VB判断奇偶性编程? 判断奇偶数的vb程序段

\u7528vb\u7f16\u7a0b \u4efb\u610f\u8f93\u5165\u4e00\u6574\u6570\uff0c\u5224\u65ad\u5176\u5947\u5076\u6027\u3002

Dim A
Do
A = InputBox("\u8bf7\u8f93\u5165\u4e00\u4e2a\u6574\u6570")
Loop While IsNumeric(A) = False Or Val(A) Int(A)
If A Mod 2 = 1 Then
MsgBox A & "\u662f\u5947\u6570"
Else
MsgBox A & "\u662f\u5076\u6570"
End If

vb\u7a0b\u5e8f\u6bb5\u5982\u4e0b\uff1a
Private Sub Command1_Clicko
If Val\uff08Text1.Text\uff09Mod 2 = 1 And Val\uff08Text1.Text\uff09= Int\uff08Val\uff08Text1.Text\uff09Then
Label1.Caption="\u8fd9\u662f\u5947\u6570"
Else
If Val\uff08Text1.Text\uff09Mod 2= 0 And Val\uff08Text1.Text\uff09= Int\uff08Val\uff08Text1.Text\uff09\uff09Then
Label1.Caption ="\u8fd9\u662f\u5076\u6570"
Else
Label1.Caption ="\u975e\u5947\u975e\u5076"
End If
End If
End Sub

\u6269\u5c55\u8d44\u6599\uff1a
\u5224\u65ad\u5947\u5076\u6570\u65f6\uff0c\u4e3b\u8981\u662f\u4f7f\u7528\u8fd0\u7b97\u7b26-Mod\u548cif\u8bed\u53e5\uff0cMod\u53ef\u4ee5\u5bf9\u4e00\u4e2a\u6570\u53d6\u4f59\u6570\u3002\u4f8b\u598210/3= 3....11\u521910 Mod 3=1\uff0c\u6240\u4ee5\u5982\u679c\u4efb\u610f\u4e00\u4e2a\u6570n Mod 2=1\u8fd9\u4e2a\u6570\u5c31\u662f\u5947\u6570\u3002
If\u8bed\u53e5\u683c\u5f0f\uff1a\u5982\u679c\u6761\u4ef61\u6210\u7acb \u505a\u4ee3\u78011 \u5426\u5219 \u505a\u4ee3\u78012 \u7ed3\u675f
\u4ee3\u7801\u683c\u5f0f\uff1a
IfA1 Then
\u8bed\u53e51
Else
\u8bed\u53e52
End if

算法分析: 根据题目判断奇偶性,可以用mod函数,n mod 2 如果是1 则是奇数,如果是0则是偶数。程序:Private Sub Command1_Click()
dim n as integern=inputbox("输入需要判断的数据:")If n Mod 2 = 0 Then
Print "你输入的数字是偶数。"
Else
Print "你输入的数字是奇数。"
End IfEnd Sub唉···回答这个问题真不好意思。

Private Sub Command1_Click()
Dim a%
a = InputBox("请输入你要判断的数字")
If a Mod 2 = 0 Then
Print "你输入的数字" & a & "是偶数."
Else
Print "你输入的数字" & a & "是奇数."
End If
End Sub

dim a as Integer,b as Integera=text1.textb=text2.textmsgbox iif((a mod 2)=0,"是偶数","是奇数")

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