实验室需要配制0.2mol/L氢氧化钠溶液100mL,现有4mol/L的浓氢氧化钠溶液，计算所需浓氢氧化钠溶液的体积 实验室需要0.1mol/l的氢氧化钠溶液100ml,现有2m...
\u5b9e\u9a8c\u5ba4\u9700\u8981\u914d\u52360.1mol/LNaOH\u6eb6\u6db2100mL\uff0c\u73b0\u67092mol/LNaOH\u6eb6\u6db2\uff0e\uff081\uff09\u8ba1\u7b97\u6240\u97002mol/LNaOH\u6eb6\u6db2\u7684\u4f53\u79ef\uff1b\uff082\uff09\uff081\uff09\u7528\u6d53\u6eb6\u6db2\u914d\u5236\u7a00\u6eb6\u6db2\u5c31\u662f\u6eb6\u6db2\u7a00\u91ca\u8fc7\u7a0b\uff0c\u5728\u7a00\u91ca\u8fc7\u7a0b\u4e2d\u6eb6\u8d28\u7684\u7269\u8d28\u7684\u91cf\u4e0d\u53d8\uff0c\u4ee4\u97002mol/LNaOH\u6eb6\u6db2\u7684\u4f53\u79ef\u4e3aV\uff0c\u5219\uff1a0.1mol/L\u00d70.1L=2mol/L\u00d7V\uff0c\u89e3\u5f97V=0.005L=5mL\uff0c\u7b54\uff1a\u6240\u97002mol/L\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u7684\u4f53\u79ef\u4e3a5mL\uff1b\uff082\uff0980mL\u76841mol/L\u7684\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u4e2dn\uff08NaOH\uff09=0.1mol/L\u00d70.08L=0.008mol\uff0c2NaOH+H2SO4=Na2SO4+2H2O2 10.008mol 0.004mol\u6240\u4ee5\u9700\u89811mol/L\u7684\u786b\u9178\u4f53\u79ef\u4e3a0.004mol1mol/L=0.004L\uff0c\u7b54\uff1a\u5b8c\u5168\u4e2d\u548c80mL 0.1mol/L\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\uff0c\u9700\u89811mol/L\u7684\u786b\u91780.004L\uff0e
\u9700\u8981\u7684\u6c22\u6c27\u5316\u94a0\u7684\u7269\u8d28\u7684\u91cfn=c1\u00d7V1=0.1mol/L\u00d7100ml=0.01mol
\u6240\u9700\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u7684\u4f53\u79efV2=n/c2=0.01mol/\uff082mol/L\uff09=0.005L=5ml
50ml\u5df2\u914d\u7f6e\u6eb6\u6db2\u4e2d\u6c22\u6c27\u5316\u94a0\u7684\u7269\u8d28\u7684\u91cfn=2mol/L\u00d750ml=0.1mol
NaOH+HCl=NaCl+H2O
\u4e5f\u5c31\u662f\u8bf40.1mol\u6c22\u6c27\u5316\u94a0\u9700\u89810.1mol\u76d0\u9178\uff0c\u56e0\u6b64\u76d0\u9178\u7684\u4f53\u79efV=n/c=0.1mol/\uff081mol/L\uff09=0.1L=100ml
设体积V
0.2*0.1=4V
V=0.005L=5 mL
将足量的镁铝合金溶于该溶液中，产生H2的体积（标准状况下）是多少？
只有Al反应
2Al + 2NaOH + 2H2O = 2NaAlO2 + 3H2
---------2mol-------------------------------3*22.4L
---------0.02mol-----------------------------V
V=0.672L
绛旓細渚濇嵁绋閲婂墠鍚庢憾娑蹭腑婧惰川鐨勭墿璐ㄧ殑閲忎笉鍙樺彲鐭ワ紝4mol/L脳V=0.2mol/L脳250ml锛岃В寰楋細V=12.5ml锛涙晠绛旀涓猴細15.6锛12.5锛涳紙3锛夌敤4mol/L鐨勭～閰搁摐婧舵恫閰嶅埗250mL 0.2mol/L鐨勭～閰搁摐婧舵恫鐨勬楠や负锛氳绠椼侀噺鍙栥佺█閲娿佸喎鍗淬佺Щ娑层佹礂娑ゃ佸畾瀹广佹憞鍖锛...
绛旓細瀹為獙瀹ら渶瑕侀厤鍒0.2mol/L姘㈡哀鍖栭挔婧舵恫100mL,鐜版湁4mol/L鐨勬祿姘㈡哀鍖栭挔婧舵恫锛岃绠楁墍闇娴撴阿姘у寲閽犳憾娑茬殑浣撶Н(mL);璁句綋绉疺 0.2*0.1=4V V=0.005L=5 mL 灏嗚冻閲忕殑闀侀摑鍚堥噾婧朵簬璇ユ憾娑蹭腑锛屼骇鐢烪2鐨勪綋绉紙鏍囧噯鐘跺喌涓嬶級鏄灏戯紵鍙湁Al鍙嶅簲 2Al + 2NaOH + 2H2O = 2NaAlO2 + 3H2 ---2mol---...
绛旓細5H2O鐨勭墿璐ㄧ殑閲=500mL脳10-3L/mL脳0.2mol/L=0.1mol锛孋uSO4?5H2O鐨勮川閲=0.1mol脳250g/mol=25.0g锛涳紙2锛閰嶅埗涓瀹氱墿璐ㄧ殑閲忔祿搴︽憾娑茬殑鎿嶄綔姝ラ涓猴細鈶犵敤鎵樼洏澶╁钩绉板彇25.0gCuSO4?5H2O鏅朵綋锛屾斁鍦ㄧ儳鏉腑锛岀敤閫傞噺鐨勮捀棣忔按浣垮畠婧惰В骞舵仮澶嶈嚦瀹ゆ俯锛涒憽灏嗗埗寰楃殑婧舵恫閫氳繃鐜荤拑妫掑紩娴侊紝灏忓績鍦扮Щ鑷冲閲忕摱涓...
