Python编程求平均值的两种方法是? python编程:均值的均值怎么写?

python\u7f16\u7a0b\u8f93\u5165n.\u6c42\u5e73\u5747\u6570

\u201cpython\u7f16\u7a0b\u8f93\u5165n.\u6c42\u5e73\u5747\u6570\u201d
==>
\u8f93\u5165n\u4e2a\u6b63\u6574\u6570\uff0c\u8ba1\u7b97\u5176\u5e73\u5747\u503c
==>
def enterInteger(prompt="Enter an integer: "): """prompt input an integer""" while 1: try: return int(raw_input(prompt)) except: passdef main(n): data = [enterInteger() for x in xrange(n)] if data: print "Avg: %.2f" % (1. * sum(data) / len(data))if __name__ == "__main__": main(5)

#coding:gb18030
no = 0
total = 0
for record in open('the_file.cvs','r').readlines():
no += 1
if no == 30:
p1, p2, p3, p4 = record.split(',') # Supposed the limiter of CVS is ','. If not, replace ',' with real one.
total += float(p4)
elif no > 10030:
break

print 'average of column E:', total / no

方法一:
scores = [91, 95, 97, 99, 92, 93, 96, 98]
scores2 = []
avg = sum(scores) / len(scores)
print('平均成绩是:{}'.format(avg))
for i in scores:
if i avg># 少于平均分的成绩放到新建的空列表中
scores2.append(i)
print('低于平均成绩的有:{}'.format(scores2))
方法二:
导入函数库
import numpy as np # 导入 numpy库,as 即为导入的库起一个别称,别称为np
scores1 = [91, 95, 97, 99, 92, 93, 96, 98]
scores2 = []
average = np.mean(scores1) # 一行解决。
print('平均成绩是:{}'.format(average))
# 下面展示一种NumPy数组的操作,感兴趣的同学可以自行去学习哈。
scores3 = np.array(scores1)
print('低于平均成绩的有:{}'.format(scores3[scores3

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