怎样用maple求解隐函数方程和含参的积分。 请问用Maple（或者别的数学软件也可以）怎么绘制隐函数方程...
Maple \u5fae\u5206\u65b9\u7a0b\u89e3\u5305\u542b\u79ef\u5206\u7b26\u53f7\u600e\u4e48\u529e?\u81ea\u5df1\u5148\u6c42\u5bfc\u554a
\u4e8c\u5143\u51fd\u6570\u56fe\u50cf\u662f\u4e8c\u6b21\u66f2\u9762\uff0c\u4e0d\u662f\u66f2\u7ebf\u3002Maple \u7ed8\u56fe\u547d\u4ee4\u5982\u4e0b\uff1a
with(plots):
implicitplot3d(z = x^2+y^2, x = -2 .. 2, y = -2 .. 2, z = 0 .. 4, scaling = constrained, axes = boxed, grid = [20, 20, 20], title = (z = x^2+y^2))
\u8fd9\u4e2a\u662f\u692d\u5706\u629b\u7269\u9762
implicitplot3d(x^2+2*y^2+3*z^2 = 20, x = -5 .. 5, y = -4 .. 4, z = -3 .. 3, scaling = constrained, axes = boxed, grid = [15, 15, 15], title = (x^2+2*y^2+3*z^2 = 20))
\u8fd9\u4e2a\u662f\u692d\u7403\u9762
因为不知道你的J(x)具体表达式是什么，只能举例说明了
积分函数int，比如要求sin(x)的积分，则int(sin(x),x)即可
若要求sin(x)在区间(-1,1)上的定积分则写作int(sin(x),x=-1..1)
solve函数的语法就是solve(方程,未知数)，比如求方程x^2-x-1=0的解，写作solve(x^2-x-1=0,x)
假设你的J(x)是a*sin(x)/x在区间(0,正无穷)上的积分，那么你的问题可写作
solve(x^2=3-2*int(a*sin(x)/x,x=0..infinity),x)
绛旓細maple瑙ｆ柟绋涓鑸敤solve鍑芥暟锛岀Н鍒嗗嚱鏁版槸int 鍥犱负涓嶇煡閬撲綘鐨凧(x)鍏蜂綋琛ㄨ揪寮忔槸浠涔堬紝鍙兘涓句緥璇存槑浜 绉垎鍑芥暟int锛屾瘮濡傝姹俿in(x)鐨勭Н鍒嗭紝鍒檌nt(sin(x),x)鍗冲彲 鑻ヨ姹俿in(x)鍦ㄥ尯闂(-1,1)涓婄殑瀹氱Н鍒嗗垯鍐欎綔int(sin(x),x=-1..1)solve鍑芥暟鐨勮娉曞氨鏄痵olve(鏂圭▼,鏈煡鏁)锛屾瘮濡姹傛柟绋x^2-x-1=...
绛旓細implicitplot((x^2+y^3)+15=5*x*y, x=-10..25, y=-10..10,grid=[100,100]);
绛旓細灏鏂圭▼绉婚」骞跺彇骞虫柟锛(r-z)^2-(-b+sqrt(R*R-z*z))^2 = (a-x)^2 绉婚」骞跺睍寮锛歜^2 + (R^2-z^2) - 2*b*sqrt(R*R-z*z) = (r-z)^2 - (a-x)^2 鍐嶇Щ椤癸紝鍙栧钩鏂癸細(b^2 + (R^2-z^2) - (r-z)^2 + (a-x)^2)^2 = 4*b^2*(R*R-z*z)鐢辨寰楀埌鐨勬槸...
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绛旓細> dy/dx = implicitdiff(x²+y² = 9, y, x);dy x -- = - - dx y > dy/dx = implicitdiff(x²+y² = a, y, x);dy x -- = - - dx y diff 鐢ㄤ簬鏄惧嚱鏁版眰瀵硷紝闅愬嚱鏁姹傚搴旇鐢 implicitdiff(f, y, x)
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绛旓細鍋闅愬嚱鏁鏈変竴浜涚壒瀹氱殑鍛戒护杩涜浣跨敤锛maple鐨勫畼缃戦噷闈㈡湁涓绡囨槸浠嬬粛杩欎釜鐨勶紝锛坢aple銆俶akeding銆俢om锛変絾鏄瘮杈冪畝鍗曪紝浣犳垨鑰呬篃鍙互鍒癿aple鎶鏈氦娴佺兢閲岄潰鍘昏鏁欎竴浜涘ぇ绁炰滑鐪嬬湅銆
绛旓細鍏堟妸鍑芥暟杈撹繘鍘伙紝渚嬪杈撳叆y=x锛屾寜鍥炶溅銆傚簲璇ヤ細鍑烘潵涓涓摑鑹茬殑鍑芥暟寮忋傚彸閿偣鍑昏繖涓嚱鏁板紡锛岄夋嫨2-D Implicit Plot閲岀殑x锛寉
绛旓細鏂规硶涓锛氬彲浠ョ敤isosurface缁樺埗涓夎缃戞牸鍥俱傛瘮濡傜粯鍒闅愬嚱鏁(x^2+(9/4)*y^2+z^2-1)^3=x^2*z^3+(1/9)*y^2*z^3鐨勫浘鍍忥紙涓棰楃埍蹇冿級[x,y,z]=meshgrid(linspace(-1.3,1.3));val=(x.^2 + (9/4)*y.^2 + z.^2 - 1).^3 - x.^2.*z.^3 - (1/9)*y.^2.*z.^3;...
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