我要详细的解题过程，以下题目
\u4ee5\u4e0b\u9898\u76ee\uff0c\u6211\u8981\u8fc7\u7a0b\uff01\u8be6\u7ec6\u89e3\u7b54\uff0130\u5428\u6bd4\uff08 25 \uff09\u5428\u591a\u4e94\u5206\u4e4b\u4e00\uff1f
30\uff1d\uff081+1/5\uff09x
\u89e3\u5f97\uff1ax=25
30\u5428\u6bd4\uff0829.8 \uff09\u5428\u591a\u4e94\u5206\u4e4b\u4e00\u5428\uff1f
1/5=0.2
30-0.2=29.8
\u7ea2\u82b1\u6bd4\u767d\u82b1\u591a60\u6735\uff0c\u767d\u82b1\u662f\u7ea2\u82b1\u7684\u4e09\u5206\u4e4b\u4e00\uff0c\u767d\u82b1\u3001\u7ea2\u82b1\u5404\u51e0\u6735\uff1f
\u7ea2\u82b1\uff1a60/\uff081-1/3\uff09\uff1d90
\u767d\u82b1\uff1a90-60\uff1d30
\u5f53x\u22652\u65f6\uff0c\u539f\u5f0f\u53ef\u5316\u4e3ax-2=2-x
\u6240\u4ee5x=2
\u5f53x\uff1c2\u65f6\uff0c\u539f\u5f0f\u53ef\u5316\u4e3a2-x=2-x
\u7b49\u5f0f\u6052\u6210\u7acb
\u7efc\u4e0a\u6240\u8ff0\uff0cx\u22642
解：①∵DN＝BM，AD＝AB，则RtΔABM≌RtΔADN
∴AM＝AN，∠BAM＝∠NAD＝22.5°
过A作AE⊥MN，∴∠MAE＝∠NAE＝22.5°，ME＝EN
∴易证RtΔABM≌RtΔAEM，∴BM＝ME
同理可证NE＝DN，故DN＋BM＝MN
图在哪？
绛旓細锛1锛.瑙ｏ細璁惧師璁″垝姣忓ぉ闆跺敭x鍚紝鍒欏疄闄呴浂鍞畑+2鍚 鐢棰樼洰鍙煡锛200/x+6-200/锛坸+2)+6=5 瑙ｅ緱X=2 鎵浠ュ師璁″垝姣忓ぉ闆跺敭2鍚 锛2).鐢辩涓闂彲鐭ワ細閿鍞殑澶╂暟锛200/(2+2)+6=20 鎵浠ュ埄娑︿负锛20x(2000x6+2200x4)=416000
绛旓細杩囩▼濡備笅 绗竴棰 25x+5=(x-1)*(25+5)25x+5=(x-1)*30 鍘绘帀绛夊紡鍙宠竟鐨勬嫭鍙凤紝鍒╃敤涔樻硶鍒嗛厤鐜囷紝寰楀埌 25x+5=30x-30 锛堣繖涓瓑寮忓彲浠ヨ繖鏍风悊瑙ｏ紝涓よ竟鍚屾椂鍔犱笂30锛屽悓鏃跺噺鍘25x锛屽緱鍒35=5x 鍏跺疄35=5x 涓 5x=35 鏄悓涓涓瓑寮忥紝鍙笉杩囨妸绛夊紡鐨勫乏杈瑰拰鍙宠竟瀵硅皟浜嗕竴涓嬨備竴鑸暟瀛︿腑鐨勪功鍐欎範鎯紝鏄...
绛旓細14/(1+2+4)=2涓
绛旓細1銆 a,b涓哄疄鏁帮紝涓攁鐨勫钩鏂瑰姞b鐨勫钩鏂瑰啀鍑5绛変簬2锛坅+2b),姹傦紙a-b)鐨2003娆℃柟鐨勭珛鏂规牴 搴旇鏄繖鏍风殑鍚э紵a^2+b^2+5=2(a+2b)(a^2-2a+1)+(b^2-4b+4)=0 (a-1)^2+(b-2)^2=0 a-1=0 b-2=0 a=1;b=2 [(a-b)^2003]^1/3=(-1)^(1/3)=-1 2銆 a=10鐨勮礋浜屾...
绛旓細1-7鐨勬暟鍜屾槸28 A+B+C+D+E+F+G=28 A+B+C+2D+2E+2F+3G=15*3=45 D+E+F+2G=17 D+E+F鐨勫 鏄鏁 D+E+F<=15 G<6 A+B+C-G=11 A+B+C>=12 A+B+C+3G 鐨勫 鏄鏁 纭畾G=1 D+E+F=15 A+B+C=12 A=6,B=2,C=4 D=5,E=3,F=7 G=1 ...
绛旓細200脳2=400 10+20+30+...70+80=90脳4=360 400-360=40=10+30 姝ｄ腑闂村～涓10鍜30锛200-40=160=80+60+20=70+50+40锛
绛旓細1.鐢遍鎰忓緱X+Y=20鍙樺舰鐨刋=20-Y鏈夋柟宸叕寮忓緱锛圶-10)²+锛圷-10锛²=8甯﹀叆寰楋紙Y-10锛²+锛10-Y锛²=8瑙ｅ緱Y=12鎴8鎵浠=8鎴栨墍浠12Y-X鐨勭粷瀵瑰=4 2.瑙ｇ瓟锛氳繛鎺E,鈭礑C鈭B锛屼笖DC=2FB锛屸埓鈻矰CE鐨勯潰绉埗鈻矪FE鐨勯潰绉=4鈭1锛屸埓璁锯柍BFE闈㈢Н=1锛屽垯鈻矰CE鐨勯潰绉...
绛旓細瑙ｅ緱x=28 鍗宠瀹氭椂闂翠负28澶╋紝鍥犱负24<28,鎵浠ョ敳锛屼箼涓ょ粍鍚堝彲浠ュ湪瑙勫畾鏃堕棿鍐呭畬鎴愩傦紙2锛夊厛姹傜敳銆佷箼涓ょ粍鍚堝仛瀹岃繖椤瑰伐绋嬬殑5/6鎵闇鐨勬椂闂 锛5/6锛/ {1/锛 2x+4 锛 + 1 / [2*锛2x+4锛 / 3] } =锛5/6锛/锛1/60 + 1/40锛=20澶 28 - 20 =8澶╋紝鎵浠ュ墿涓嬬殑1/6瑕8澶╁畬鎴 ...
绛旓細鍏斿瓙閫熷害 6x锛岀嫄鐙搁熷害 4x锛屾澗榧犻熷害 3x 4x-3x=14/1 x=14 (6x-4x)*0.5=2*14*0.5=14
绛旓細1銆佷粠棰樼洰鍙互鐭ラ亾,鐢蹭粠A鍑哄彂涓庝箼鐩搁亣鍚庨┈涓婂啀杩斿洖A,鑺辩殑鏃堕棿涓1.5*2=3灏忔椂,鑰岃繖娈垫椂闂翠箼浠嶣鍑哄彂,璧板埌璺濈A3km鐨勫湴鏂,鎵浠ヤ箼鐨勯熷害涓(27-3)/3=8(鍗冪背/灏忔椂),鐢茬殑閫熷害涓(27-8*1.5)/1.5=10(鍗冪背/灏忔椂)2銆佽鐏溅闀垮害涓篨,閫熷害涓篩 鍥犱负鐏溅浠庡紑濮嬩笂妗ュ埌瀹屽叏閫氳繃妗,杞﹀ご瀹為檯缁忚繃璺濈涓...
