求解java中16进制补码转10进制数要怎么转 java 中的 ~ 取补码的详细意思是什么 ?
java\u4e2d\u600e\u4e48\u628a\u4e00\u4e2a16\u8fdb\u5236\u6570\u7684\u7b2c\u516d\u4e2a\u6bd4\u7279\u4f4d\u53d6\u8865\u7801~\u5c31\u662f\u53d6\u53cd\u7684\u610f\u601d\u3002\u5c31\u662f\u628a\u90a3\u4e2a\u6570\u5b57\u7684\u4e8c\u8fdb\u5236\u4f4d\uff0c\u539f\u6765\u662f0\u7684\u53d8\u4e3a1\uff0c\u539f\u6765\u662f1\u7684\u53d8\u4e3a0.\u800c\u4e8c\u8fdb\u5236\u8865\u7801\u8868\u793a\u7684\u6570\u5b57\uff08\u73b0\u5728\u7684\u8ba1\u7b97\u673a\u51e0\u4e4e\u90fd\u662f\u7528\u7684\u4e8c\u8fdb\u5236\u8865\u7801\u6765\u8868\u793a\u7684\uff09\u8fdb\u884c\u8fd9\u6837\u7684\u64cd\u4f5c\u5c31\u7b49\u4e8e\u53d6\u76f8\u53cd\u6570\u518d\u51cf\u4e00\u3002\u6240\u4ee5~5\u5c31\u662f-5-1=-6.\u800c\u540e\u9762\u90a3\u4e2a~a-b\u5c31\u662f~5-3\uff0c\u800c~5=-6\u6240\u4ee5\u5c31\u662f-6-3=-9\u4e86\u3002
\u5bf9\u4e8e\u4e8c\u8fdb\u5236\u8865\u7801\u7684\u6570\u5b57\u7684\u64cd\u4f5c\uff0c\u5982\u679c\u4f60\u662f\u5b66\u8ba1\u7b97\u673a\u4e13\u4e1a\u7684\u5b66\u751f\uff0c\u90a3\u4e48\u4f1a\u5728\u8ba1\u7b97\u673a\u57fa\u7840\u4e4b\u7c7b\u7684\u8bfe\u7a0b\u91cc\u9762\u5b66\u7684\u3002\u5982\u679c\u4e0d\u662f\u5b66\u8ba1\u7b97\u673a\u4e13\u4e1a\u7684\uff0c\u77e5\u9053\u8fd9\u4e2a\u7ed3\u8bba\u5c31\u53ef\u4ee5\u4e86\u3002
public class 十六转10 {
//补码源码这些东西只发生在二进制里面,不要混淆!
public static void main(String[] args) {
String s1="a",s2="b",s3="3c";
//方法1:
int a1=Integer.parseInt(s1,16);
int a2=Integer.parseInt(s2,16);
int a3=Integer.parseInt(s3,16);
//方法2:
int b1=Integer.valueOf(s1,16);
int b2=Integer.valueOf(s2,16);
int b3=Integer.valueOf(s3,16);
//打印!
System.out.println("a1="+a1+"a2="+a2+"a3="+a3);
System.out.println("b1="+b1+"b2="+b2+"b3="+b3);
// a1=10 a2=11 a3=60
// b1=10 b2=11 b3=60
}
}
Integer.valueOf("0101",2)
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