求高人将同花顺天狼剑搞成一个选股公式,当股价跌至指标停损下限附近又阳线反包,发岀买入信号。谢谢。

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XG:CROSS(3*SMA((CLOSE-LLV(LOW,27))/(HHV(HIGH,27)-LLV(LOW,27))*100,5,1)-2*SMA(SMA((CLOSE-LLV(LOW,27))/(HHV(HIGH,27)-LLV(LOW,27))*100,5,1),3,1),10);


VAR1:=EMA(HHV(HIGH,500),21); VAR2:=EMA(HHV(HIGH,250),21); VAR3:=EMA(HHV(HIGH,90),21); VAR4:=EMA(LLV(LOW,500),21); VAR5:=EMA(LLV(LOW,250),21); VAR6:=EMA(LLV(LOW,90),21); VAR7:=EMA((VAR4*0.96+VAR5*0.96+VAR6*0.96+VAR1*0.558+VAR2*0.558+VAR3*0.558)/6,21); VAR8:=EMA((VAR4*1.25+VAR5*1.23+VAR6*1.2+VAR1*0.55+VAR2*0.55+VAR3*0.65)/6,21); VAR9:=EMA((VAR4*1.3+VAR5*1.3+VAR6*1.3+VAR1*0.68+VAR2*0.68+VAR3*0.68)/6,21); VARA:=EMA((VAR7*3+VAR8*2+VAR9)/6*1.738,21); VARB:=REF(LOW,1); VARC:=SMA(ABS(LOW-VARB),3,1)/SMA(MAX(LOW-VARB,0),3,1)*100; VARD:=EMA(IF(CLOSE*1.350;

\u8981\u505a\u6210\u4e8c\u4e2a\u516c\u5f0f\u624d\u53ef\u4ee5\u5b9e\u73b0\uff0c\u4e00\u4e3a\u9009\u80a1\u5982\u4e0b
A1:=COUNT(MA(C,5)>REF(MA(C,5),1) AND MA(C,10)>REF(MA(C,10),1) AND MA(C,30)>REF(MA(C,30),1),7)=7;
A2:=COUNT(MA(C,5)>REF(MA(C,5),1) AND MA(C,30)>REF(MA(C,30),1) AND MA(C,125)>REF(MA(C,125),1),7)=7;
A3:=COUNT(MA(C,10)>REF(MA(C,10),1) AND MA(C,30)>REF(MA(C,30),1) AND MA(C,125)>REF(MA(C,125),1),7)=7;

XG:COUNT(A1 OR A2 OR A3,30)=1;

=============
\u53e6\u4e00\u4e3a\u6307\u6807\u516c\u5f0f\u5982\u4e0b(\u6ce8\u610f\uff1a\u6700\u597d\u628a\u5b83\u8bbe\u7f6e\u4e3a\u4e3b\u56fe\u6307\u6807)
A1:=COUNT(MA(C,5)>REF(MA(C,5),1) AND MA(C,10)>REF(MA(C,10),1) AND MA(C,30)>REF(MA(C,30),1),7)=7;
A2:=COUNT(MA(C,5)>REF(MA(C,5),1) AND MA(C,30)>REF(MA(C,30),1) AND MA(C,125)>REF(MA(C,125),1),7)=7;
A3:=COUNT(MA(C,10)>REF(MA(C,10),1) AND MA(C,30)>REF(MA(C,30),1) AND MA(C,125)>REF(MA(C,125),1),7)=7;

XG:=COUNT(A1 OR A2 OR A3,30)=1;
DRAWTEXT(XG=1,LOW,'\u2191');

\u7528\u6cd5\uff1a\u5148\u7528\u9009\u80a1\u516c\u5f0f\u9009\u80a1\uff0c\u7136\u540e\u518d\u7528\u6307\u6807\u516c\u5f0f\u89c2\u5bdf\u3002

XXX:=1;
B1:=MA(C,1);
B2:=SMA(SMA(SMA(B1,2,1),2,1),2,1)*XXX;
SMA2:=MA(B2,3)*XXX;
停损下限:=IF(LLV(MA(B2,8),3)<B2,LLV(MA(B2,8),3),B2)*XXX;
SNAKEA:=HHV(MA(B2,1),13);
XG:B2>停损下限 AND REF(B2,1)=REF(停损下限,1);

B1:=MA(C,1);
B2:=SMA(SMA(SMA(B1,2,1),2,1),2,1);
SMA2:=MA(B2,3);
停损下限:=IF(LLV(MA(B2,8),3)<B2,LLV(MA(B2,8),3),B2);
XG:L<=停损下限 AND CROSS(C,停损下限);
{个人看法,仅供参考。}

可以吗

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