Cu、Cu2O和CuO组成的混合物，加入100mL 0.6mol/LHNO3溶液恰好使混合物溶解，同时收集到224mLNO气体（标准 氢气还原氧化铜所得的红色固体可能是铜与氧化亚铜的混合物，已知...
\u73b0\u6709Cu\u3001Cu2O\u548cCuO\u7ec4\u6210\u7684\u6df7\u5408\u7269\uff0c\u67d0\u7814\u7a76\u6027\u5b66\u4e60\u5c0f\u7ec4\u4e3a\u4e86\u63a2\u7a76\u5176\u7ec4\u6210\u60c5\u51b5\uff0c\u52a0\u5165100mL0.6mol/LHNO3\u6eb6\u6db2\u6070\u597d\u4f7f\u6807\u51c6\u72b6\u51b5\u4e0b224mLNO\u6c14\u4f53\u7684\u7269\u8d28\u7684\u91cf\u4e3a\uff1a0.224L22.4L/mol=0.01mol\uff0c\u785d\u9178\u4e0eCu\u3001Cu2O\u548cCuO\u7ec4\u6210\u7684\u6df7\u5408\u7269\u6070\u597d\u53cd\u5e94\uff0c\u751f\u6210Cu\uff08NO3\uff092\u4e0eNO\uff0c\u6839\u636e\u6c2e\u5143\u7d20\u5b88\u6052\u53ef\u77e5n[Cu\uff08NO3\uff092]=12[n\uff08HNO3\uff09-n\uff08NO\uff09]=12\uff080.1L\u00d70.6mol/L-0.01mol\uff09=0.025mol\uff0c\u6839\u636e\u7535\u5b50\u8f6c\u79fb\u5b88\u6052\u67092n\uff08Cu\uff09+2n\uff08Cu2O\uff09=3n\uff08NO\uff09\uff0c\u65450.01mol\u00d72+2n\uff08Cu2O\uff09=3\u00d70.01mol\uff0c\u89e3\u5f97n\uff08Cu2O\uff09=0.005mol\uff0c\u6839\u636e\u94dc\u5143\u7d20\u5b88\u6052\u53ef\u77e5n\uff08CuO\uff09=n[Cu\uff08NO3\uff092]-n\uff08Cu\uff09-2n\uff08Cu2O\uff09=0.025mol-0.01mol-2\u00d70.005=0.005mol\uff0c\u6545m\uff08Cu2O\uff09\uff1an\uff08CuO\uff09=0.005mol\u00d7144g/mol\uff1a0.005mol\u00d780g/mol=9\uff1a5\uff0c\u6545\u7b54\u6848\u4e3a\uff1a0.025mol\uff1b9\uff1a5\uff0e
\uff081\uff09n\uff08CuO\uff09=8.4g80g/mol=0.105mol\uff0c\u6c27\u5143\u7d20\u7684\u7269\u8d28\u7684\u91cf=n\uff08CuO\uff09\u2550\u94dc\u5143\u7d20\u7684\u7269\u8d28\u7684\u91cf=0.105mol\uff1b\u56fa\u4f53\u7531CuO\u751f\u6210Cu\u548cCu2O\uff0c\u51cf\u5c11\u7684\u8d28\u91cf\u4e3a\u6c27\u5143\u7d20\u7684\u8d28\u91cf\uff0c\u53738.4g-6.96g=1.44g\uff0c\u51cf\u5c11\u7684\u6c27\u5143\u7d20\u7684\u7269\u8d28\u7684\u91cf=1.44g16g/mol=0.09mol\uff0c\u6240\