Java中怎么删除指定字符串中的最后一个字符 java中字符串如何去除最后一个字符
java\u600e\u4e48\u53bb\u6389\u5b57\u7b26\u4e32\u6700\u540e\u4e00\u4e2a\u5b57\u7b26\u5b57\u7b26\u4e32\uff1astring s = "1,2,3,4,5,"
\u76ee\u6807\uff1a\u5220\u9664\u6700\u540e\u4e00\u4e2a ","
\u65b9\u6cd5\uff1a
1\u3001\u7528\u7684\u6700\u591a\u7684\u662fSubstring\uff0c\u8fd9\u4e2a\u4e5f\u662f\u6211\u4e00\u76f4\u7528\u7684
s = s.Substring(0,s.Length - 1)
2\u3001\u7528 RTrim\uff0c\u8fd9\u4e2a\u6211\u539f\u6765\u53ea\u77e5\u9053\u7528\u6765\u5220\u9664\u6700\u540e\u7684\u7a7a\u683c\uff0c\u4e5f\u6ca1\u6709\u4ed4\u7ec6\u770b\u8fc7\u5176\u5b83\u7684\u7528\u6cd5\uff0c\u624d\u53d1\u73b0\u53ef\u4ee5\u76f4\u63a5trim\u6389\u4e00\u4e9b\u5b57\u7b26
s = s.ToString().RTrim(',')
3\u3001\u7528TrimEnd,\u8fd9\u4e2a\u4e1c\u897f\u548cRTrim\u5dee\u4e0d\u591a\uff0c\u533a\u522b\u662f\u8fd9\u4e2a\u4f20\u9012\u7684\u662f\u4e00\u4e2a\u5b57\u7b26\u6570\u7ec4\uff0c\u800cRTrim\u53ef\u4ee5\u662f\u4efb\u4f55\u6709\u6548\u7684\u5b57\u7b26\u4e32
s=s.TrimEnd(',') //\u5982\u679c\u8981\u5220\u9664"5,"\uff0c\u5219\u9700\u8981\u8fd9\u4e48\u5199 char[] MyChar = {'5',','}; s = s.TrimEnd(MyChar); //s = "1,2,3,4"
\u5229\u7528java\u4e2dString\u7c7b\u7684substring()\u5b57\u7b26\u4e32\u622a\u53d6\u65b9\u6cd5 \u548clength()\u6c42\u5b57\u7b26\u4e32\u957f\u5ea6\u65b9\u6cd5\u5373\u53ef\u3002
1\u3001\u8bed\u6cd5\u89e3\u6790\uff1a
public String substring(int beginIndex, int endIndex)\uff1b\u7b2c\u4e00\u4e2aint\u4e3a\u5f00\u59cb\u7684\u7d22\u5f15\uff0c\u5bf9\u5e94String\u6570\u5b57\u4e2d\u7684\u5f00\u59cb\u4f4d\u7f6e\uff1b\u7b2c\u4e8c\u4e2a\u662f\u622a\u6b62\u7684\u7d22\u5f15\u4f4d\u7f6e\uff0c\u5bf9\u5e94String\u4e2d\u7684\u7ed3\u675f\u4f4d\u7f6e\u3002
2\u3001\u5177\u4f53\u4ee3\u7801\u5982\u4e0b\uff1a
3\u3001\u6267\u884c\u7ed3\u679c\u5982\u4e0b\uff1a
\u6269\u5c55\u8d44\u6599\uff1a
\u4f7f\u7528RTrim\uff0c\u6b64\u51fd\u6570\u4e0d\u4ec5\u4ec5\u7528\u6765\u5220\u9664\u6700\u540e\u7684\u7a7a\u683c\uff0c\u4e5f\u53ef\u4ee5\u76f4\u63a5trim\u6389\u4e00\u4e9b\u5b57\u7b26 \u3002
1\u3001\u5177\u4f53\u4ee3\u7801\u5982\u4e0b\uff1a
2\u3001\u4f7f\u7528TrimEnd\uff0c\u6b64\u51fd\u6570\u548cRTrim\u7c7b\u4f3c\uff0c\u533a\u522b\u662f\u8fd9\u4e2a\u4f20\u9012\u7684\u662f\u4e00\u4e2a\u5b57\u7b26\u6570\u7ec4\uff0c\u800cRTrim\u53ef\u4ee5\u662f\u4efb\u4f55\u6709\u6548\u7684\u5b57\u7b26\u4e32\u3002
\u6267\u884c\u4ee3\u5982\u4e0b\uff1a
\u6267\u884c\u7ed3\u679c\u5982\u4e0b\uff1a
\u53c2\u8003\u8d44\u6599\uff1a
\u767e\u5ea6\u767e\u79d1--substring
\u767e\u5ea6\u767e\u79d1--trim
String a = "hello!";
//这句话就是从字符的第0的开始截取，一直到最后一个减1也就是倒数第二个。这样所截的字符串就是你想要的结果了。
a = a.substring(0, a.length()-1);
System.out.print(a);
方法有很多。不过如果只是个测试，那哪种都可以。
最简单易懂的方法
利用substring()与length()
String str = "abcdefg";
str.substring(0,str.length()-1);
if(null!=a&&a.length()>0)
a = a.substring(0, a.length()-1);
一般在调用substring()的时候要进行判断
String a = "hello!";
a = a.substring(0, a.length()-1);
System.out.print(a);
直接用substring(0, length()-1)
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