中职高一数学解题，急！要过程！
\u9ad8\u4e00\u6570\u5b66\uff0c\u8981\u8be6\u7ec6\u8fc7\u7a0b\uff0c\u6025\uff01\uff01c\u5c0f\u4e8e1\uff0c\u6700\u5c0f\uff0c
a\u548cb\uff0c\u56e0\u4e3alog(4)3.6=(1/2)log(2)3.6
log(2) 3.4 > (1/2)log(2) 3.6
\u6240\u4ee5a>b>c
\u590d\u5408\u51fd\u6570\u5355\u8c03\u6027\u7684\u95ee\u9898\uff1a\u201d\u589e\u589e\u4e3a\u589e\u3001\u589e\u51cf\u4e3a\u51cf\u201c
y=2^x\u5728R\u4e0a\u5355\u8c03\u9012\u589e\uff0c\u800c-x^2+3x+2\u5728(-\u221e,3/2]\u4e0a\u5355\u8c03\u9012\u589e\uff0c\u5728(3/2,+\u221e)\u4e0a\u5355\u8c03\u9012\u51cf
\u2234y=2^(-x^2+3x+2)\u7684\u5355\u8c03\u9012\u589e\u533a\u95f4\u4e3a(-\u221e,3/2]\uff0c\u5355\u8c03\u9012\u51cf\u533a\u95f4\u4e3a(3/2,+\u221e)
\u671b\u91c7\u7eb3
7; (1); CuA={1,3,4,5,6}, CuB={1,2,4,8}
(2); A∩CuB={2,8}, CuA∪B={1,3,4,5,6,7}
8; CuA={x|x<1}
11; A∩B={x|<x<5} ,A∪B={x|0<x<6}
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绛旓細锛1锛夛經x|x=0.5} (2) 锝泋|x=3} (3) x^2-5x+4=0鍖栬В涓(x-4)(x-1)=0鎵浠ワ經x|x=1鎴杧=4} 锛4锛夛級锝泋|x>1/3} (5) x^2+2=0绉婚」x^2=-2鍙堝洜涓簒^2澶т簬绛変簬0鎵浠ヨВ涓虹┖闆 (6){-4,-3,-2,-1,0,1,2,} (7) {x|x=1鎴栬厁=0} (8) {x鈭圸|x=2n;...
绛旓細CsA={2,3,4}Cs锛圕sA锛={1,5} CsA...闆嗗悎A鍦ㄥ叏闆哠涓嬬殑琛ラ泦Cs锛圕sA锛夈傞泦鍚圕sA鍦ㄥ叏闆哠涓嬬殑琛ラ泦鍗虫槸A 10锛岃鍏ㄩ泦S={0,1,2,3,4}锛孉={1,2,4}锛孊={1,3}锛屽垯 CsA={0,3}锛孉鈭狢sB={0,2,4}锛孋sA鈭狟={0,1锛3}锛孋sB鈭狝={0,1,2,4} 璁惧叏闆哠=R锛孋sA{x|}x鈭圧,涓攛鈮...
绛旓細瑙ｆ硶涓锛氾紙1-鈭3tan75掳锛/锛堚垰3+tan75掳锛=(1-tan60掳tan75掳) /(tan60掳+tan75掳)=1/ tan(60掳+75掳)=1/tan135掳 = -1 瑙ｆ硶浜岋細tan75掳=tan(45掳+30掳)=(tan45掳+tan30掳) /(1-tan45掳tan30掳)=(1+鈭3/3) /(1-鈭3/3)=(3+鈭3) /(3-鈭3)=(鈭3+1)/(鈭3...
绛旓細11; A鈭〣={x|<x<5} ,A鈭狟={x|0<x<6}
绛旓細鏍规嵁鏁板鐨勫崐瑙掑叕寮忥紝鏈変互涓瑙ｉ姝ラ杩囩▼銆2sin伪=1+cos伪 宸﹁竟=2sin(伪/2) * cos(伪/2)鍙宠竟= 2(cos(伪/2))^2 鍗2sin(伪/2) * cos(伪/2) = 2(cos(伪/2))^2 鍒檚in(伪/2) = cos(伪/2)鍙堝洜涓簊in(伪/2)鐨勫钩鏂+ cos(伪/2)鐨勫钩鏂=1 鎵浠ワ紝瑙ｅ緱锛宑os(伪/2)=卤鈭2/...
绛旓細鍟﹀暒鍟︼紝鐢ㄤ簩鍊嶈鍏紡鍙洰鏍囧嚱鏁扳滄敹鈥濇垚涓夎鍑芥暟褰㈠紡锛屾敞鎰忚礋鍙凤紒璇︾粏杩囩▼濡傚浘锛
绛旓細鍥炵瓟锛(1)浠=a^x,鎷╁垯鏈 y=1/2(t-1/t),鍗硉^2-2yt-1=0 瑙ｅ緱t1=y+(1+y^2)^(1/2),t2=y-(1+y^2)^(1/2) 鍥犱负t=a^x銆0,鑰宼2<0,鑸嶅幓銆傛墍浠 t=y+(1+y^2)^(1/2) 鍗砤^x=y+(1+y^2)^(1/2) x=(浠涓哄簳)log[y+(1+y^2)^(1/2)] 鍙嶅嚱鏁版槸 y=...
绛旓細(1) 鑻ュ嚱鏁癴锛坸锛夋槸瀹氫箟鍦≧涓婄殑鍋跺嚱鏁般佸湪锛堣礋鏃犵┓锛0锛変笂鏄鍑芥暟 鍒欏湪(0, +鈭)涓婃槸鍑忓嚱鏁 宸茬煡f(3)=0 鍒檉(-3)=0 褰搙<0鏃 f(x)>0=f(-3) 鐢变簬鍗曞锛屽垯0>x>-3 褰搙>0鏃 f(x)>0=f(3) 鐢变簬鍗曞噺锛屽垯0<x<3 缁间笂锛-3<x<0 鎴0<x<3 (2) 璁緁(x)...
绛旓細7aa+16ab-15bb=0锛屾牴鎹悜閲忕殑瀹氫箟锛歛.b=|a||b|cos澶硅 褰撲袱涓悜閲忕浉绛夋椂锛屽す瑙掍负0锛屾墍浠ワ細aa=|a|^2,bb=|b|^2 棰樻剰鍛婅瘔鍚戦噺a鍜屽悜閲廱澶硅涓60搴 锛屾墍浠ワ細ab=|a||b|cos60=1/2|a||b|,浠ｅ叆涓婅堪鏂圭▼鍙互寰楀埌锛7|a|^2+8|a||b|-15|b|^2=0,鎵浠ワ細锛7|a|+15|b|锛夛紙|a|-...
绛旓細绗竴涓汉閿欎簡绗竴棰橈紝鎴戞潵璁㈡涓涓嬨傦紙1锛夊绉拌酱=-2a/b=1 鍥犱负a>0鎵浠ュ湪鍖洪棿[2,3]鍐呭綋x=2鏃跺嚱鏁版湁鏈灏忓2锛屽綋x=3鏃跺嚱鏁版湁鏈澶у5 绠楀嚭a=1b=0
