如图,长方形ABCD的面积为48,E,F分别在BC,CD上,并且BE=FD=2,求△AFE的面积 如图:长方形ABCD中,E、F分别在BC、CD上,BE=11...

\u5982\u56fe\uff0c\u957f\u65b9\u5f62ABCD\u7684\u9762\u79ef\u4e3a48\uff0eE\uff0cF\u5206\u522b\u5728BC\uff0cCD\u4e0a\uff0c\u5e76\u4e14BE=FD=2\uff0c\u90a3\u4e48\u25b3AEF\u7684\u9762\u79ef\u662f______

\u8bbe\u957f\u4e3ax\uff0c\u5bbd\u4e3ay\uff0c\u7531\u9898\u610f\u53ef\u77e5\u25b3AEF\u7684\u9762\u79ef=S\u25a1ABCD-S\u25b3ABE-S\u25b3ECF-S\u25b3ADF\uff0c=48-x-y-\uff08x-2\uff09\uff08y-2\uff09\u00f72\uff0c=48-xy\u00f72-2\uff0c\u2235\u957f\u65b9\u5f62ABCD\u7684\u9762\u79ef\u4e3a48\uff0c\u5373xy=48\uff0c\u2234\u25b3AEF\u7684\u9762\u79ef\u4e3a48-24-2=22\uff0e\u6545\u7b54\u6848\u4e3a\uff1a22\uff0e

\u8bbeAB=a\uff0cAD=b\uff0c\u5219CE=b-11\uff0cCF=a-11\uff0c\u56e0\u4e3a\u77e9\u5f62ABCD\u7684\u9762\u79ef=\u4e09\u89d2\u5f62ABE\u7684\u9762\u79ef+\u4e09\u89d2\u5f62CEF\u7684\u9762\u79ef+\u4e09\u89d2\u5f62AEF\u7684\u9762\u79ef+\u4e09\u89d2\u5f62ADF\u7684\u9762\u79ef\uff0c\u6240\u4ee5ab=1/2\u00d711a+1/2\uff08b-11\uff09\uff08a-3\uff09+17+1/2\u00d73b\uff0c\u6574\u7406\u5f97ab=67\uff0c\u6240\u4ee5\u77e9\u5f62ABCD\u7684\u9762\u79ef=ab=67

解:设长为x,宽为y,由题意可知△AEF的面积=S□ABCD-S△ABE-S△ECF-S△ADF,
=48-x-y-(x-2)(y-2)÷2,
=48-xy÷2-2,
∵长方形ABCD的面积为48,即xy=48,
∴△AEF的面积为48-24-2=22.
故答案为:22.

此题可设长为x,宽为y,△AEF的面积可用长方形的面积减去3个小三角形的面积即可求得答案.

解:设长为x,宽为y,由题意可知△AEF的面积=S□ABCD-S△ABE-S△ECF-S△ADF,
=48-2*x-(y-2)*(x-2)-y*(x-2)
=48-xy÷8-8,
∵长方形A0CD的面积为48,即xy=48,
∴△AEF的面积为48-84-8=88.
故答案为:88.

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