一道简单的JAVA程序题:编写一个方法：判断给定的三位数是否是水仙花数，方法的返回值是布尔型。 编写一个方法判断一个数是不是水仙花数？
JAVA\u7ed9\u5b9a\u4e00\u4e2a\u6570,\u5224\u65ad\u8fd9\u4e2a\u6570\u662f\u4e0d\u662f"\u6c34\u4ed9\u82b1\u6570"\u3002//\u6c34\u4ed9\u82b1\u7d20
public class shuixian
{
public static void main(String[] args)
{
for(int i=1;i<1000;i++)
{
int a=i/100;
int b=(i-a*100)/10;
int c=i-a*100-b*10;
if(i==a*a*a+b*b*b+c*c*c)
{
System.out.println("\u6c34\u4ed9\u82b1\u7d20:"+i);
}
}
}
}
//\u98a0\u5012\u6570\u7ec4\u9012\u5f52\u65b9\u6cd5
public class Test322 {
static void reverse(int[] a, int left, int right) {
if (left >= right) {
return;
}
int val;
val = a[left];
a[left] = a[right];
a[right] = val;
right--;
left++;
reverse(a, left, right);
}
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int aa[] = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
reverse(aa, 0, 8);
for (int i = 0; i < aa.length; i++) {
System.out.print(aa[i] + "\t");
}
}
}
\u770b\u4e0b\u6211\u7684\u628a \u5f88\u7b80\u5355\u7684 \uff1a
import java.util.Scanner;
class Test
{
public static void main(String[] args)
{
Scanner in=new Scanner(System.in);
int x=0;
try
{
i=in.nextInt();
}
catch(Exception e)
{
System.out.println("\u8f93\u5165\u975e\u6570\u5b57\uff01");
return;
}
if(x=1000)
{
System.out.println("\u8f93\u5165\u7684\u4e0d\u662f\u4e09\u4f4d\u6570\uff01");
return;
}
if(isSX(x))
{
System.out.println(x"\u662f\u6c34\u4ed9\u82b1\u6570\uff01");
}
else
{
System.out.println(x"\u4e0d\u662f\u6c34\u4ed9\u82b1\u6570\uff01");
}
}
static boolean isSX(int x)
{
String s="";
s=s+x;
int i1=new Integer(s[0]);
int i2=new Integer(s[1]);
int i3=new Integer(s[2]);
if((i1+i2+i3)==x)
{
return true;
}
else
{
return false;
}
}
}
return y;
返回的就是输入的数字；
但如果你输的不是水仙花数：
这个 y=r*r*r+s*s*s+t*t*t;
既是x！=y； 所以返回的return y 是一个新的数字，该数字是r*r*r+s*s*s+t*t*t;
定义Shuixian方法的时候是Integer类型。调用的时候用double类型。
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