C语言求逆序数 用c语言编程 求一个数的逆序数。(如 1234 的逆序数是 ...

\u6c42\u9006\u5e8f\u6570c\u8bed\u8a00\u7a0b\u5e8f

#include
main()
{
int a,b1,b2,b3,c;
printf("\u8f93\u5165\u4e00\u4e2a\u4e09\u4f4d\u6570");
scanf("%d",&a);
b1=a/100;
b2=(a-100*b1)/10;
b3=a-100*b1-10*b2;
c=100*b3+10*b2+b1;
printf("c=%d\n",c);
}
\u697c\u4e3b\u81ea\u5df1\u591a\u7f16\u7f16\uff0c\u7ecf\u9a8c\u51fa\u6765\u4e86\u5c31\u4f1a\u4e86
\u8fd8\u662f\u81ea\u5df1\u52aa\u529b\u54c8~

#include
#include
#include
void main()
{
char array[10];
int k;
scanf("%d", &k);
itoa(k, array, 10);
k = strlen(array);
while(k>=0)
{
printf("%c", array[k-1]);
k--;
}
//\u5982\u679c\u60f3\u9006\u5e8f\u8f93\u51fa\u6570\u662f\u6574\u578b\u6570\uff0c\u53ef\u4ee5\u7528atoi()\u51fd\u6570\u8f6c\u6362\u56de\u6765
}

#include <stdio.h>
int main()
{
int n,m=0;
scanf("%d",&n);
while(n)
{m=m*10+n%10;n/=10;}
printf("%d",m);
return 0;
}

运行示例:

请自行对照。



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