根号3sinx-cosx咋化简? 根号(3sinx+cosx)怎么化简?

\u6839\u53f73sinx+cosx\u5982\u4f55\u5316\u7b80

\u89e3\u221a3sinx+cosx
=2\uff08\u221a3/2sinx+1/2cosx\uff09
=2\uff08cos\u03c0/6sinx+sin\u03c0/6cosx\uff09
=2sin\uff08x+\u03c0/6)

\u6839\u53f7\uff083sinx+cosx\uff09
=\u6839\u53f7[\u6839\u53f7\uff083^2+1^2\uff09\uff083/(\u6839\u53f73^2+1^2)\uff09sinx+1/(\u6839\u53f73^2+1^2)cosx]
=\u6839\u53f7[\u6839\u53f710\uff08\uff083/\u6839\u53f710\uff09sinx+1/\u6839\u53f710cosx\uff09]
\u4ee43/\u6839\u53f710=cos\u03b1\uff0c1/\u6839\u53f710=sin\u03b1 \u5219tan\u03b1=1/3
\u539f\u5f0f=\u6839\u53f7\uff08\u6839\u53f710sin(x+\u03b1)\uff09=10\u6839\u53f7\uff08sin\uff08x+\u03b1\uff09

√3sinx-cosx
=2(sinxcosπ/6-cosxsinπ/6)
=2sin(x-π/6)

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