python怎么取各个数位的数 python程序设计求一个数各数位上数字阶乘和
\u8fd9\u6bb5python\u6211\u5df2\u7ecf\u63d0\u53d6\u5404\u4e2a\u4f4d\u7f6e\u7684\u6570\u5b57\uff0c\u600e\u4e48\u5f04\u6210\u5404\u4e2a\u4f4d\u7f6e\u76f8\u52a0\u4e4b\u548c#\u8fd9\u79cd\u9898\u6ca1\u5fc5\u8981\u9012\u5f52sum = 0n = input()while True: if n/10 != 0: sum += n%10 n = n/10 else: sum += n breakprint sum###\u6216\u8005\u4e0d\u7528\u9664\u6cd5\u548c\u6c42\u4f59sum = 0for i in str(input("Enter a number: ")): sum += int(i) print sum
def getDigits(data): digits = [] while data / 10: digits.append(data % 10) data /= 10 digits.append(data) print digits return digitsdef sumNfabric(data): digits = getDigits(data) digits.sort() print digits sumOfDigitsFabric = 0 fabric = 1 for i in xrange(1, digits[-1] + 1): fabric *= i if i in digits: sumOfDigitsFabric += fabric print sumOfDigitsFabric return sumOfDigitsFabricprint sumNfabric(31245)
a = 12345 取个位 : b = (a / 1) % 10 = a % 10 取十位: b = (a / 10) % 10 取百位: b = (a / 100) % 10 以此类推。假设输入的数是n, n不为0 n=某数 while n>0。 (n,r) = divmod(n,10) print r 其中(n,r) = divmod(n,10) r是个位数。n是其它高位数,divmod包含 除和求余数.。或者用 [int(i) for i in str(n)] str(n) 把数变成字符串 int(i) 把字符串里的字母变成数字。
假设输入的数是n, n不为0
n=某数
while n>0:
(n,r) = divmod(n,10)
print r
其中(n,r) = divmod(n,10) r是个位数，n是其它高位数，divmod包含 除和求余数。
或者用
[int(i) for i in str(n)]
str(n) 把数变成字符串
int(i) 把字符串里的字母变成数字
a = 12345
取个位 : b = (a / 1) % 10 = a % 10
取十位： b = (a / 10) % 10
取百位： b = (a / 100) % 10
以此类推
思路是，除10取余
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