（6分）在标准状况下，将224L HCl气体溶于635mL水（ρ＝1.00g·cm － 3 ）中，所得盐酸的密度为1.18g·c
\u5316\u5b66\uff1a\u5728\u6807\u51c6\u72b6\u51b5\u4e0b\uff0c\u5c06224L HCl\u6c14\u4f53\u6eb6\u4e8e635mL\u6c34\u4e2d\uff0c\u6240\u5f97\u76d0\u9178\u7684\u5bc6\u5ea6\u4e3a1.18g/cm3\uff0c\u53d6\u6b64\u76d0\u917810ML\uff0c\u89e3\uff1a\u7531\u4e8e\u6eb6\u6db2\u7684\u8d28\u91cf\u7b49\u4e8e\u6eb6\u8d28\u52a0\u6eb6\u5242\uff0c\u800cHCl\u6709224/22.4=10mol\uff0c
\u2234m\uff08HCl\uff09=n\uff08HCl\uff09\u00b7M\uff08HCl\uff09=10\u00b736.5=365g\uff0cm\uff08H20\uff09=635g\uff08\u6c34\u7684\u5bc6\u5ea6\u662f1g/cm3\uff09
\u2234\u76d0\u914d\u8d28\u91cfm\u4e3am\uff08HCl\uff09+m\uff08H20\uff09=1000g\uff0c\u5176\u4e2dHCl\u7684\u8d28\u91cf\u5206\u6570\u4e3a36.5%\u3002
\u800c10mL\u76d0\u9178\u7684\u8d28\u91cf\u4e3a1.18\u00d710=11.8g\uff0c\u5176\u4e2d\u542bHCl11.8g\u00d736.5%=4.307g\u3002
\u5219\u6b64\u65f6n\uff08HCl\uff09=m\uff08HCl\uff09/M\uff08HCl\uff09=4.307g\u00f736.5g/mol=0.118mol
\u6240\u4ee5\u57281.45L\u7684\u6eb6\u6db2\u4e2d\uff0c\u91cf\u6d53\u5ea6\u4e3a
c=n/V=0.118mol/1.45L=0.08mol/L\u3002
\u5373\u5b83\u7684\u91cf\u6d53\u5ea6\u7ea6\u4e3a0.08mol/L
HCl\u7684\u7269\u8d28\u7684\u91cf 224/22.4=10(mol)
HCl\u7684\u8d28\u91cf10*36.5\uff1d365\uff08g\uff09
\u6eb6\u6db2\u7684\u8d28\u91cf365+635*1\uff1d1000\uff08g\uff09
HCl\u7684\u8d28\u91cf\u5206\u6570365/1000\u00d7100\uff05\uff1d36.5\uff05
c\uff08HCl\uff09\uff1d1000*1.19*36.5%/36.5=11.9(mo/L)
\u7a00\u91ca\u540e\u6d53\u5ea6 11.9*10\uff1d1190c \uff0cc\uff1d0.1\uff08mol/L\uff09
