五个5,中间用加减乘除,只能用一次,最后等于20,怎么算

5\u4e2a5 \u4e2d\u95f4\u7528\u52a0\u51cf\u4e58\u9664\u5404\u4e00\u6b21 \u600e\u6837\u624d\u80fd\u7b97\u5230\u7b49\u4e8e20

5\u00d75-(5\u00f75)\u00d75=20

\u3010\u5b66\u4e60\u5b9d\u5178\u3011\u56e2\u961f\u4e3a\u60a8\u7b54\u9898\u3002\u6709\u4e0d\u660e\u767d\u7684\u53ef\u4ee5\u8ffd\u95ee\uff01

7
\u548c
19
\u7528\u4e86\u4e00\u6b21\u6839\u53f7\uff0c\u5176\u4f59\u7684\u90fd\u53ea\u7528\u4e86
+\uff0c-\uff0c\u00d7\uff0c\u00f7\uff0c()
1
=
(4-4)\u00d74+4\u00f74
2
=
(4+4)\u00f74+4-4
3
=
4-4+4-4\u00f74
4
=
4-4+4-4+4
5
=
4-4+4+4\u00f74
6
=
4+4\u00f74+4\u00f74
7
=
4\u00f74+4+4-\u221a4
\uff1f\uff1f\uff1f
8
=
4+4+(4-4)\u00d74
9
=
(4+4\u00d74)\u00f74+4
10
=
(4+4)\u00f74+4+4
11
=
4+4+4-4\u00f74
12
=
4+4+4+4-4
13
=
4\u00d74-4+4\u00f74
14
=
4\u00d74-(4+4)\u00f74
15
=
(4\u00d74\u00d74-4)\u00f74
16
=
(4+4\u00f74)\u00d74-4
17
=
(4\u00d74\u00d74+4)\u00f74
18
=
4\u00d74+(4+4)\u00f74
19
=
4\u00d74+\u221a4+4\u00f74
\uff1f\uff1f\uff1f
20
=
4+4+4+4+4
\u6709\u4e9b\u6570\u4e0d\u6b62\u4e00\u79cd\u7b97\u6cd5\uff0c\u6bd4\u5982\uff1a4,
20
\u7b49\uff0c\u8fd9\u91cc\u4e0d\u518d\u5217\u4e3e\u4e86

5*5-5=20
没有说必须全用

-(5÷5)×5+5×5=20

(5÷5)×5+5×5=20 全用了哈

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