有浓度为90%的酒精100克,现在把它稀释成浓度为60%的酒精,需要加水多少克?给好评啊 浓度为80%的酒精加浓度为100%的酒精需要多少成90%
\u9152\u7cbe30\u514b\uff0c\u628a\u5b83\u7a00\u91ca\u621075%\u7684\u9152\u7cbe\uff0c\u5e94\u52a0\u6c34\u591a\u5c11\u514b30\u00f775%-30
=40-30
=10\uff08\u514b\uff09
\uff081\u00d780%-1\u00d760%\uff09\u00f7\uff0860%-55%\uff09\uff0c=0.2\u00f70.05\uff0c=4\uff08\u5347\uff09\uff0c[\uff084+1\uff09\u00d770%-\uff084+1\uff09\u00d760%]\u00f7\uff0880%-70%\uff09\uff0c=0.5\u00f70.1\uff0c=5\uff08\u5347\uff09\uff1b\u7b54\uff1a\u9700\u8981\u518d\u52a0\u4eba5\u5347\u6d53\u5ea6\u4e3a80%\u7684\u9152\u7cbe\u6eb6\u6db2\uff0e
稀释问题核心为溶质不变设加入水X克,加水后溶液质量为100+X,可以得到如下的式子
100*90%=(100+X)*60%
90=60+0.6X
0.6X=30
X=50
答:加入水为50克
30
30g
50
50
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绛旓細鍒╃敤婧惰川瀹堟亽锛岃鍔爕鍏 锛坹+100锛25%=yx5%+100x50
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