u4ee5Cu2O\u4e2d\u6c27\u5143\u7d20\u7684\u7269\u8d28\u7684\u91cf=0.105mol-0.09mol=0.015mol\uff0c\u6240\u4ee5n\uff08Cu2O\uff09=0.015mol\uff0c\u6839\u636e\u94dc\u5143\u7d20\u5b88\u6052\u5f97n\uff08Cu\uff09=0.105mol-2\u00d70.015mol=0.075mol\uff0c\u6240\u4ee5\u5355\u8d28\u94dc\u4e0e\u6c27\u5316\u4e9a\u94dc\u7684\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4\u662f5\uff1a1\uff0e\u6545\u7b54\u6848\u4e3a\uff1a5\uff1a1\uff0e\uff082\uff09\u2460n\uff08Cu\uff09=0.105mol-2\u00d70.015mol=0.075mol\uff0c\u6240\u4ee5m\uff08Cu\uff09=0.075mol\u00d764g/mol=4.8g\uff0c\u6c27\u5316\u4e9a\u94dc\u7684\u8d28\u91cf=6.96g-4.8g=2.16g\uff0e\u6c27\u5316\u4e9a\u94dc\u548c\u7a00\u786b\u9178\u53cd\u5e94\uff0c\u94dc\u548c\u7a00\u786b\u9178\u4e0d\u53cd\u5e94\uff0c\u8bbe\u6c27\u5316\u4e9a\u94dc\u548c\u7a00\u786b\u9178\u53cd\u5e94\u751f\u6210\u94dc\u7684\u8d28\u91cf\u4e3ax\uff0e\u6c27\u5316\u4e9a\u94dc\u548c\u7a00\u786b\u9178\u53cd\u5e94\u7684\u65b9\u7a0b\u5f0f\u4e3a\uff1aCu2O+H2SO4=CuSO4+Cu+H2O144g 64g2.16g xx=0.96g\u6240\u4ee5\u53ef\u5f97\u5230\u56fa\u4f53\u7684\u8d28\u91cf=4.8g+0.96g=5.76\u514b\u901a\u8fc7\u5206\u6790\u77e5\uff0c6.96\u514b\u7684\u94dc\u548c\u6c27\u5316\u4e9a\u94dc\u7684\u6df7\u5408\u7269\u4e0e\u785d\u9178\u53cd\u5e94\u76f8\u5f53\u4e8e5.76\u514b\u7684\u94dc\u4e0e\u785d\u9178\u53cd\u5e94\uff0e\u8bbe\u94dc\u4e0e\u785d\u9178\u53cd\u5e94\u5168\u90e8\u751f\u6210\u4e8c\u6c27\u5316\u6c2e\uff0c\u4e8c\u6c27\u5316\u6c2e\u7684\u4f53\u79ef\u4e3a\uff1aCu+4HNO3=Cu\uff08NO3\uff092+2NO2 \u2191+2H2O 64g 44.8L5.76 4.032L \u8bbe\u94dc\u4e0e\u785d\u9178\u53cd\u5e94\u5168\u90e8\u751f\u6210\u4e00\u6c27\u5316\u6c2e\uff0c\u4e00\u6c27\u5316\u6c2e\u7684\u4f53\u79ef\u4e3a\uff1a3Cu+8HNO3=3Cu\uff08NO3\uff092+2NO\u2191+4H2O192g 44.8L5.76 1.344L 