ab为有理数,如果规定一种新的运算,即“+”,定义a"+"b=a^2-ab+a-1,请根据+的意义计算下列各题：
\u5df1\u77e5a\u3001b\u4e3a\u6709\u7406\u6570\uff0c\u5982\u679c\u89c4\u5b9a\u4e00\u79cd\u65b0\u7684\u8fd0\u7b97\u201c*\u201d\u5b9a\u4e49a*b=a 2 -ab+a-1\uff0c\u6839\u636e\u201c*\u201d\u7684\u610f\u4e49\uff0c\u8ba1\u7b97\uff081*3\uff09*\uff08-3\u6839\u636e\u9898\u610f\u5f97\uff1a1\u22953=1 2 -1\u00d73+1-1=-2\uff0c\u5219\uff081*3\uff09*\uff08-3\uff09=\uff08-2\uff09\u2295\uff08-3\uff09=\uff08-2\uff09 2 -\uff08-2\uff09\u00d7\uff08-3\uff09+\uff08-2\uff09-1=4-6-2-1=4-9=-5\uff0e\u6545\u7b54\u6848\u4e3a\uff1a-5\uff0e
3\u253c6=3³-3*6+3-1=27-18+3-1=9+2=11
(1\u253c3)\u253c(-3)=(1³-1*3+1-1)\u253c(-3)
=(1-3+1-1)\u253c(-3)
=(-2)\u253c(-3)
=(-2)³-(-2)*(-3)+(-2)-1
=-8-6-2-1
=-17
=3^2-3*6+3-1
=9-18+3-1
=-7
（1“+”3）“+”（-3）
=(1^2-1*3+1-1)“+”（-3）
=(-2)“+”（-3）
=(-2)^2-(-2)*(-3)-2-1
=4-6-2-1
=-5
3"+"6=-7
(1"+"3)"+"(-3)=-5
-10
-7
绛旓細鍒╃敤棰樹腑鐨勬柊瀹氫箟鍖栫畝鏂圭▼寰楋細3锛坸-4锛+3=6锛屽幓鎷彿寰楋細3x-12+3=6锛岃В寰楋細x=5锛屾晠绛旀涓猴細5
绛旓細21a+3b 瑕佺敤鏁翠綋鎹㈠厓鐨勬濇兂鍋
绛旓細-2*x-(2x)*3 =-2-2x-(2x-6)=-4x+4=0 鈭磝=1
绛旓細a*b=b.4ab=b (4a-1)b=0 褰揵=0鏃,a涓轰竴鍒鏈夌悊鏁 褰揵鈮0鏃,4a-1=0鍗砤=1/4
绛旓細(5+3)+(-1)=(2*5-3))+(-1)=7+(-1)=2*7-(-1)=15
绛旓細鎴戜滑鍏堣В绛旀嫭鍙峰唴鐨勯儴鍒 鏍规嵁鍏紡a鈥b=a-b+1 鍒2鈥3=2-3+1=0 鎵浠1鈥伙紙2鈥3锛=1鈥0=1-0+1=2
绛旓細a鈥籦=ab+a-b 4鈥2+(2-4)鈥3 =4脳2+4-2+锛-2锛夆3 =10+锛-2锛壝3+锛-2锛-3 =10-6-2-3 =-1
绛旓細鍥犱负A*B*C=A+B-C 鎵浠2*3*(X-1)=2+3-锛圶-1锛=5-X+1=6-X=4 X=2
绛旓細|a b||c d|=ad-bc|2 4||1-x 5|=182*5-4(1-x)=1810-4+4x=186+4x=18x=3
绛旓細(2*3)*2 =(2-3+1)*2 =0*2 =0-2+1 =-1