绛旓細瑕侀厤缃0.2 mol/L鐨勬阿姘у寲閽狅紙NaOH锛夋憾娑诧紝闇瑕鐭ラ亾NaOH鐨勬懇灏旇川閲忓拰鎵闇鐨勬憾瑙ｆ恫鐨勪綋绉備互涓嬫槸閰嶇疆婧舵恫鐨勬楠わ細璁＄畻鎵闇鍥轰綋NaOH鐨勮川閲忥細鏍规嵁鎽╁皵璐ㄩ噺锛岃绠楀嚭鎵闇NaOH鐨勮川閲忋傛懇灏旇川閲忥紙M锛変负 22.99 g/mol (Na) + 16.00 g/mol (O) + 1.01 g/mol (H)锛屾墍浠aOH鐨勬懇灏旇川閲忎负 39.99 g...
绛旓細1銆侀ケ鍜屾阿姘у寲閽犳憾娑閰嶅埗鍙湪钂搁姘翠腑鍔犲叆姘㈡哀鍖栭挔鐩村埌涓嶅啀婧惰В銆傦紙1锛夈佸皢姘㈡哀鍖栭挔閰嶆垚楗卞拰婧舵恫锛屾敞杩涘鏂欐《涓瘑闂斁缃嚦婧舵恫娓呬寒锛屼娇鐢ㄥ墠浠ュ鏂欑铏瑰惛涓婂眰娓呮恫銆傦紙2锛夈佹祿搴︽阿姘у寲閽犻ケ鍜屾憾娑叉敞杩涗笉鍚獵O₂鐨勬按銆傦紙3锛夈0.1mol/L閲忓彇5ml1000涓憞鍖锛0.2mol/L閲忓彇10ml1000涓憞鍖锛0.5mol...
绛旓細涓哄畬鎴愬疄楠岃繕闇瑕佺殑浠櫒鏈夎兌澶存淮绠°佺幓鐠冩锛涙晠绛旀涓猴細娌℃湁鐢ㄧ幓鐠冩寮曟祦锛涜嵂鍖欍佺幓鐠冩銆佽兌澶存淮绠★紱锛2锛瀹為獙瀹ら渶瑕0.2mol/L鐨凬a2CO3婧舵恫480mL锛岀敱浜庡閲忕摱鐨勮鏍兼病鏈480mL锛屽彧鑳界敤500mL瀹归噺鐡讹紝鍒500mLNa2CO3婧舵恫闇瑕丯a2CO3鐨勭墿璐ㄧ殑閲忎负锛0.5L脳0.2mol/L=0.1mol锛...
绛旓細瑕侀厤鍒0.2mol/L鐨勬棤姘寸７閰镐笁閽狅紙Na3PO4锛夋憾娑诧紝闇瑕佷互涓嬫楠わ細1. 璁＄畻鎵闇璐ㄩ噺锛氶鍏堢‘瀹氭墍闇婧舵恫鐨勪綋绉紝渚嬪100 mL銆傜劧鍚庢牴鎹懇灏旀祿搴﹀拰浣撶Н璁＄畻鎵闇鐨勭墿璐ㄨ川閲忋傛懇灏旀祿搴︿负0.2mol/L锛屼綋绉负0.1 L锛屽洜姝ゆ墍闇璐ㄩ噺涓0.2mol/L 脳 0.1 L = 0.02 mol銆2. 鍑嗗鏃犳按纾烽吀涓夐挔锛氭牴鎹墍闇...
绛旓細锛1锛夛紙2锛閰嶅埗100mL銆0.2mol?L-1鐨凬aCl婧舵恫鐨勬楠や负锛氳绠椼佺О閲忋佹憾瑙ｃ佽浆绉汇佹礂娑ゃ佸畾瀹广佹憞鍖绛夛紝闇瑕鐨勪华鍣ㄦ湁锛氭墭鐩樺ぉ骞炽佽嵂鍖欍佺儳鏉佺幓鐠冩銆100mL瀹归噺鐡躲佽兌澶存淮绠＄瓑锛屼笉闇瑕佺殑浠櫒涓猴細A锛庨敟褰㈢摱锛孊.200mL瀹归噺鐡讹紱杩樼己灏戠殑浠櫒鏈夛細鐑ф澂銆佺幓鐠冩锛涙晠绛旀涓猴細锛1锛堿B锛涳紙2锛夌儳鏉佺幓鐠...
绛旓細瀹氬 銆佹憞鍖绛夛紝闇瑕浣跨敤鐨勪华鍣ㄦ湁锛氳嵂鍖 銆佺儳鏉 銆侀噺绛 銆佹墭鐩樺ぉ骞 锛堢牆鐮併侀晩瀛愶級銆佺幓鐠冩 銆佽兌澶存淮绠 銆500mL 瀹归噺鐡 锛屾墍浠ヨ繕缂哄皯500mL瀹归噺鐡讹紝鏁呯瓟妗堜负锛500mL瀹归噺鐡讹紱锛2锛500mL 0.2mol/L Na2CO3婧舵恫涓惈鏈夋憾璐 纰抽吀閽 鐨勮川閲忎负锛歮锛圢a2CO3锛=0.2mol/L脳0.5L脳106g/L=10.6g锛閰嶅埗500mL...
绛旓細n(NaOH)=0.2*500/1000=0.1mol M(NaOH)=40g/mol m(NaOH)=n(NaOH)*M(NaOH)=0.1*40=4g