1.344L\uff1c1.568l\uff1c4.032L\uff0c\u6240\u4ee5\u8be5\u6c14\u4f53\u662f\u4e8c\u6c27\u5316\u6c2e\u548c\u4e00\u6c27\u5316\u6c2e\u7684\u6df7\u5408\u7269\uff0e\u8bbe\u751f\u6210\u4e00\u6c27\u5316\u6c2e\u7684\u7269\u8d28\u7684\u91cf\u4e3aymol\uff0c\u751f\u6210\u4e8c\u6c27\u5316\u6c2e\u7684\u7269\u8d28\u7684\u91cf\u4e3azmol\uff0e3Cu+8HNO3=3Cu\uff08NO3\uff092+2NO\u2191+4H2O 192g 2mol 96yg ymolCu+4HNO3=Cu\uff08NO3\uff092+2NO2 \u2191+2H2O64g 2mol32zg zmoly+z=1.56822.4mol=0.07mol\uff0c96y+32z=5.76\uff0c\u89e3\u5f97y=0.055mol\uff0cz=0.015mol\uff0cy\uff1az=11\uff1a3\u6240\u4ee5\u4e00\u6c27\u5316\u6c2e\u548c\u4e8c\u6c27\u5316\u6c2e\u7684\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4\u4e3a11\uff1a3\uff0e\u6545\u7b54\u6848\u4e3a\uff1aNO\u3001NO2\uff1b 11\uff1a3\uff0e \u2461\u6839\u636e\u94dc\u5143\u7d20\u5b88\u6052\u77e5\uff0c\u6c27\u5316\u94dc\u4e2d\u7684\u94dc\u5168\u90e8\u8f6c\u5316\u4e3a\u785d\u9178\u94dc\u4e2d\u7684\u94dc\u79bb\u5b50\uff0c\u4e3a0.105mol\uff0c\u539f\u6eb6\u6db2\u4e2d\u7684Cu2+\u670920%\u6b8b\u7559\u5728\u6bcd\u6db2\u4e2d\uff0c\u6240\u4ee5\u6676\u4f53\u4e2d\u94dc\u79bb\u5b50\u7684\u7269\u8d28\u7684\u91cf\u4e3a0.084mol\uff0c\u6839\u636e\u5316\u5b66\u5f0f\u77e5\uff0c\u6676\u4f53\u4e2d\u785d\u9178\u94dc\u7684\u7269\u8d28\u7684\u91cf=\u94dc\u79bb\u5b50\u7684\u7269\u8d28\u7684\u91cf=0.084mol\uff0cm\uff08Cu\uff08NO3\uff092\uff09=0.084mol\u00d7188g/mol=15.792g\uff1c20.328g\uff0c\u6240\u4ee5\u6676\u4f53\u4e2d\u6709\u6c34\uff0c\u6c34\u7684\u7269\u8d28\u7684\u91cf=20.328g?15.792g18g/mol=0.252mol\uff0c\u785d\u9178\u94dc\u4e0e\u6c34\u7684\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4=0.084mol\uff1a0.252mol=1\uff1a3\uff0c\u6240\u4ee5\u5176\u5316\u5b66\u5f0f\u4e3aCu\uff08NO3\uff092?3H2O\uff0e\u6545\u7b54\u6848\u4e3a\uff1aCu\uff08NO3\uff092?3H2O\uff1b\uff083\uff09\u7531Cu\u5143\u7d20\u5b88\u6052\u