| 36.5％；11.8mol·L － 1 ；0. 118mol·L － 1 （6分） 绛旓細鍥犱负鍓嶅悗鐨勪綋绉彲鑳芥湁鍙樺寲锛屾墍浠ヤ笉鑳界洿鎺ョ敤 224/22.4/0.33= 30.3mol/L 棰樻剰鍙煡锛22.4L姘ㄦ皵鐨勭墿璐ㄧ殑閲忎负 10mol 璐ㄩ噺涓10x17=170g锛0.33L姘寸殑璐ㄩ噺涓330g 婧舵恫鐨勮川閲忎负 170+330=500g 鎵浠ユ憾娑茬殑浣撶Н涓簃/p=500/0.8= 625ml=0.625L 鎵浠ョ墿璐ㄧ殑閲忔祿搴︿负 10/0.625=16mol/L 鎵浠ワ紝锛1... 绛旓細锛1锛12.0 mol路 L -1 锛2锛26.9 L33.6 g 锛1锛塶(HCl)="224" L/22.4 L路 mol -1 ="10.0" molm(HCl婧舵恫)="635" g+10.0 mol脳36.5 g路 mol -1 =1.00脳10 3 gc(HCl)= =" 12.0 " mol 路 L -1 锛2锛塇Cl+NaHCO 3 ===NaCl+H 2 O+CO 2 鈫1 mol ... 绛旓細n=224/22.4=10mol 婧舵恫浣撶Н涓篤 V=m梅瀵嗗害 m=婧惰川+婧跺墏=10*36.5+635*1.0=1000g c=n/V=10梅[锛1000梅1.18锛*10^-3]=11.8mol/L 鐢ㄥ瘑搴︾畻鍑烘潵鐨勪綋绉崟浣嶆槸ml 鎹㈢畻鎴怢 鎵浠ヤ箻浠10^-3 绛旓細(1)36.5%銆11.8 mol路L 锛1 銆(2)1 mol路L 锛1 (3)2.6銆(4)5.85 (1)n(HCl)锛 锛10 mol锛宮(HCl)锛10 mol脳36.5 g路mol 锛1 锛365 g锛岀洂閰哥殑璐ㄩ噺鍒嗘暟w锛 脳100%锛36.5%锛宑(HCl)锛 锛 锛11.8 mol路L 锛1 銆(2)鏍规嵁c(娴)路V(娴)锛漜(绋)路V(绋... 绛旓細鈶爊HCl=10mol锛宮HCl=365g mH2O=635g锛宮婧舵恫=1000g锛岄偅涔堢洂閰哥殑鎬讳綋绉 V=1000/1.2mL鍚1/1.2L c=10/锛1/1.2锛=12mol/L 鈶100mL鐨勮瘽nHCl=1.2mol NaHCO3+HCl=NaCl+H2O+CO2鈫 鐭ラ亾浜咰O2鏄1.2mol锛屼綋绉槸1.2脳22.4=26.88L 鈶O2鏄1.2mol 2Na2O2+2CO2=2Na2CO3+O2 2涓狢O2璧... 绛旓細HCl鐨勭墿璐ㄧ殑閲=224/22.4=10mol HCl鐨勮川閲=10*36.5=365鍏 婧舵恫鐨勮川閲365+835=1200鍏 婧舵恫鐨勪綋绉=1200/1.2=1000cm3=1L 鎵寰楃洂閰哥殑鐗╄川鐨勯噺娴撳害涓篲_10/1=10mol/L___. 绛旓細鍦ㄦ爣鍑嗙姸鍐典笅锛1mol浠讳綍姘斾綋閮芥槸22.4l銆傛嵁姝ゅ彲鐭ユ爣鍑嗙姸鍐典笅11.2l hcl灏辨槸11.2/22.4=0.5mol 蹇界暐姘斾綋婧朵簬姘村紩璧风殑姘村井閲忕殑浣撶Н鍙樺寲锛岀墿璐ㄧ殑閲忕殑娴撳害=0.5mol/0.5l=1mol/l銆 绛旓細1.224HCL鍗10molHCl m(HCl)=10mol*36.5g/mol=365g 婧舵恫鎬昏川閲365g+635g=1000g 鍗847.46mL=0.84746L C(HCL)==10mol/0.84746L=11.8mol/L 鎵浠ユ憾浜庢按婧舵恫鐗╄川鐨勯噺娴撳害涓11.8mol/L 10.0ml涓湁HCl 0.118mol C(绋閲)=0.118mol/1.45L=0.0813mol/L 2.纰抽吀閽犵墿璐ㄧ殑閲忎负0.0026... 绛旓細鍡紝鏀硅繃鏉ヤ簡 锛1锛塶(HCl) = 224/22.4 = 10mol m(HCl) = 10*36.5 = 365g 鎵浠ョ洂閰哥殑璐ㄩ噺鍒嗘暟 = 365/(365+635) = 36.5 婧舵恫浣撶Н = (365+635)/1.2 = 833mL = 0.833L 鎵浠ョ洂閰哥殑鐗╄川鐨勯噺娴撳害 = 10/0.833 = 12mol/L 锛2锛夌█閲婂嶆暟 = 2/0.01 = 200 鎵浠ョ█閲婂悗鐗╄川鐨... 绛旓細224HCL鍗10molHCl m(HCl)=10mol*36.5g/mol=365g 婧舵恫鎬昏川閲365g+635g=1000g 鍗847.46mL=0.84746L C(HCL)==10mol/0.84746L=11.8mol/L 本站交流只代表网友个人观点，与本站立场无关 |
