初一数学
\u521d\u4e00\u6570\u5b66\u5bf9\u6b63\u591a\u8fb9\u5f62\uff0c\u6bcf\u4e2a\u5185\u89d2\u5747\u76f8\u7b49\uff0c\u5219\u5176\u76f8\u90bb\u7684\u5916\u89d2\u4e5f\u76f8\u7b49\u3002
\u8bbe\u5916\u89d2\u4e3ax\uff0c\u5219\u5185\u89d2\u4e3a3x+20\uff0c\u5185\u5916\u89d2\u4e4b\u548c\u4e3a180\u5ea6\uff0c\u6709\u7b49\u5f0f\uff1ax+3x+20=180
\u89e3\u5f97x=40\uff0c\u5219\u5185\u89d2\u4e3a180-40=140\u3002
\u8fb9\u6570\u4e3a360/\uff08180-2*140/2\uff09\u5373\u4e3a9\uff0c\u8be5\u6b63\u591a\u8fb9\u5f62\u4e3a9\u8fb9\u5f62\u3002
\u5185\u89d2\u548c=\uff089-2\uff09*180=1260\u5ea6
1\u30020.1.2
2.1/2<X<4
2.X>-3/4
4.a<=-2
5.-2,-1,0,1
2.(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)=?
3.已知,x-y=5,xy=11/4.求(1).x^2+y^2.(2).x+y
答案:1.m=正负12.
2.(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^1-1)(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)
=(2^64-1)(2^64+1)
=2^128-1
3.(1). x-y=5
(x-y)^2=5^2
x^2-2xy+y^2=25
x^2-2*(11/4)+y^2=25
x^2+y^2=61/2
(2).(x+y)^2
=x^2+y^2+2xy
=61/2+11/2
=36
(x+y)^2=36
(x+y)^2=6^2
x+y=正负6
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