unfortunate+adv
答:if you see her, you’re extremely fortunate. 如果你见到她(雌性鬼鱼),你真是万分幸运。Unfortunate a. 不幸的 fortunately adv. 幸运地 10. depart for…=leave for…/go away to… 动身前往……when the tanks of fish were completely sold out, Happy usually departed for anothe...
答:副词 adv.1.向前 His hat is on wrong side to.他的帽子前后戴歪了。2.(门窗等)关上;虚掩着 The door was blown to.风吹把门关上了。3.开始;着手 We turned to with a will.我们开始努力干。4.在附近 We were close to when it happened.事情发生时我们正在附近。5.苏醒过来 after he...
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庾佩14789368007:
best most 区别likebest We need cows most .什么时候用best,什么时候用most -
45993宰才
:[答案] KK:[] DJ:[] a.(good和well的最高级) 1.最好的;最熟练的;道德最高尚的 I think John's plan is best. 我认为约翰的方案最好. ... It took the best part of a day to get there. 花了大半天时间才到达那里. ad.(well的最高级) 1.最好地;最适当地;最有效地 I think ...
庾佩14789368007:
喷瓜是葫芦科的一种植物,其性别决定由基因决定.决定性别的是三个等位基因,即aD、a+、ad;其显隐关系为aD对a+为显性,a+对ad为显性.aD基因决定发... -
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:[答案] (1)aD对a+、ad为显性,a+对ad为显性,则当aD存在时植株表现为雄性,当基因型为adad时植株表现为雌性,当基因型为a+a+、a+ad时植株表现为雌雄同株,如果雄性植株为纯合体,则它的基因型即为aDaD,这需要此植株的父本和母本各提供一...
庾佩14789368007:
在三角形ABC中,AB=2,AC=3,D是BC的中点,则向量AD乘以向量BC=? -
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:[答案] =2.5首先建立直角坐标系以A为原点AC设在x轴上,则B轨迹为以A为原点半径为2的圆方程为x2+y2=4.设B为(a,b)则B满足方程.此时D的坐标为{(3+a)/2,b/2},向量AD同D坐标,向量BC为(3-a,-b).向量AD乘BC为(3+a)*(3-a)/...
庾佩14789368007:
(2014•盘锦三模)如图,▱ABCD的周长为16cm,AC、BD交于点O,且AD>CD,过O作OM⊥AC,交AD于点M,则△CDM的周长为______cm. -
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:[答案] ∵四边形ABCD是平行四边形, ∴OA=OC, ∵OM⊥AC, ∴AM=CM, ∴△CDM的周长为:CD+DM+CM=CD+DM+AM=CD+AD, ∵▱ABCD的周长为16cm, ∴CD+AD=8cm, ∴△CDM的周长为8cm. 故答案为:8.
庾佩14789368007:
《雷蒙·斯尼奇的不幸历险》(Lemony Snicket's A Series of Unfortunate Event)的英文影评 -
45993宰才
: In Brief: Welcome to the wicked world of Lemony Snicket, free of a troublesome happy ending and devoid of any sort of joy. It's a world where one bad thing happens after another, a veritable series of unfortunate events. And it's wonderfully executed...
庾佩14789368007:
如图在三角形abc中角c90度角b45度ab平分角bac且交bc于点d求证ab=ac+cd -
45993宰才
:[答案] 证明:过D作DE⊥AB于E, ∵AD平分∠BAC,∴∠DAC=∠DAE, ∵∠AED=∠C=90°,AD=AD, ∴ΔADC≌ΔADE(AAS), ∴AE=AC,CD=DE, ∵ ΔABC是等腰直角三角形,∴∠B=45°, ∴ΔBDE是等腰直角三角形, ∴DE=BE, ∴AB=AE+BE=AC+CD.
庾佩14789368007:
正方形abcd,ab边上有一点e,ae=3,eb=1在ac上有点p使ep+bp为最短ep+bp为?ac为abcd对角线,p图上没有. -
45993宰才
:[答案] 连接BD交AB于P,则P为所求(即PE+PB最小). 连接DE,AB=AE+BE=4, ∵ABCD是正方形,∴∠DAE=90°,AD=AB=4, ∴DE=√(AE²+AD²)=5, ∴PE+PB最小=5.
庾佩14789368007:
如图,三角形ABC中∠B=60°AD,CE分别是∠BAC,∠ACB的角平分线.E点在AB上,D点在BC上在.求证AE+CD=AC. -
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:[答案] ∵∠ABC=60° ∴∠BAC+∠BCA=120° ∵AD、CE是∠BAC、∠BCA的角平分线 ∴∠OAC+∠OCA=60° ∴∠AOC=120° ∴∠AOE=∠COD=60°(对顶角,圆周角=360°) 作∠AOC的角平分线OM交AC于M 则∠AOE=∠AOM=60°∠COM=...
庾佩14789368007:
在三角形ABC中 角B=40度,BD平分角B交AC于点D,且BD+AD=BC,求证AB=AC -
45993宰才
:[答案] 证明: 在BC上截取BE=BD,连接DE ∵BD+AD=BC BE+CE=BC ∴AD=CE ∵BD平分∠ABC ∴AB:BC=AD:CD ∴AB:BC=CE:CD 又∵∠ACB=∠ECD【公共角】 ∴⊿ACB∽⊿ECD【对应边成比例夹角相等】 ∴∠A=∠DEC ∵∠B=40º ∴∠DBE...