因式分解，全部具体过程
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绛旓細鍥犲紡鍒嗚В鎸囩殑鏄妸涓涓椤瑰紡鍒嗚В涓哄嚑涓暣寮忕殑绉殑褰㈠紡.鈶存彁鍏洜寮忔硶 鈶犲叕鍥犲紡锛氬悇椤归兘鍚湁鐨勫叕鍏辩殑鍥犲紡鍙仛杩欎釜澶氶」寮忓悇椤圭殑鍏洜寮忋傗憽鎻愬叕鍥犲紡娉曪細涓鑸湴锛屽鏋滃椤瑰紡鐨勫悇椤规湁鍏洜寮忥紝鍙互鎶婅繖涓叕鍥犲紡鎻愬埌鎷彿澶栭潰锛屽皢澶氶」寮忓啓鎴愬洜寮忎箻绉殑褰㈠紡锛岃繖绉嶅垎瑙ｅ洜寮忕殑鏂规硶鍙仛鎻愬叕鍥犲紡娉.銆俛m锛媌m锛媍m锛漨锛坅...
绛旓細涔熷彲浠ョ敤寰呭畾绯绘暟娉曞皢鍏鍒嗚В锛鍙槸鍒嗚В鍑烘潵鐨勫紡瀛愬苟涓嶆暣娲併傝繖鏄洜涓猴紝鐢变唬鏁板熀鏈畾鐞嗗彲鐭娆′竴鍏冨椤瑰紡鎬绘槸鏈塶涓牴锛屼篃灏辨槸璇达紝n娆′竴鍏冨椤瑰紡鎬绘槸鍙互鍒嗚В涓簄涓竴娆鍥犲紡鐨涔樼Н銆傚苟涓旇繕鏈変竴鏉″畾鐞嗭細瀹炵郴鏁板椤瑰紡鐨勮櫄鏁版牴涓や袱鍏辫江鐨勶紝灏嗘瘡瀵瑰叡杞殑铏氭暟鏍瑰搴旂殑涓娆″洜寮忕浉涔橈紝鍙互寰楀埌浜屾鐨勫疄绯绘暟鍥犲紡锛...
绛旓細鈶鍒嗚В鍥犲紡蹇呴』鍒嗚В鍒版瘡涓椤瑰紡鍥犲紡閮戒笉鑳藉啀鍒嗚В涓烘銆 娉:鍒嗚В鍥犲紡鍓嶅厛瑕佹壘鍒板叕鍥犲紡,鍦ㄧ‘瀹氬叕鍥犲紡鍓,搴斾粠绯绘暟鍜屽洜寮忎袱涓柟闈㈣冭檻銆 3.鎻愬叕鍥犲紡娉曞熀鏈楠: (1)鎵惧嚭鍏洜寮; (2)鎻愬叕鍥犲紡骞剁‘瀹氬彟涓涓洜寮: 鈶犵涓姝ユ壘鍏洜寮忓彲鎸夌収纭畾鍏鍥犲紡鐨鏂规硶鍏堢‘瀹氱郴鏁板湪纭畾瀛楁瘝; 鈶＄浜屾鎻愬叕鍥犲紡骞剁‘瀹氬彟涓涓洜寮...
绛旓細(x+a)^2-6(x+a)(x-b)+9(x-b)^2 =(x+a-3x+3b)^2 =(a+3b-2x)^2 -10x^2y-5xy^2+15xy =-5xy(2x+y-3)x(x-y)(a-b)-y(y-x)(b-a)=x(x-y)(a-b)-y(x-y)(a-b)=(x-y)(a-b)(x-y)=(a-b)(x-y)^2 ...
绛旓細鍗佸瓧鐩镐箻璇曚竴璇曪紝鍒嗙粍鍒嗚В瑕佸悎閫傘傗 鍑犻亾渚嬮 1锛鍒嗚В鍥犲紡(1+y)^2-2x^2(1+y^2)+x^4(1-y)^2锛 瑙ｏ細鍘熷紡=(1+y)^2+2(1+y)x^2(1-y)+x^4(1-y)^2-2(1+y)x^2(1-y)-2x^2(1+y^2)锛堣ˉ椤癸級 =[(1+y)+x^2(1-y)]^2-2(1+y)x^2(1-y)-2x^2(1+y^2)锛...
绛旓細瑙 鍒嗕笁姝鍒嗚В [1]锛(yz^5+zx^5+xy^5)-(zy^5+xz^5+yx^5)=-yz(y^4-z^4)+zx(x^4-z^4)-xy(x^4-y^4)=-yz(y-z)(y+z)*(y^2+z^2)+zx(x-y+y-z)(z+x)(z^2+x^2)-xy(x-y)(x+y)(x^2+y^2)=-x(x-y)(y-z)[(y+z)(y^2+z^2)+x(y^2+z^2+...
绛旓細锛1锛夊師寮=(5x)²-(4y)²=(5x+4y)(5x-4y)(2) 鍘熷紡=(a-b)(x-y)+(a-b)(x+y)=(a-b)(x-y+x+y)=(a-b)脳2x =2x(a-b)
绛旓細=x(3x锛1)(x锛2)锛3(3x锛1)=(3x锛1)(x²锛2x锛3)=(3x锛1)(x锛3)(x锛1)x³锛媥锛30 =(x³锛27)锛(x锛3)=(x³锛3³)锛(x锛3)=(x锛3)(x²锛3x锛9)锛(x锛3)=(x锛3)(x²锛3x锛9锛1)=(x锛3)(x²锛3x锛10)
绛旓細1 鍘熷紡=3x(2-y+3y^2)=3x(3y+1)(y-1)2.鍘熷紡=(m-n)(m-1)3. 鍘熷紡=(3m+3n+4m-4n)(3m+3n-4m+4n)=(7m-n)(7n-m)4. 鍘熷紡=3x[9x^2-(2x-y)^2]=3x(3x+2x-y)(3x-2x+y)=3x(5x-y)(x+y 5. 鍘熷紡=2(m+n)[x^2+4(m+n)]=2(n+n)(x^2+4m+4n)6. 鍘熷紡=...
绛旓細x1=-4/3, x2=2 (2)x^2-6x=2 x^2-6x-2=0 杩欓鍙兘鐢ㄦ眰鏍瑰叕寮忓仛 (3)y^2+3y+1=0杩欓瑙ｆ硶鍚岋紙2锛夛紙4锛墄^2-9x-10=0 (x-10)(x+1)=0 x1=10,x2=-1 (5)(x+2)^2-8(x+2)+16=0 (x+2-4)^2=0 x1=x2=2 11銆侊紙1锛墄(x-2)+x-2=0 (x+1)(x+2锛=0 x...
