六上年级数学计算阴影部分面积和周长

\u516d\u5e74\u7ea7\u4e0a\u518c\u6570\u5b66\u9634\u5f71\u90e8\u5206\u7684\u5468\u957f\u548c\u9762\u79ef

\u60a8\u597d\uff0c\u5bd2\u6a31\u6696\u6696\u4e3a\u4f60\u89e3\u7b54\uff1a

\u7b2c\u4e8c\u5f20\u7684\uff1a
2\u00d71/4\u00d73.14\u00d73\u00d73-3\u00d73
=14.13-9
=5.13\u5e73\u65b9\u5398\u7c73

\u5982\u679c\u4f60\u8ba4\u53ef\u6211\u7684\u56de\u7b54\uff0c
\u8bf7\u53ca\u65f6\u70b9\u51fb\u3010\u91c7\u7eb3\u4e3a\u6ee1\u610f\u56de\u7b54\u3011\u6309\u94ae\uff0c\uff08\u6216\u5728\u5ba2\u6237\u7aef\u53f3\u4e0a\u89d2\u8bc4\u4ef7\u70b9\u3010\u6ee1\u610f\u3011\uff09
\u4f60\u7684\u91c7\u7eb3\uff0c
\u662f\u6211\u524d\u8fdb\u7684\u52a8\u529b! \u4e5f\u4f1a\u7ed9\u4f60\u5e26\u53bb\u8d22\u5bcc\u503c\u7684\u3002
\u5982\u6709\u4e0d\u660e\u767d\uff0c
\u53ef\u4ee5\u8ffd\u95ee\uff0c\u76f4\u5230\u5b8c\u6210\u5f04\u61c2\u6b64\u9898!
==================================================
\u91c7\u7eb3\u4e86\uff0c\u6211\u53ef\u4ee5\u3010\u518d\u5e2e\u4f60\u505a\u7b2c\u4e00\u5f20\u7684\u90a3\u9898\u3011\uff01\uff01\uff01
\u91c7\u7eb3\u540e\uff0c\u8fd8\u8981\u8ffd\u95ee\u54df\uff0c\uff08\u53ef\u4ee5\u53ea\u53d1\u4e00\u4e2a\u95ee\u53f7\u3002\uff09\u4e0d\u7136\u5e2e\u4e0d\u5230\u4f60\u3002
==================================================

\u7b2c\u4e00\u9898\uff1a\u5468\u957f\u4e3a6\u00d73.14\uff0b6\uff0b6\uff1d30.84 \u9762\u79ef\u4e3a36-9\u00d73.14\uff1d7.74 \u7b2c\u4e8c\u9898\uff1a\u5468\u957f\u4e3a3.14\u00d74\u00f72+2+2+4\uff1d14.28 \u9762\u79ef\u4e3a2\u00d74-4\u00f72\u00d73.14\uff1d1.72

解:
左右两个半圆合起来刚好是一个圆
阴影部分面积
=4×4-π×(4÷2)²
=16-4π

阴影部分周长
=π×4+4+4
=4π+8

面积:10*10-25π
=100-25π
周长:10π+2*10
=10π+20
π按照题目中所要的取值

C=10+10+10×3.14=51.4cm
S=10×10-(10÷2)²×3.14=21.5cm²

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