编写程序输入三位数(100—999),然后按数字逆序输出。(例:输入123↙,输出321) 求“输入一个100至999内的整数,反序显示这个数,如输入1...

\u7f16\u5199\u7a0b\u5e8f\u8f93\u5165\u4e09\u4f4d\u6570\uff08100\u2014999\uff09\uff0c\u7136\u540e\u6309\u6570\u5b57\u9006\u5e8f\u8f93\u51fa\u3002\uff08\u4f8b\uff1a\u8f93\u5165123\u2199\uff0c\u8f93\u51fa321

\u2026\u2026
int main()
{
int a,b;
cin>>a;

int m,n,p;
m=a/100;
n=(a-100m)/10;
p=a-100m-10n;
b=100p+10n+m;
cout<<b;
return 0;}

#include
#include
int main()
{
int i = 0;
int n = 0;
int len;
char str[4];
memset(str, 0x00, sizeof(str));
printf("\u8bf7\u8f93\u5165\u4e00\u4e2a100-999\u8303\u56f4\u5185\u7684\u6574\u6570: ");
scanf("%d", &i);
sprintf(str, "%d", i);
len = strlen(str);
printf("\u53cd\u5e8f\u8f93\u51fa: ");
for (n = len - 1; n >= 0; n--) {
printf("%c", str[n]);
}
printf("\n");
return 0;
}


\u4e0d\u77e5\u9053\u4f60\u7528\u7684\u4ec0\u4e48\u7f16\u8bd1\u5668, \u6211\u5728Linux\u4e0bGcc\u7f16\u8bd1\u901a\u8fc7

import java.util.*;
public class sws {
public static void main(String args[]) {
int sws;
int sws1[] = new int[4];
Scanner sc1 = new Scanner(System.in);
System.out.print("请输入一个三位数:");
sws = sc1.nextInt();
for(int i=0;i<3;i++) {
sws1[i] = sws%10;
sws = sws/10;
}
System.out.print("转换完毕,下面倒序输出:");
for(int i=0;i<3;i++) {
System.out.print(sws1[i]);
}
}
}

#include<stdio.h>
int main()
{
int num;
int h;
int t;
int n;
printf("请输入一个三位整数:");
scanf("%d",&num);
h = num/100;
t = (num - h*100)/10;
n = num%10;
printf("原始的三位整数:%d\n",num);
printf("逆转后的三位整数:%d%d%d\n",n,t,h);
return 0;

}

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