请问用java怎么判断输入是否为数字和英文字母,如果不是就提示输入错误? 在C语言中如何判断输入的是否为英文字母?

\u8bf7\u95ee\u7528java\u600e\u4e48\u5224\u65ad\u8f93\u5165\u662f\u5426\u4e3a\u6570\u5b57\u548c\u82f1\u6587\u5b57\u6bcd\uff0c\u5982\u679c\u4e0d\u662f\u5c31\u63d0\u793a\u8f93\u5165\u9519\u8bef\uff1f

\u7528\u6b63\u5219\u8868\u8fbe\u5f0f\u5339\u914d\u3002
\u6bd4\u5982\u8f93\u5165\u4e3aString
s\uff0cs.matches("[0-9a-zA-Z]*")\u8fd4\u56detrue\uff0c\u5c31\u53ef\u4ee5\u4e86\uff5e

\uff1a#include
isalnum() \u7528\u6765\u5224\u65ad\u4e00\u4e2a\u5b57\u7b26\u662f\u5426\u4e3a\u82f1\u6587\u5b57\u6bcd\u6216\u6570\u5b57\uff0c\u76f8\u5f53\u4e8e isalpha(c) || isdigit(c)\uff0c\u5176\u539f\u578b\u4e3a\uff1a
int isalnum(int c);
\u3010\u53c2\u6570\u3011c \u4e3a\u9700\u8981\u68c0\u6d4b\u7684\u5b57\u7b26\u3002
\u3010\u8fd4\u56de\u503c\u3011\u82e5\u53c2\u6570c \u4e3a\u5b57\u6bcd\u6216\u6570\u5b57\uff0c\u82e5 c \u4e3a 0 ~ 9 a ~ z A ~ Z \u5219\u8fd4\u56de\u975e 0\uff0c\u5426\u5219\u8fd4\u56de 0\u3002\u6ce8\u610f\uff0cisalnum()\u4e3a\u5b8f\u5b9a\u4e49\uff0c\u975e\u771f\u6b63\u51fd\u6570\u3002
\u3010\u5b9e\u4f8b\u3011\u627e\u51fastr \u5b57\u7b26\u4e32\u4e2d\u4e3a\u82f1\u6587\u5b57\u6bcd\u6216\u6570\u5b57\u7684\u5b57\u7b26\u3002
#include main(){char str[] = "123c@#FDsP[e?";int i;for (i = 0; str[i] != 0;
i++)if(isalnum(str[i]))printf("%c is an alphanumeric character\n", str[i]);}
#include
main(){
char str[] = "123c@#FDsP[e?";
int i;
for (i = 0; str[i] != 0; i++)
if(isalnum(str[i]))
printf("%c is an alphanumeric character\n", str[i]);}
\u8f93\u51fa\u7ed3\u679c\uff1a1 is an apphabetic character
2 is an apphabetic character
3 is an apphabetic character
c is an apphabetic character
F is an apphabetic character
D is an apphabetic character
s is an apphabetic character
P is an apphabetic character
e is an apphabetic character

用正则表达式匹配。
比如输入为String s,s.matches("[0-9a-zA-Z]*")返回true,就可以了~

(1)字符串操作,获得密码框里的字符,分割开....(2)判断每次输入时按下的键值【ASCII码】(3)正则表达式。提倡(3)。

可以根据 国际标准码 判断

这里的输入指的是从哪里输入呢???流??输入框(b/c)??

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