初一数学多项式题
\u521d\u4e00\u6570\u5b66 \u591a\u9879\u5f0f\u4e58\u591a\u9879\u5f0f\u7684\u98981.\u8ba1\u7b97
1\uff09\uff08-2y^3)^2+(-4y^2)^3-[(-2y)^2\u00b7(-3y^2)^2]
=4y^6-64y^6-[4y^2*9y^4]
=4y^6-64y^6-36y^6
=-96y^6
2) (3x+2)^2-(3x-2)^2+(3x+2)^2\u00b7(3x-2)^2
=[(3x+2)+(3x-2)][(3x+2)-(3x-2)]+[(3x+2)(3x-2)]^2
=6x*4+(9x^2-4)^2
=24x+81x^4-72x^2+16
=81x^4-72x^2+24x+16
2.\u5316\u7b80\u6c42\u503c
\uff08x^2+3x)(x-3)-x(x-2)^2+(-x-y)(y-x), \u5176\u4e2d x=3,y=2.
\uff08x^2+3x)(x-3)-x(x-2)^2+(-x-y)(y-x)
=x(x+3)(x-3)-x(x-2)^2-(y+x)(y-x)
=x(x^2-9)-x(x^2-4x+4)-(y^2-x^2)
=x(x^2-9-x^2+4x-4)-y^2+x^2
=x(4x-13)-y^2+x^2
=5x^2-13x-y^2
\u5c06x=3\uff0cy=2\u4ee3\u5165\uff0c
\u539f\u5f0f=5*3^2-13*3-2^2
=45-39-4
=2
A-\uff08\uff0d3x\uff0b5\uff09+x²\uff0dx\uff0d7=5x²\uff0d3x\uff0d1
A=4x²\uff0d5x+11
由三次二项式得
n=3
m=-2
m^n=(-2)^3=-8
由代数式是三次 得 n=3
则代数式变为2X^3+(m+2)x+3
由于是2项 则(m+2)x=0
m=-2
m^n= -8
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