求解数学，微积分的，悬赏可以增加哦！
\u6c42\u89e3\u6570\u5b66\u5fae\u79ef\u5206\u4e09\u89d2\u51fd\u6570\u4e07\u80fd\u516c\u5f0f
\u4ee4tanx/2=t
(secx/2)^2dx/2=dt
dx=2dt/(t^2+1)
\u222bdx/(sinx+tanx)
=\u222b2dt/{(t^2+1)*[2t/(1+t^2)+2t/(1-t^2)]}
=\u222bdt/{(1+t^2)*2t/[(1+t^2)(1-t^2)]}
=\u222b(1-t^2)/(2t)dt
=1/2\u222b(1/t-t)dt
=1/2lnt-t^2/4+c
=1/2ln[tan(x/2)]-[tan(x/2)]^2/4+c
x= 2sin(2t)
dx/dt = 4cos2t
y=2sint
dy/dt = 2cost
dy/dx = dy/dt.dt/dx = cost/(2cos2t)
\u221a3 = 2sin2t (1)
1= 2sint (2)
(1)/(2)
2cost =\u221a3
t = \u03c0/6
dy/dx| t=\u03c0/6 = (\u221a3/2)
tangent of the equation (\u221a3,1)
y-1 = (\u221a3/2)(x-\u221a3)
horizontal tangent ie dy/dx = 0
cost =0
t = \u03c0/2 or 3\u03c0/2
ie
(0, 2) or (0,-2)
vertal tangent , 1/dy/dx = 0
cos2t =0
t = \u03c0/4 or 3\u03c0/4 or 5\u03c0/4 or 7\u03c0/4
ie
(2, \u221a2) or (-2,\u221a2) or (2,-\u221a2) or (-2,-\u221a2)
2)当x趋近于无穷大时,(ax^2+b)/(x^2+1),趋近于1,a=1,b为任意实数
3)当x趋近于无穷大时,根号x除以(x+1)为无穷小,sinx^2为有界量,极限为0
4)当x在0的左侧趋于0时,
5)(1-sinx)^(3/x) (1-sinx)^(3/sinx) = e^(-3)
1 ln((x+1)/(x-1))
2 1
绛旓細16銆佹柟绋嬩袱杈瑰x姹傚寰 y'=0+siny+x*cosy*y'锛岃В寰 y'=siny/(1锛峹cosy)銆
绛旓細5)(1-sinx)^(3/x) (1-sinx)^(3/sinx) = e^(-3)
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