高一数学因式分解三次方的怎么做啊？ X^3+X^2-2=? 做.为什么2的x次方+3的x次方
\u5206\u89e3\u56e0\u5f0f:\uff08x²-3\uff09²-x\uff08x²-3\uff09-2x²\u8fd9\u9898\u600e\u4e48\u505a\u3000\u3000\uff08x²-3\uff09²-x\uff08x²-3\uff09-2x²
\u3000\u3000=(x²-3-2x)(x²-3+x)
\u3000\u3000=(x-3)(x+1)(x²-3+x)
\u4f60\u8fd9\u91cc\u662f\u505a\u6c42\u5bfc\u8fd8\u662f\u79ef\u5206\uff1f
\u8bb0\u4f4f\u57fa\u672c\u516c\u5f0f(a^x)'=lna *a^x
\u6240\u4ee52^x+3^x\u6c42\u5bfc\u5f97\u5230ln2 *2^x+ln3 *3^x
\u540c\u7406\u5982\u679c\u662f\u79ef\u5206
\u5c31\u662f1/ln2 *2^x+1/ln3 *3^x
x^3+x²-2=0
x^3-1+x²-1=0
(x-1)(x²+x+1)+(x+1)(x-1)=0
(x-1)(x²+x+1+x+1)=0
(x-1)(x²+2x+2)=0
x²+2x+2在实数范围内无法分解
x-1=0
x=1
(x-1)(x﹡2+2x+2）……高三表示无压力……
x=1方程为0，所以有（x-1)因式
X^3+X^2-2
=x^3-x^2+2(x^2-1)
=(x-1)x^2+(x-1)*2(x+1)
=(x-1)(x^2+2x+2)
2x^3+3X^2-1怎么分解因式，
x=-1方程=0，必有（x+1）因式
X^3-2X+1怎么分解因式
x=1方程为0，所以有（x-1)因式
x+x-2=(x-1)+(x-1)=(x-1)(x+x+1)+(x-1)(x+1)=(x-1)(x+2x+2)!
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