对于任意两个自然数a和b,定义一种新运算“*”:a*b=a÷b×5+3,30*6*7等于? 对于两个不相等的实数a、b,定义一种新的运算如下, a*b=...

\u5bf9\u4e8e\u4efb\u610f\u7684\u4e24\u4e2a\u81ea\u7136\u6570a\u548cb\uff0c\u89c4\u5b9aa\uff0ab\uff1da\uff08a\uff0b1\uff09\uff08a\uff0b2\uff09...\uff08a\uff0bb\uff0d1\uff09\uff0c\u5982\u679c\uff08x\uff0a3\uff09

x*3=60,x(x+1)(x+2)=60\u6240\u4ee5x=3

\u2235 a*b= a+b a-b (a+b\uff1e0) \uff0c\u22345*4= 5+4 5-4 =3\uff0c\u22346*\uff085*4\uff09=6*3\uff0c= 6+3 6-3 \uff0c=1\uff0e\u6545\u7b54\u6848\u4e3a\uff1a1\uff0e

a*b=a÷b×5+3
则30*6*7
=(30÷6×5+3)*7
=28*7
=28÷7×5+3
=4×5+3
=23
希望可以帮到你,^_^

解:a*b=a÷b×5+3,
30*6=28,28*7=23

30*6
=30÷6×5+3
=28

28*7
=28÷7×5+3
=23

30*6*7
=(30/6×5+3)*7
=28*7
=28/7*5+3
=23

23

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