python求1234可以组成多少个互不相同且无重复数字三位数的三位数。
lista=[]listb=[]
listx=[str(j) for j in range(5,10)]
listx.insert(0,"0")
'''(Tab)处缩进代码'''
for j in range(123, 433):
#确定范围123～432
(Tab)if str(j)[1] not in listx and str(j)[2] not in listx:
#排除三位数中各数位上数字是0、5、6、7、8、9
(Tab)(Tab)lista.append(str(j))
for jj in lista:
(Tab)if jj[0]!=jj[1] and jj[0]!=jj[2] and jj[1]!=jj[2]:
#去除任意两个数位上有相同的数字
(Tab)(Tab)listb.append(int(jj))
print(listb)
'''运行效果
[123, 124, 132, 134, 142, 143, 213, 214, 231, 234, 241, 243, 312, 314, 321, 324, 341, 342, 412, 413, 421, 423, 431, 432]
'''
绛旓細python鏈夊洓涓暟瀛1234,鑳界粍鎴24涓笉鍚湁閲嶅鏁板瓧鐨勫洓浣嶆暟锛鏈灏忕殑鏄1234锛屾渶澶х殑鏄4321.
绛旓細鍙互缁勬垚123锛124锛132锛134锛142锛143锛213锛214锛231锛234锛241锛243锛312锛314锛321锛324锛341锛342锛412锛413锛421锛423锛431锛432鍏24涓笉閲嶅鐨勪笁浣嶆暟銆
绛旓細杩欎釜鏄竴涓帓鍒楅棶棰樸鍙互缁勬垚鐨勪笁浣嶆暟缁勫悎涓4*3*2=24绉嶃傚垎鍒负123銆124銆132銆134銆142銆143銆213銆214銆231銆234銆241銆243銆312銆314銆321銆324銆341銆342銆412銆413銆421銆423銆431銆432銆
绛旓細鍏缁勬垚18涓笁浣嶆暟锛屽垎鍒槸123锛132锛124锛134锛142锛143锛231锛234锛213,214锛243锛241锛312锛314锛321锛324锛342锛341锛412锛413锛423锛421锛432锛431
绛旓細a.append(i)i = m // 10 % 10 a.append(i)i = m // 100 % 10 a.append(i)i = m // 1000 % 10 a.append(i)if(1 in a) and (2 in a) and (3 in a) and (4 in a):for x in range(2,m // 2 + 1):if m % x == 0:break else:if x == m // 2:pr...
绛旓細浣犳槸鎯宠璁＄畻1234鐨勪簩杩涘埗琛ㄧず銆鍙互浣跨敤Python鐨鏁存暟闄ゆ硶鍜屽彇浣欒繍绠楁潵瀹炵幇锛歯um = 1234 result = ""while num > 0:result = str(num % 2) + result num //= 2 print(result)杈撳嚭缁撴灉涓猴細10011010010锛屽嵆1234鐨勪簩杩涘埗琛ㄧず銆
绛旓細璇峰弬鑰冿細from itertools import def permu(i):s=str(i)l=[]for x in permutations(s, len(s)):l.append(int("".join(x)))return(l)a=1235 print permu(a)
绛旓細30-3**2=21 鈥12鈥+鈥34鈥=鈥1234鈥13//5+3=5 13%5+3=5 (-7+2)*(-4)=20
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绛旓細鍐欏湪鏈鍚: 涓婇潰浠ｇ爜鍙互婊¤冻棰樹富闇姹,浣嗘槸濡傛灉灏嗕笂闈㈢殑input鍑芥暟涓彁绀烘ф枃瀛椾互鍙妏rint鍑芥暟涓緭鍑虹殑鏂囧瓧淇敼涓涓,鍙兘閫傜敤鎬у氨鏇村ソ涓浜; 姣旀柟璇翠綘瑕佸垽鏂殑鏄1234,鍒欎綘鏈鍚庢墦鍗扮殑鍐呭鏄"鍗曡瘝1234xxxx"鐪嬬潃灏变笉澶ソ,鍥犱负1234涓嶆槸鍗曡瘝,铏界劧缁撴灉鏄纭殑. 浣嗚繕鏄湅棰樹富鎬庝箞鐢ㄤ簡,濡傛灉鍙槸鍗曠函鐨勫幓瀵瑰崟璇嶅仛...
