实验室需要0.1摩尔每升氢氧化钠溶液100毫升,现有2mol/L氢氧化钠溶液。 (1)计算所需2mol/L氢氧化钠溶液...
\u662f\u5b9e\u9a8c\u5ba4\u9700\u89810.1mol\u6bcf\u5347\u7684\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2100mL\uff0c\u73b0\u67092MOL\u6bcf\u5347\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u3002 \u8ba1\u7b97\u6240\u97002M(1)0.1mol\L*0.1L=0.01mol
0.01mol\u9664\u4ee52mol/L=0.005L=5ml
(2)1mol\u786b\u9178\u9700\u89812molNaOH
\u53ef\u4ee5\u4e2d\u548c\u786b\u9178\u7269\u8d28\u7684\u91cf0.01mol\u9664\u4ee52=0.005mol
0.005mol\u9664\u4ee55mol/L=0.001L=1ml
\uff081\uff09\u8bbe\u6240\u97002mol/L\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u7684\u4f53\u79ef\u4e3aV\uff0c\u7531\u6eb6\u6db2\u914d\u5236\u524d\u540e\u6eb6\u8d28\u7684\u7269\u8d28\u7684\u91cf\u76f8\u7b49\uff0c\u52192mol/L\u00d7V=0.1mol/L\u00d70.1L\uff0c\u89e3\u5f97V=0.005L=5mL\uff1b \uff082\uff09\u8bbe\u9700\u89811mol/L\u7684\u76d0\u9178\u7684\u4f53\u79ef\u4e3ax\uff0c\u521950mL 0.1mol/L\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u4e3a0.005mol NaOH+HCl\u2550NaCl+H2O 1 10.005mol x\u00d71mol/L11\uff1d0.005molx\u00d71mol/Lx=0.005L=5mL\u7b54\u6848\uff1a\uff081\uff09\u6240\u9700 2mol/L\u6c22\u6c27\u5316\u94a0\u6eb6\u6db2\u7684\u4f53\u79ef5mL\uff082\uff09\u9700\u89811mol/L\u7684\u76d0\u91785mL
(1)稀释定律c浓V浓=c稀V稀 2mol/L*V浓= 0.1mol/L*100mL
(2) NaOH ~ HCl
1mol 1mol
0.1mol/L*0.05L 1mol/L*V(HCl)
0.1mol/L*0.05L = 1mol/L*V(HCl)
c1V1=c2V2 2V1=0.1*0.1
NaOH------------------HCl
1 1
0.05*0.1 1*V
V=100*0.1/2=5mL
绛旓細0.1mol/L*0.05L = 1mol/L*V(HCl)
绛旓細0.1鎽╁皵姣忓崌姘㈡哀鍖閽450ml,40*0.1*450/1000=1.8鍏 0.5鎽╁皵姣忓崌纭吀婧舵恫500ml,98*0.5*500/1000=24.5鍏
绛旓細0.1鎽╁皵姣忓崌NaOH婧舵恫50姣崌锛堝嵆0.05鍗囷級鎵濂絅aOH鐗╄川鐨勯噺涓 0.1脳0.05锛0.005mol 璁句腑鍜屾墍闇HCl鐗╄川鐨勯噺涓簒 mol銆侼aOH 锛 HCl锛 NaCl锛 H2O 1 : 1 0.005mol :x mol 璁＄畻寰梮锛0.005mol 0.005鎽╁皵HCl鎵闇1鎽╁皵姣忓崌鐩愰吀鐨勪綋绉负 0.005/1锛0.005鍗 鍗冲畬鍏ㄤ腑鍜50姣崌宸查厤缃...
绛旓細涓涓阿姘у寲閽犳秷鑰椾竴涓偦鑻簩鐢查吀姘㈤捑 NaOH鐗╄川鐨勯噺涓 0.1*0.02 鍒0.1*0.03 鍗抽偦鑻簩鐢查吀姘㈤捑 鐗╄川鐨勯噺涓0.1*0.02 鍒0.1*0.03 鍙堝叾鎽╁皵璐ㄩ噺涓 204.22 g/mol 鍒欒川閲忎负 0.41 g 鍒0.61 g涔嬮棿
绛旓細0.500L * 0.1mol/L * 40g/mol = 2g
绛旓細璁＄畻杩囩▼:V(H2O)=500ml=0.5L n(NaOH)= 0.1mol/L脳0.5L=0.05mol ,m(NaOH)=nM=0.05mol脳40g/mol=2g 閰嶇疆姝ラ:1.鎵樼洏澶╁钩涓婂厛绉板彇娲佸噣骞茬嚗鐑ф澂璐ㄩ噺绉板彇2gNaOH 2.鍚戠儳鏉姞閫傞噺钂搁姘寸敤鐜荤拑妫掓悈鎷屼娇鍏舵憾瑙ｅ苟浣垮叾鎭㈠瀹ゆ俯 3.婧舵恫娌跨幓鐠冩娉ㄥ叆500 mL 瀹归噺鐡 4.鐢ㄩ傞噺钂搁姘存礂娑ょ儳鏉2鑷3...
绛旓細鍏堢О閲40g鐨姘㈡哀鍖閽犲浐浣擄紝鐒跺悗鍙栬捀棣忔按鍜1L瀹氬鍣紝鐒跺悗灏嗘阿姘у寲閽犲浐浣撴憾瑙ｄ簬鐑ф澂涓紝鐒跺悗灏嗘憾娑插埌浜哄畾瀹瑰櫒涓紝涔嬪悗娲楁钉鐑ф澂鍜岀幓鐠冩鍐嶅掑叆瀹氬鍣ㄤ腑锛岀洿鍒板掓弧涓烘銆
绛旓細鎿嶄綔姝ラ锛氾紙1锛夎绠楋細璁＄畻閰嶅埗鎵闇鍥轰綋婧惰川鐨勮川閲忔垨娑蹭綋娴撴憾娑茬殑浣撶Н銆傛祿搴︿负37%鐨凥Cl鐨勭墿璐ㄧ殑閲忔祿搴︿负锛(37/36.5)/[锛100/1.18)脳10^-3]=12mol/L 0.1脳100脳10^-3锛12脳V V锛0.8ml 锛2锛夌О閲忥細閲忓彇娴撶洂閰0.8姣崌銆傦紙3锛夋憾瑙ｏ細绋閲婃憾璐紝鎭㈠鑷冲娓╋紝妫鏌ュ閲忕摱鏄惁婕忔按 锛4锛...
绛旓細1mol姘㈡哀鍖閽犱负40g,0.1mol涓4g,500ml涓2g
绛旓細璁＄畻杩囩▼锛 V锛圚2O锛=500ml=0.5L 锛宯(NaOH)= 0.1mol/L脳0.5L=0.05mol , m锛圢aOH锛=nM=0.05mol脳40g/mol=2g 閰嶇疆姝ラ锛1.鍦ㄦ墭鐩樺ぉ骞充笂鍏堢О鍙栨磥鍑骞茬嚗鐑ф澂鐨勮川閲忓悗绉板彇2gNaOH 2.鍚戠儳鏉腑鍔犻傞噺钂搁姘达紝鐢ㄧ幓鐠冩鎼呮媽锛屼娇鍏舵憾瑙ｏ紝骞朵娇鍏舵仮澶嶅娓 3.灏嗘憾娑叉部鐜荤拑妫掓敞鍏500 mL 瀹...
