x2十2x一3=0用十字相乘法详细过程? 2x²+x-3=0 用十字相乘法,要详细过程。
x2\uff0d2x\uff0d3\uff1d0\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u600e\u6837\u7b97?x2\uff0d2x\uff0d3\uff1d0
\uff08x-3)(x+1)=0
x1=3,x2=-1
\u89e3
2 3
1 -1
\u6240\u4ee5 \u539f\u65b9\u7a0b\u5373\uff1a
(2x+3)(x-1)=0
\u5373 2x+3=0\u6216x-1=0
\u89e3\u5f97 x=-3/2\u62161
过程解析如图所示,希望能够解决你心中的困惑
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