206\u6eb6\u4e8e\u6c34,\u6240\u4ee5\u9633\u6781\u751f\u6210\u7684\u6c14\u4f53\u5e94\u8be5\u4f1a\u6bd4\u9634\u6781\u5c11

电解饱和食盐水,阴极上的电极反应式为2H++2e-=H2↑,当阴极附近有0.4molOH-生成时,说明在该极上减少的氢离子为0.4mol,所以会转移电子0.4mol,阳极电极反应式为2Cl--2e-═Cl2,生成0.2molCl2
故选B.

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