python求两数最小公倍数流程图及代码 用python求俩个数的最大公约数和最小公倍数
\u6700\u5c0f\u516c\u500d\u6570python\u4ee3\u7801def gcd(a,b):
if a%b==0:
return b
return gcd(b,a%b)
def lcm(a,b):
return a*b//gcd(a,b)
a,b=map(int,input().split())
print(lcm(a,b))
def fun(num1, num2): # \u5b9a\u4e49\u4e00\u4e2a\u51fd\u6570, \u4e24\u4e2a\u5f62\u53c2
if num1 < num2: # \u5224\u8bfb\u4e24\u4e2a\u6574\u6570\u7684\u5927\u5c0f,\u76ee\u7684\u4e3a\u4e86\u5c06\u5927\u7684\u6570\u4f5c\u4e3a\u9664\u6570,\u5c0f\u7684\u4f5c\u4e3a\u88ab\u9664\u6570
num1, num2 = num2, num1 # \u5982\u679cif\u6761\u4ef6\u6ee1\u8db3,\u5219\u8fdb\u884c\u503c\u7684\u4ea4\u6362
vari1 = num1 * num2 # \u8ba1\u7b97\u51fa\u4e24\u4e2a\u6574\u6570\u7684\u4e58\u79ef,\u65b9\u4fbf\u540e\u9762\u8ba1\u7b97\u6700\u5c0f\u516c\u500d\u6570
vari2 = num1 % num2 # \u5bf92\u4e2a\u6574\u6570\u8fdb\u884c\u53d6\u4f59\u6570
while vari2 != 0: # \u5224\u65ad\u4f59\u6570\u662f\u5426\u4e3a0, \u5982\u679c\u4e0d\u4e3a0,\u5219\u8fdb\u5165\u5faa\u73af
num1 = num2 # \u91cd\u65b0\u8fdb\u884c\u8d4b\u503c,\u8fdb\u884c\u4e0b\u6b21\u8ba1\u7b97
num2 = vari2
vari2 = num1 % num2 # \u5bf9\u91cd\u65b0\u8d4b\u503c\u540e\u7684\u4e24\u4e2a\u6574\u6570\u53d6\u4f59\u6570
# \u76f4\u5230 vari2 \u7b49\u4e8e0,\u5f97\u5230\u6700\u5230\u516c\u7ea6\u6570\u5c31\u9000\u51fa\u5faa\u73af
vari1 /= num2 # \u5f97\u51fa\u6700\u5c0f\u516c\u500d\u6570
print("\u6700\u5927\u516c\u7ea6\u6570\u4e3a:%d" % num2) # \u8f93\u51fa
print("\u6700\u5c0f\u516c\u500d\u6570\u4e3a:%d" % vari1) # \u8f93\u51fa
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\u4f5c\u8005\uff1ayancelyq
\u6765\u6e90\uff1aCSDN
\u539f\u6587\uff1ahttps://blog.csdn.net/yancelyq/article/details/79504364
\u7248\u6743\u58f0\u660e\uff1a\u672c\u6587\u4e3a\u535a\u4e3b\u539f\u521b\u6587\u7ae0\uff0c\u8f6c\u8f7d\u8bf7\u9644\u4e0a\u535a\u6587\u94fe\u63a5\uff01
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