设3×4矩阵A的各行元素之和为零,且A的3行向量线性无关,则齐次线性方程组AX=0的通解是x= 已知A是m*4阶矩阵,R(A)=3,且A的每行元素之和等于零...
\u8bbe\u77e9\u9635a3*4\u7684\u884c\u5411\u91cf\u6784\u6210\u7684\u5411\u91cf\u7ec4\u7ebf\u6027\u65e0\u5173.\u5219\u5176\u6b21\u7ebf\u6027\u65b9\u7a0b\u7ec4ax=0\u7684\u57fa\u7840\u89e3\u6240\u5305\u542b\u7684\u5411\u91cf\u4e2a\u6570\u56e0\u4e3aA\u7684\u884c\u5411\u91cf\u6784\u6210\u7684\u5411\u91cf\u7ec4\u7ebf\u6027\u65e0\u5173
\u6240\u4ee5 r(A)=3
\u6240\u4ee5 \u57fa\u7840\u89e3\u7cfb\u542b n-r(A) = 4-3 = 1 \u4e2a\u5411\u91cf
\u5404\u884c\u5143\u7d20\u4e4b\u548c\u4e3a\u96f6\u7684\u542b\u4e49\u5982\u56fe\uff0c\u53ef\u4ee5\u51d1\u51fa\u4e00\u4e2a\u57fa\u7840\u89e3\u7cfb\u3002\u7ecf\u6d4e\u6570\u5b66\u56e2\u961f\u5e2e\u4f60\u89e3\u7b54\uff0c\u8bf7\u53ca\u65f6\u91c7\u7eb3\u3002\u8c22\u8c22\uff01
x=K[1 1 1]T,,,,,,k取任意常数！
绛旓細include<iostream.h> void main(){ int array[3][4]={{1,3,5,7},{2,4,6,8},{1,2,3,4}};long int sum=0;for(int i=0;i<3;i++){ for(int j=0;j<4;j++){ if(i==0||j==0)sum=sum+array[i][j];else if(i==2)sum=sum+array[i][j];else if(j==3)sum=...
绛旓細鎴戞渶杩戝湪鐪婥++ C璇█涓嶄竴瀹氱敤鐨勫緢涓撲笟 瑙佽皡鍟婏紒include <stdio.h> void main(){ int array[3][4]={0};int i,j,sun=0;printf("Please input a array:\n");for(i=0;i<3;i++)for(j=0;j<4;j++)scanf("%d",&array[i][j]);printf("the array is over!\n");for(i=0;i...
绛旓細include<stdio.h> void main(){ int a[3][4]={3,5,6,8,2,1,4,9,8,7,1,6};int i,j,sum;for(i=0;i<3;i++){ for(j=0;j<4;j++){ printf("%4d",a[i][j]);} printf("\n");} printf("sum of the line:\n");for(i=0;i<3;i++){ for(j=0,sum=0;j<4...
绛旓細椤涔嬪拰 寮忎腑k1,k2,...,kn鏄皢搴忓垪1,2,...,n鐨勫厓绱娆″簭浜ゆ崲k娆℃墍寰楀埌鐨勪竴涓簭鍒,危鍙疯〃绀哄k1,k2,...,kn鍙栭亶1,2,...,n鐨勪竴鍒囨帓鍒楁眰鍜,閭ｆ湯鏁癉绉颁负n闃舵柟闃电浉搴旂殑琛屽垪寮.渚嬪,鍥闃惰鍒楀紡鏄4!涓舰涓 鐨勯」鐨勫拰,鑰屽叾涓璦13a21a34a42鐩稿簲浜巏=3,鍗宠椤瑰墠绔殑绗﹀彿搴斾负 (-1)3. 鑻闃舵柟闃礎=(...
绛旓細include "stdio.h"int main(int argc,char *argv[]){int m[3][4],i,j,s;double ave;printf("Input 12 numbers...\n");for(s=i=0;i<3;i++)for(j=0;j<4;j++){scanf("%d",m[i]+j);s+=m[i][j];}printf("\nThe AVE is %g\n",ave=s/12.0);printf("Larger than...
绛旓細int arry1[5]={1,3,5,7,9};int arry2[5]={2,4,6,8,10};int arry3[5]={3,5,8,7,6};int sum_row[3]={0*3};/*涓琛屽厓绱犱箣鍜*/int sum_column[5]={0*8};/*涓鍒楀厓绱犱箣鍜*/for(int i=0;i<5;i++){ sum_row[0]+=arry1[i]; sum_row[1]+=arry2[i]; sum_row[2]+=...
绛旓細琛屽悜閲忕粍鎸囩殑鏄煩闃垫瘡琛屾瀯鎴愪竴涓悜閲,鎵鏈夎鏋勬垚鐨勫悜閲忕殑鏁翠綋绉颁负涓涓鍚戦噺缁 鍒楀悜閲忕粍鎸囩殑鏄鐭╅樀姣鍒楁瀯鎴愪竴涓悜閲,鎵鏈夊垪鏋勬垚鐨勫悜閲忕殑鏁翠綋绉颁负涓涓垪鍚戦噺缁 渚嬪锛 缁欎綘涓涓鐭╅樀A A = 1 2 3 4 5 6 鍒A鐨琛屽悜閲忕粍涓: (1,2,3), (4,5,6)A鐨勫垪鍚戦噺缁勪负: (1,4)',(2...
绛旓細璁鐭╅樀A鏄痬脳n鐨勩佺煩闃礏鏄痭脳s鐨勶紝涔樻硶AB鍚庡緱鍒扮煩闃礐锛屽垯C涓簃脳s鐨勶紝濡備笅鍥炬墍绀恒傜煩闃礐鐨勭i琛岀j鍒楃殑鍏冪礌Cij灏辨槸鍙A鐨绗琲琛屽厓绱銆丅鐨勭j鍒楀厓绱狅紝鐒跺悗瀵瑰簲鐩镐箻銆備妇涓疄闄呯殑渚嬪瓙鏉ョ悊瑙ｄ竴涓嬶紝姣斿涓嬪浘鎵绀虹殑鐭╅樀涔樻硶銆侰11鏄敱A鐨勭涓琛屼笌B鐨勭涓鍒楀搴旂浉涔樺緱鍒扮殑锛屽嵆C11=1脳3+2脳1+4...
绛旓細include <conio.h> include <stdio.h> int fun(int a[3][3]){ int cnt=0;for(int i=0;i<3;i++){ cnt+=a[0][i];} return cnt;} int main(){ int a[3][3]={{1,2,3},{4,5,6},{7,8,9}};int i,j,sum;// clrscr();printf("array is:\n");for(i=0;i<...
绛旓細scanf("%d",&a[i][j]);max=min=a[0][0];for(i=0,i<3;i++)for(j=0;j<4;j++){ if(a[i][j]>max){ max=a[i][j];maxi=i+1;maxj=j+1;} if(a[i][j]<min){ min=a[i][j];mini=i+1;minj=j+1;} } printf("鏈澶у间负%d锛屽湪绗%d琛岋紝绗%d鍒楋紱\n鏈灏...
