初二数学,解方程:

\u521d\u4e8c\u6570\u5b66\u89e3\u65b9\u7a0b

\u662f\u51e0\u4e2a\u9898\u5417\uff1f
\uff081\uff09x²-2x=9999 x² -2x+1=10000=(100)² (x-1)²=(100)² x=101\u6216-99
(2)\u540c\u65f6\u6269\u59273\u500d x² -2x+2=0 x\u65e0\u89e3
\uff083\uff09\uff082-\u221a3\uff09x²-2\u221a3x=2+\u221a3 [ (2-\u221a3 )x-\u221a3-2](x+1)=0 x=-1 \u6216x=1
(4)(\u221a5-\u221a2)x=3\u221a2 x=2+\u221a10
(5)\u221a2x-\u221a3y=1 \u2460 \u221a3x-\u221a2y=\u221a2 \u2461
\u2460\u00d7\u221a3\u5f97 \u221a6x-3y=\u221a3 \u2462
\u2461 \u00d7\u221a2\u5f97 \u221a6x-2y=2 \u2463
\u2463-\u2462 y=2-\u221a3 \u2464
\u628a\u2464\u4ee3\u5165\u2463\u5f97 \u221a6x-2\u00d7( 2-\u221a3)=2 \u5373 x=\u221a6-\u221a2

\u4eb2\uff0c\u8fd9\u79cd\u9898\u5728\u6c42\u89e3\u7b54\u4e0a\u4e00\u641c\u5c31\u51fa\u6765\uff0c\u5927\u5bb6\u90fd\u5728\u7528\uff0c\u8d76\u7d27\u6233\u8fdb\u53bb\u5427\uff0c\u4e0d\u7136\u5c31out\u4e86
\u4ee5\u540e\u6709\u4ec0\u4e48\u4e0d\u4f1a\u7684\u9898\uff0c\u5feb\u53bb\u201c\u6c42\u89e3\u7b54\u201d\u5427\uff0c\u4e0a\u9762\u9898\u5e93\u91cf\u8d85\u5927\uff0c\u57fa\u672c\u4e0a\u4e0d\u4f1a\u7684\u9898\u76ee\u90fd\u641c\u7684\u5230\uff0c\u6570\u5b66\u7269\u7406\u5316\u5b66\u90fd\u6709\uff0c\u5c24\u5176\u662f\u5386\u5e74\u4e2d\u8003\u9898\uff0c\u6a21\u62df\u9898\uff0c\u8bfe\u672c\u4e0a\u9898\uff0c\u800c\u4e14\u7b54\u6848\u975e\u5e38\u8be6\u7ec6\uff0c\u6ca1\u6709\u539f\u9898\u4e5f\u6709\u540c\u7c7b\u9898\uff0c\u754c\u9762\u5f88\u79d1\u5b66\u54e6\uff0c\u52a0\u6cb9\u5427
\u8fd8\u6709\u6c42\u89e3\u7b54\u9ad8\u4e2d\u7248\u6700\u8fd1\u4e5f\u4e0a\u7ebf\u4e86\uff0c\u5404\u79cd\u9ad8\u4e2d\u6570\u7406\u5316\u9898\u76ee\u7b49\u4f60\u6765\u641c\u89e3\u96be\u9898\u5c31\u53bb\u3010\u6c42\u89e3\u7b54\u3011\uff0c\u521d\u4e2d\u6570\u7406\u5316\u751f\u7269\u9898\uff0c\u9ad8\u4e2d\u6570\u7406\u5316\u751f\u7269\u9898\uff0c\u5565\u90fd\u6709

解:
1/(x²+x)+1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)=4/21
1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)=4/21
1/x - 1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)=4/21
1/x-1/(x+4)=4/21
4/(x²+4x)=4/21
x²+4x=21
x²+4x-21=0
(x+7)(x-3)=0
x1=-7 x2=3

分母先因式分解:
1/[x(x+1)]+1/[(x+1)(x+2)]+1/[(x+2)(x+3)]+1/[(x+3)(x+4)]=4/21
再拆分:
1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)=4/21
合并:1/x-1/(x+4)=4/21
去分母:21(x+4-x)=4x(x+4)
x^2+4x-21=0
(x-3)(x+7)=0
得x=3或x=-7
经检验,只有x=-7为原方程的解。

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