Python如何判断录入非数字? Python3 先判断输入的是不是数字,若不是,则输出“输入...

python\u4e2d\u5982\u4f55\u5224\u65ad\u8f93\u5165\u53c2\u6570\u662f\u5426\u4e3a\u6570\u5b57?

num=9
type(num)
type()\u53ef\u4ee5\u83b7\u5f97num\u7684\u7c7b\u578b
\u5224\u65ad\u53ef\u4ee5\u7528isinstance(num, int)\u6765\u5224\u65ad,\u7b26\u5408\u5219\u4e3atrue,\u53cd\u4e4b,false

def askNumber():
question='\u8bf7\u8f93\u5165\u4e00\u4e2a\u6570\u5b57'
rep=False
while not rep:
try:
rep =int(input(question))
except:
rep=False
question ='\u8f93\u5165\u65e0\u6548\uff0c\u8bf7\u8f93\u5165\u4e00\u4e2a\u6570\u5b57'
return rep
num=askNumber()
if num >0:
print('\u8f93\u5165\u7684\u662f\u6b63\u6570')
pass
elif num==0:
pass
else:
pass

用isdigit() 函数判断。可以这样写:if not num1.isdigit() #即:如果num1不是数字。

if num1 in ['1234'] and num2 in ['1234']



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