数学题:乙给甲1个,甲比乙多1。甲给乙1个,乙比甲多一半。求甲乙各是多少 甲给乙一分,甲比乙多一分,乙给甲一分,是甲的一半。求甲乙是几...
\u6570\u5b66\u9898:\u4e59\u7ed9\u75321\u4e2a\uff0c\u7532\u6bd4\u4e59\u591a1\u3002\u7532\u7ed9\u4e591\u4e2a\uff0c\u4e59\u6bd4\u7532\u591a\u4e00\u534a\u3002\u6c42\u7532\u4e59\u5404\u662f\u4e59\u7ed9\u75321\u4e2a\uff0c\u7532\u6bd4\u4e59\u591a1\uff0c\u8bf4\u660e\u4e59\u6bd4\u7532\u591a1\u4e2a\u3002\u7532\u7ed9\u4e591\u4e2a\uff0c\u4e59\u6bd4\u7532\u591a\u4e00\u534a\u4e5f\u5c31\u662f\u591a3\u4e2a\uff0c\u6240\u4ee5\u7532\u67093*2+1=7\u4e2a\uff0c\u4e59\u67097+1=8\u4e2a
\u7532x
\u4e59y
x-1-(y+1)=1
x-y=3
2*(y-1)=x+1
2y-x=3
y=6
x=9
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绛旓細涔欑粰鐢1涓紝鐢叉瘮涔欏1锛岃鏄庝箼姣旂敳澶1涓鐢茬粰涔1涓锛屼箼姣旂敳澶氫竴鍗婁篃灏辨槸澶3涓紝鎵浠ョ敳鏈3*2+1=7涓紝涔欐湁7+1=8涓
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绛旓細涔欐瘮鐢茶吹涓鍊 鐢叉瘮涔渚垮疁涓鍗,涔欐槸鏁翠綋 涔欐瘮鐢茶吹澶氬皯锛岀敳鏄暣浣
绛旓細濡傛灉鐢茬粰涔欓1棰,涓や汉灏变竴鏍峰,璇存槑鍘熸潵鐢叉瘮涔澶氾細1鍗1=2锛堥锛夊鏋涔欑粰鐢1棰楃敳鐨勯鏁板氨鏄箼鐨2鍊 灏辨槸涔欏噺灏1,鐢插鍔1,鐢插氨姣斾箼澶氾細2鍗1鍗1=4锛堥锛夎繖鏃剁敳姣斾箼澶氾細2-1=1锛堝嶏級鎵浠 涔欙紙1鍊嶏級鏈4棰,鐢叉湁4x2=8锛堥锛
绛旓細璁惧師鏉ョ敳鏈墄鍙緤锛屼箼y鍙緤 {x-1=y+1 x+1=2(y-1)瑙ｅ緱x=7,y=5 鍘熸潵鐢叉湁7鍙緤锛屼箼5鍙緤
绛旓細鐢叉瘮涔欏1+1=2妫 鐜板湪鐢叉瘮涔欏2+1+1=4妫 鎵浠ョ幇鍦ㄤ箼鏄4梅锛2-1锛=4妫 鎵浠ュ師鏉ヤ箼4+1=5妫 鐢5+2=7妫
绛旓細棰樼洰鍙兘鏄繖鏍凤細鐢蹭箼涓璧烽挀楸.鐢茶锛氣滃鏋滀綘鎺夌殑楸肩粰鎴戜竴鏉,鎴戠殑楸煎氨姣斾綘澶氫竴鍊.鈥濅箼璇达細鈥滀綘缁欐垜涓鏉″挶淇╁氨涓鏍峰.鈥濋棶锛氱敳銆佷箼鍚勮皟鍑犳潯楸?鏅氬仛娉锛氱敳姣斾箼澶1+1=2鏉 姝ゆ椂灏嗕箼鐪嬩綔1鍊嶆暟,涔欑粰鐢1鏉,鐢叉瘮涔欏2+1脳2=4鏉 閭ｄ箞姝ゆ椂涔欐湁4/1=4鏉 鍘熸潵涔欐湁4+1=5鏉 鍘熸潵鐢叉湁5+...
绛旓細瑙ｏ細璁剧敳鐗х鏈塜鍙緤銆傚垯涔欐湁X-2鍙2(X-2-1)=X+1 2X-4-2=X+1 X=4+2+1 X=7 7-2=5锛堝彧锛夊鏋滀綘璁ゅ彲鎴戠殑鍥炵瓟锛岃鍙婃椂鐐瑰嚮閲囩撼涓恒愭弧鎰忓洖绛斻戞寜閽 鎵嬫満鎻愰棶鑰呭湪瀹㈡埛绔彸涓婅璇勪环鐐光滄弧鎰忊濆嵆鍙備綘鐨勯噰绾虫槸鎴戝墠杩涚殑鍔ㄥ姏! 濡傝繕鏈夋柊鐨勯棶棰橈紝璇峰彟澶栧悜鎴戞眰鍔╋紝绛旈涓嶆槗锛岃阿璋㈡敮鎸佲...
绛旓細鐢叉湁涓鍙锛屼箼鏈変袱鍙
绛旓細鐢瞲 涔y x-1-(y+1)=1 x-y=3 2*(y-1)=x+1 2y-x=3 y=6 x=9 甯屾湜鎴戠殑鍥炵瓟鍙互甯埌浣狅紝璇烽噰绾筹紝涓囧垎鎰熻阿\(^o^)/
