编程:编写一个求x的n次方的函数(函数名为power),在主函数中输入x和n的值,调用函数求出x的 c++编写求x的n次方的递归函数,并在主函数中调用、输出。 ...

C\u8bed\u8a00 \u51fd\u6570\u529f\u80fd\u662f\u8ba1\u7b97x\u7684n\u6b21\u65b9

C\u8bed\u8a00\u4e2d\u8ba1\u7b97x\u7684n\u6b21\u65b9\u53ef\u4ee5\u7528\u5e93\u51fd\u6570\u6765\u5b9e\u73b0\u3002\u5177\u4f53\u7684\u4ee3\u7801\u5982\u4e0b\uff1a
#include
#include
int main( ) {printf("%f",pow\uff08x\uff0cn)\uff09\uff1breturn 0\uff1b}
C\u8bed\u8a00\u662f\u4e00\u79cd\u7ed3\u6784\u5316\u8bed\u8a00\uff0c\u5b83\u6709\u7740\u6e05\u6670\u7684\u5c42\u6b21\uff0c\u53ef\u6309\u7167\u6a21\u5757\u7684\u65b9\u5f0f\u5bf9\u7a0b\u5e8f\u8fdb\u884c\u7f16\u5199\uff0c\u4e14c\u8bed\u8a00\u7684\u5904\u7406\u548c\u8868\u73b0\u80fd\u529b\u90fd\u975e\u5e38\u7684\u5f3a\u5927\uff0c\u4f9d\u9760\u975e\u5e38\u5168\u9762\u7684\u8fd0\u7b97\u7b26\u548c\u591a\u6837\u7684\u6570\u636e\u7c7b\u578b\uff0c\u53ef\u4ee5\u8f7b\u6613\u5b8c\u6210\u5404\u79cd\u6570\u636e\u7ed3\u6784\u7684\u6784\u5efa\uff0c\u901a\u8fc7\u6307\u9488\u7c7b\u578b\u66f4\u53ef\u5bf9\u5185\u5b58\u76f4\u63a5\u5bfb\u5740\u4ee5\u53ca\u5bf9\u786c\u4ef6\u8fdb\u884c\u76f4\u63a5\u64cd\u4f5c\u3002

\u6269\u5c55\u8d44\u6599\uff1a
\u5982\u679c\u4e00\u4e2a\u53d8\u91cf\u58f0\u660e\u65f6\u5728\u524d\u9762\u4f7f\u7528 * \u53f7\uff0c\u8868\u660e\u8fd9\u662f\u4e2a\u6307\u9488\u578b\u53d8\u91cf\u3002\u6362\u53e5\u8bdd\u8bf4\uff0c\u8be5\u53d8\u91cf\u5b58\u50a8\u4e00\u4e2a\u5730\u5740\uff0c\u800c *\uff08\u6b64\u5904\u7279\u6307\u5355\u76ee\u8fd0\u7b97\u7b26 * \uff0c\u4e0b\u540c\u3002C\u8bed\u8a00\u4e2d\u53e6\u6709 \u53cc\u76ee\u8fd0\u7b97\u7b26 *\uff09 \u5219\u662f\u53d6\u5185\u5bb9\u64cd\u4f5c\u7b26\uff0c\u610f\u601d\u662f\u53d6\u8fd9\u4e2a\u5185\u5b58\u5730\u5740\u91cc\u5b58\u50a8\u7684\u5185\u5bb9\u3002\u6307\u9488\u662f C \u8bed\u8a00\u533a\u522b\u4e8e\u5176\u4ed6\u540c\u65f6\u4ee3\u9ad8\u7ea7\u8bed\u8a00\u7684\u4e3b\u8981\u7279\u5f81\u4e4b\u4e00\u3002
\u6307\u9488\u4e0d\u4ec5\u53ef\u4ee5\u662f\u53d8\u91cf\u7684\u5730\u5740\uff0c\u8fd8\u53ef\u4ee5\u662f\u6570\u7ec4\u3001\u6570\u7ec4\u5143\u7d20\u3001\u51fd\u6570\u7684\u5730\u5740\u3002\u901a\u8fc7\u6307\u9488\u4f5c\u4e3a\u5f62\u5f0f\u53c2\u6570\u53ef\u4ee5\u5728\u51fd\u6570\u7684\u8c03\u7528\u8fc7\u7a0b\u5f97\u5230\u4e00\u4e2a\u4ee5\u4e0a\u7684\u8fd4\u56de\u503c\uff0c\u4e0d\u540c\u4e8ereturn\uff08z\uff09\u8fd9\u6837\u7684\u4ec5\u80fd\u5f97\u5230\u4e00\u4e2a\u8fd4\u56de\u503c\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-C\u8bed\u8a00

#includefloat rpow(float x,int n){ // \u8fd9\u91cc\u521d\u59cb\u5316\u4e0b float t = 0; // \u5982\u679c\u7b49\u4e8e0\uff0c\u5219\u8fd4\u56de1 if (n==0) { return 1; } if(n>0) t=x*rpow(x,n-1); else t=(1/x)*rpow(x,n+1); return t;}int main(){ float x,t; int n; printf("\u8bf7\u8f93\u5165x\u548cn"); scanf("%f",&x); scanf("%d",&n); t=rpow(x,n); printf("%f",t); return 0;}\u7ed3\u679c\u5982\u4e0b\uff1a

#include<stdio.h>

double power(double x, int n)
{
        double p=1.0;
        while(n>0) {
                p=p*x;
                n--;
        }
        return p;
}

int main(void)
{
        double x;
        int n;
        scanf("%lf %d",&x,&n);
        printf("%lf
",power(x,n));
        return 0;
}


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