53ef\u5f97\uff1a2\u00d7n\uff08Cu20\uff09+n\uff08CuO\uff09+X=0.025mol\uff0c\u7531\u6c27\u5316\u8fd8\u539f\u53cd\u5e94\u5f97\u5931\u7535\u5b50\u5b88\u6052\u53ef\u77e5\uff1aX\u00d72+2\u00d7n\uff08Cu20\uff09=0.224L22.4L/mol\uff0c\u89e3\u4e4b\u5f97\uff1an\uff08CuO\uff09=X-0.005mol\uff0cn\uff08Cu20\uff09=0.015mol-X\uff0c\u52190.005mol\uff1cX\uff1c0.015mol\uff0c\u7b54\uff1a\u5176\u4e2dCu20\u3001CuO\u7684\u7269\u8d28\u7684\u91cf\u4e3a\uff1an\uff08CuO\uff09=X-0.005mol\uff0cn\uff08Cu20\uff09=0.015mol-X\uff0cX\u7684\u53d6\u503c\u8303\u56f4\u4e3a0.005mol\uff1cX\uff1c0.015mol\uff0e
硝酸具有强氧化性，硝酸与Cu、Cu2O和CuO组成的混合物恰好反应，生成Cu（NO3）2与NO，标准状况下224mLNO气体的物质的量为：| 0.224L |
| 22.4L/mol |
A．根据N元素守恒2n[Cu（NO3）2]+n（NO）=n（HNO3），可知n[Cu（NO3）2]=
| 1 |
| 2 |
| 1 |
| 2 |
B．由Cu元素守恒可得：2×n（Cu2O）+n（CuO）+x=0.025mol，由氧化还原反应得失电子守恒可知：x×2+2×n（Cu2O）=0.01×3，解之得：n（CuO）=x-0.005mol，n（Cu2O）=0.015mol-x，所以Cu2O、CuO的物质的量共为x-0.005mol+0.015mol-x=0.01mol，故B错误；
C．由Cu元素守恒可得：2×n（Cu2O）+n（CuO）+0.01mol=0.025mol，由氧化还原反应得失电子守恒可知：0.01×2+2×n（Cu2O）=0.01mol×3，解之得：n（Cu2O）=0.005mol，n（CuO）=0.005mol，故C正确；
D．由B可知n（CuO）=x-0.005mol，n（Cu2O）=0.015mol-x，表达式有意义，且各物质都含有，所以0.005mol＜x＜0.015mol，故D正确，
故选B．
绛旓細n锛CuO锛=0.0025-0.01-0.005脳2=0.005mol 锛4锛 鏍规嵁锛3锛夎В娉曞彲寰梟锛Cu2O锛=0.015-Xmol n锛圕uO锛=X-0.005mol.鏍规嵁鐢靛瓙瀹堟亽杩涜鏋佺鍋囪锛氳嫢鐢靛瓙鍏ㄧ敱Cu鎻愪緵鍒檔锛圕u锛=0.015mol锛涜嫢鐢靛瓙鍏ㄧ敱Cu2O鎻愪緵鍒檔锛圕u2O锛=0.015mol,鍒檔锛圕u2+锛==0.03mol澶т簬浜0.025mol,璇存槑n锛圕u锛変笉绛...
绛旓細纭濋吀鍏锋湁寮烘哀鍖栨э紝纭濋吀涓嶤u銆Cu2O鍜孋uO缁勬垚鐨娣峰悎鐗╂伆濂藉弽搴旓紝鐢熸垚Cu锛圢O3锛2涓嶯O锛屾爣鍑嗙姸鍐典笅224mLNO姘斾綋鐨勭墿璐ㄧ殑閲忎负锛0.224L22.4L/mol=0.01mol锛孉锛庢牴鎹甆鍏冪礌瀹堟亽2n[Cu锛圢O3锛2]+n锛圢O锛=n锛圚NO3锛夛紝鍙煡n[Cu锛圢O3锛2]=12[n锛圚NO3锛-n锛圢O锛塢=12脳锛0.1L脳0.6mol/L-0.01mol...
绛旓細0.01mol2=0.025mol锛屾贩鍚堢墿涓櫧鍚湁Cu銆Cu2O鍜孋uO涓夌鐗╄川锛屼絾鍙傚姞姘у寲杩樺師鍙嶅簲鐨勫彧鏈 Cu銆丆u2O锛屾墍浠ュ埄鐢ㄧ數瀛愬畧鎭掑彲鐩存帴姹傝В锛庤浆绉荤數瀛愮殑鐗╄川鐨勯噺锛歯锛坋锛=n锛圢O锛壝3=0.03mol锛孋u鎻愪緵鐢靛瓙鐨勭墿璐ㄧ殑閲忥細0.01脳2=0.02mol锛孋u2O鎻愪緵鐢靛瓙鐨勭墿璐ㄧ殑閲忥細0.03-0.02=0.01mol n锛圕u2O锛=0.01...
绛旓細鏁呯瓟妗堜负锛3Cu2O+14H++2NO3-鈺6Cu2++2NO鈫+7H2O锛涳紙2锛Cu銆丆u2O銆CuO涓嶩NO3鎭板ソ瀹屽叏鍙嶅簲鏃剁敓鎴怌u锛圢O3锛2銆丯O鍜孒2O锛岀閰哥殑鐗╄川鐨勯噺1L脳0.6mol/L=0.6mol锛
绛旓細(3)寰楀け鐢靛瓙瀹堟亽娉鍜孋u瀹堟亽銆侶NO3鍙樻垚NO锛屽緱鍒0.3mol鐢靛瓙銆0.1molCu澶卞幓0.2mol鐢靛瓙銆傛墍浠u2O瑕佸け鍘0.1mol鐢靛瓙锛屽嵆Cu2O鐨鐗╄川鐨勯噺涓0.05mol.鏍规嵁绗簩姝ュ彲鐭ラ亾Cu鐨鎬荤墿璐ㄧ殑閲忎负0.25mol.鎵浠CuO鐨鐗╄川鐨勯噺涓0.25-0.1-(0.05*2)=0.05mol (4)鍋囪娉曪紙姹傚彇鍊艰寖鍥寸殑涓鑸兘鐢ㄥ亣璁炬硶锛屽氨鏄...
绛旓細鎰熻鏉′欢涓嶅 杞Щ鐢靛瓙鎬绘暟锛歯锛坋-锛= n锛圢O锛壝3==0.03mol Cu鎻愪緵鐢靛瓙鏁帮細0.01脳2=0.02mol Cu2O鎻愪緵鐢靛瓙鏁帮細0.03-0.02=0.01mol n锛圕u2O锛=0.01/2=0.005mol n锛CuO锛=0.0025-0.01-0.005脳2=0.005mol
绛旓細Cu銆Cu2O鍜孋uO缁勬垚鐨娣峰悎鐗╁拰1 L 0.6 mol/L HNO3婧舵恫鍙嶅簲锛岀敓鎴怘2O锛孋u锛圢O3)2鍜孨O 鍥犱负鏀堕泦鍒2240 mL NO姘斾綋锛堟爣鍑嗙姸鍐碉級锛屽嵆0.1mol锛屾墍浠ュ叾涓璑鍏冪礌鐗╄川鐨勯噺涓0.1mol 鍙堢敱浜庡姞鍏1 L 0.6 mol/L HNO3婧舵恫鎭板ソ浣挎贩鍚堢墿婧惰В锛屾墍浠ュ弽搴擧NO3鐗╄川鐨勯噺涓0.6mol锛屽叾涓璑鍏冪礌鐗╄川鐨勯噺涓0.6mol ...
绛旓細璁Cu,Cu2O,CuO鐨鐗╄川鐨勯噺鍒嗗埆涓簒mol,ymol,zmol銆傚垯鍚湁鐨勯摐鍏冪礌鐨勬荤墿璐ㄧ殑閲忎负锛歺+2y+z mol,鑰屽叾涓摐鍗曡川鐨勭墿璐ㄧ殑閲忎负锛歺+y mol锛屾荤殑姘у厓绱犵殑鐗╄川鐨勯噺涓猴細y+z mol锛孉浠介氬叆瓒抽噺H2,鍥轰綋璐ㄩ噺鍑忓皯6.4g锛屽垯鍏朵腑鍚湁鐨勬哀鍏冪礌鐨勮川閲忎负6.4 g锛屽嵆0.4mol锛屾湁锛歽+z=0.4 鍐嶆牴鎹細3Cu+8...
绛旓細CuO xmol锛Cu2O ymol 64(x+2y)/(80x+144y)=88 姹傦細x:y
绛旓細灏嗘贩鍚堢墿绛夋晥涓Cu鍜孋uO涓ょ鐗╄川锛屽彲浠ョ湅鍒帮紝CuO搴斾负0.4mol锛涜孋u搴斾负0.15-0.45mol涔嬮棿锛汣u鍏冪礌鐨勬婚噺鍦0.55-0.85mol涔嬮棿锛涚閰告伆濂芥憾瑙ｏ紝婧舵恫涓殑NO3-鎬婚噺涓1.1-1.7mol涔嬮棿锛屽姞涓婂弽搴旀帀鐨0.3mol锛屽簲涓1.4-2.0mol涔嬮棿锛涙墍浠NO3鐨勬祿搴︼紝搴斾负9.33mol/L-13.33mol/L涔嬮棿銆傛棰樹笉鏄緢...
